Problem 20
Question
In Exercises \(9-20,\) determine whether each equation defines \(y\) as a function of \(x .\) $$x+y^{3}=27$$
Step-by-Step Solution
Verified Answer
Yes, the equation \(x + y^3 = 27\) does define \(y\) as a function of \(x\).
1Step 1: Rearrange The Equation
Start by rearranging the equation to represent \(y\) as a function of \(x\). This can be done by subtracting \(x\) from both sides of the equation, resulting in \(y^3 = 27 - x\).
2Step 2: Derive Function of y
To derive the function of \(y\), take the cube root of both sides of the equal sign. This will express \(y\) as a function of \(x\), i.e., \(y = \sqrt[3]{27 - x}\).
3Step 3: Verify Whether y Is a Function of x
For \(y\) to be a function of \(x\), for each value of \(x\) there should be exactly one value of \(y\). Since the cube root will always yield a unique result for any real number, the given equation does indeed define \(y\) as a function of \(x\).
Key Concepts
Determining FunctionsImplicit EquationsCube Root Functions
Determining Functions
In algebra, determining whether an equation defines a function is crucial. A function from a set of inputs (usually called domain) to a set of outputs (usually called range) assigns each input exactly one output.
Here's how you can check if an equation provides a function:
The cube root function directly links each \(x\) value to a singular \(y\) outcome, confirming it as a function.
Here's how you can check if an equation provides a function:
- Start by expressing the equation explicitly, where one variable is solely dependent on another.
- Verify whether each input (or value of \(x\)) corresponds to just one output (or value of \(y\)).
The cube root function directly links each \(x\) value to a singular \(y\) outcome, confirming it as a function.
Implicit Equations
Equations not explicitly solved for one variable are known as implicit equations. Understanding these is important because many real-world relationships are expressed implicitly.
How do you handle implicit equations?
This simplification turns challenging problems into more approachable tasks.
How do you handle implicit equations?
- Reorganize the terms to isolate the desired variable.
- Transform the equation from implicit to explicit where applicable.
This simplification turns challenging problems into more approachable tasks.
Cube Root Functions
Cube root functions are a type of radical function involving the cube root of a variable. Unlike square roots, cube roots are defined for all real numbers. This property plays a key role in algebra and functions.
Key points about cube root functions include:
The cube root's continuous and unambiguous nature guarantees that it behaves reliably across its domain.
Key points about cube root functions include:
- They map negative numbers as well as positives, unlike square roots.
- They offer a one-to-one correspondence between inputs and outputs, making them ideal for defining functions.
The cube root's continuous and unambiguous nature guarantees that it behaves reliably across its domain.
Other exercises in this chapter
Problem 20
Find: a. \((f \circ g)(x)\) b. \(\left(g^{\circ} f\right)(x)\) c. \((f \circ g)(2)\) $$f(x)=5 x+2, g(x)=3 x-4$$
View solution Problem 20
The functions in Exercises \(11-30\) are all one-to-one. For each function: a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equ
View solution Problem 20
Find the midpoint of each line segment with the given endpoints. $$(10,4) \text { and }(2,6)$$
View solution Problem 21
Begin by graphing the square root function, \(f(x)=\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$ h(x)=\sqrt{x+2}-2 $$
View solution