Problem 20
Question
Let \(f(x)=2 x+1\) and \(g(x)=x-3 .\) Find each function and give its domain. $$ g \cdot f $$
Step-by-Step Solution
Verified Answer
The function \( g \cdot f(x) = 2x^2 - 5x - 3 \) has the domain \((-\infty, \infty)\).
1Step 1: Understanding the Functions
We're given two functions, \( f(x) = 2x + 1 \) and \( g(x) = x - 3 \). The task is to find the new function formed by their multiplication, \( g \cdot f \), and to determine its domain.
2Step 2: Performing the Multiplication
To find \( g \cdot f \), multiply the two functions: \((g \cdot f)(x) = g(x) \cdot f(x) = (x - 3)(2x + 1) \). Distribute the terms: \( x(2x + 1) - 3(2x + 1) = 2x^2 + x - 6x - 3 = 2x^2 - 5x - 3 \). Thus, the new function is \( g \cdot f(x) = 2x^2 - 5x - 3 \).
3Step 3: Determining the Domain
The domain of a function \( h(x) \) is the set of all real numbers \( x \) for which \( h(x) \) is defined. Since \( g \cdot f(x) \) is a polynomial, it is defined for all real numbers. Thus, the domain of \( g \cdot f \) is all real numbers, or \( (-\infty, \infty) \).
Key Concepts
Function MultiplicationDomain of a FunctionReal Numbers
Function Multiplication
Function multiplication is an operation that combines two functions to form a new function. This is represented as \( (g \cdot f)(x) \), where each function is evaluated at \( x \) and then multiplied together. When you have two functions, say \( f(x) = 2x + 1 \) and \( g(x) = x - 3 \), you create a new function by multiplying these two expressions together. This involves distributing each term in the first function across each term in the second function.Here's a simple breakdown of the process:
- Start with \( (g \cdot f)(x) = g(x) \cdot f(x) = (x - 3)(2x + 1) \).
- Apply the distributive property: multiply \( x \) by each term in \( 2x + 1 \), and \( -3 \) by each term in \( 2x + 1 \).
- Combine like terms, giving you the expanded form: \( 2x^2 - 5x - 3 \).
Domain of a Function
The domain of a function refers to all the possible input values (or \( x \)-values) for which the function is defined. For polynomial functions, like \( g \cdot f(x) = 2x^2 - 5x - 3 \), the domain includes all real numbers.Here’s why the domain is crucial:
- Understanding the domain helps us know the values for which the function formula can be applied without any mathematical error, such as division by zero or taking the square root of negative numbers.
- For polynomial functions, the terms don’t include any division by variable expressions or other operations that might limit inputs.
Real Numbers
Real numbers form the set of numbers that include all the rationals (fractions) and irrationals (like \( \pi \) and \( \sqrt{2} \)). They are denoted as \( (-\infty, \infty) \), representing every point on the number line. Understanding real numbers is essential when discussing the domain of functions, especially polynomial functions, which are defined for all real numbers. When we talk about real numbers, we refer to:
- Whole numbers like 1, 2, 3, etc., including negatives and zero.
- Fractions and decimals, such as 1/2 or 0.75.
- Irrational numbers, which can't be expressed as exact fractions, like \( \sqrt{2} \) or \( \pi \).
Other exercises in this chapter
Problem 19
Evaluate expression. \(\log _{6} 1\)
View solution Problem 20
Complete each solution. \(\begin{aligned} \text { Solve: } \log _{2}(2 x-3) &=\log _{2}(x+4) \\\ &\square=x+4 \\ x &=\square\end{aligned}\)
View solution Problem 20
Determine whether each function is one-to-one. \(f(x)=|x|\)
View solution Problem 20
For each function, determine its inverse, \(f^{-1}(x)\) a. \(f(x)=10^{x}\) b. \(f(x)=3^{x}\) c. \(f(x)=\log x\) \(f(x)=\log _{2} x\)
View solution