Problem 20
Question
In Exercises 19 - 40, use the Binomial Theorem to expand and simplify the expression. \( \left(x + 1\right)^6 \)
Step-by-Step Solution
Verified Answer
\((x + 1)^6 = x^6 + 6x^5 + 15x^4 + 20x^3 + 15x^2 + 6x + 1\
1Step 1: Understand the Binomial Theorem Form
The Binomial Theorem itself is represented by the formula: \[ (x + y)^n = \sum_{k=0}^{n}\binom{n}{k}x^{n-k}y^{k} \] where \(\binom{n}{k}\) means 'n choose k', also known as the binomial coefficient.
2Step 2: Setting up the Expression
In the expression \((x + 1)^6\), we can see that we have \(x\) and \(1\) acting like \(x\) and \(y\) from the formula, with \(n\) being \(6\). So, we can substitute these into the binomial theorem to start expanding the expression.
3Step 3: Applying the Binomial Theorem
Upon substitution in the formula, we get: \[ (x + 1)^6 = \sum_{k=0}^{6}\binom{6}{k}x^{6-k}1^{k} \] This simplifies to: \[ = \binom{6}{0}x^6 + \binom{6}{1}x^5 + \binom{6}{2}x^4 + \binom{6}{3}x^3 + \binom{6}{4}x^2 + \binom{6}{5}x + \binom{6}{6} \]
4Step 4: Calculating and Rearranging
After calculating the binomial coefficients, we get: \[ = 1x^6 + 6x^5 + 15x^4 + 20x^3 + 15x^2 + 6x + 1 \] And this is the final, expanded form of the expression.
Key Concepts
Understanding Binomial CoefficientsExpansion of Binomials Using the Binomial TheoremPolynomial Expressions ExplainedThe Role of Combinatorics in Binomial Expansions
Understanding Binomial Coefficients
The binomial coefficient is a fundamental component of the Binomial Theorem. You might have seen it symbolized as \( \binom{n}{k} \), which is read as "n choose k." This value represents the number of ways in which \( k \) items can be chosen from \( n \) items without regard to the order of selection.
Here is how it can be calculated:
For example, when expanding \((x+1)^6\), the coefficients such as \( 1, 6, 15, 20, 15, 6, \) and \( 1 \) are calculated through this very principle.
Here is how it can be calculated:
- \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
For example, when expanding \((x+1)^6\), the coefficients such as \( 1, 6, 15, 20, 15, 6, \) and \( 1 \) are calculated through this very principle.
Expansion of Binomials Using the Binomial Theorem
Expanding binomials using the Binomial Theorem is a structured way to break down expressions like \( (x+y)^n \). Instead of multiplying factors over and over, the Binomial Theorem provides a neat formula:
\[(x + y)^n = \sum_{k=0}^{n}\binom{n}{k}x^{n-k}y^{k}\]
Here's how we apply it:
\[(x + y)^n = \sum_{k=0}^{n}\binom{n}{k}x^{n-k}y^{k}\]
Here's how we apply it:
- In \((x+1)^6\), \( x \) and \( 1 \) substitute into the positions of \( x \) and \( y \).
- Identify \( n \) as \( 6 \). Every term becomes a product of a binomial coefficient, a power of \( x \), and a power of \( y \).
Polynomial Expressions Explained
A polynomial expression is a mathematical expression that involves sums and products of variables and coefficients. These terms are composed of variables raised to whole-number exponents.
In the context of our expansion, once we have expanded the binomial \((x+1)^6\), each term produced (such as \( 1x^6, 6x^5, \ldots, 1 \)) is part of a polynomial.
Characteristics of polynomial expressions include:
In the context of our expansion, once we have expanded the binomial \((x+1)^6\), each term produced (such as \( 1x^6, 6x^5, \ldots, 1 \)) is part of a polynomial.
Characteristics of polynomial expressions include:
- Being composed of terms denoted by \( a_nx^n + a_{n-1}x^{n-1} + \ldots + a_0 \).
- Degrees of a polynomial are determined by the highest power of \( x \) present.
The Role of Combinatorics in Binomial Expansions
Combinatorics is a field of mathematics concerned with counting, arrangement, and combination of elements in sets. It's crucial in the calculation of binomial coefficients which make the Binomial Theorem possible.
When using combinatorics for binomial expansion:
When using combinatorics for binomial expansion:
- The coefficient \( \binom{n}{k} \) represents choosing \( k \) successes in \( n \) trials, relating to patterns in scenarios involving probability and decision trees.
- This is why the values \( 1, 6, 15, 20, 15, 6, \) and \( 1 \) arise naturally as combinatorial products.
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