Problem 20
Question
In Exercises \(1-20\), plot the set of parametric equations by hand. Be sure to indicate the orientation imparted on the curve by the parametrization. $$ \left\\{\begin{array}{l} x=\sin (t) \\ y=t \end{array} \text { for }-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}\right. $$
Step-by-Step Solution
Verified Answer
The curve starts at \((-1, -\frac{\pi}{2})\) and ends at \((1, \frac{\pi}{2})\), with an upward orientation.
1Step 1: Understanding Parametric Equations
Parametric equations express a set of related quantities as explicit functions of an independent variable, often denoted as \( t \), which is called the parameter. Here, we are given the parametric equations \( x = \sin(t) \) and \( y = t \) for \(-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}\).
2Step 2: Identify Range of Values
Since \( x = \sin(t) \), the range of \( x \) is determined from the range of the \( t \) values. Given \(-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}\), we know \( \sin(t) \) will range from \(-1\) to \(1\) because the sine function oscillates between these values over one period.
3Step 3: Plot Points for Specific Values of t
Choose values for \( t \) within the given range and calculate corresponding \( x \) using \( x = \sin(t) \). For example, for \( t = -\frac{\pi}{2}, 0, \frac{\pi}{2} \): - For \( t = -\frac{\pi}{2}, x = \sin(-\frac{\pi}{2}) = -1, y = -\frac{\pi}{2} \).- For \( t = 0, x = \sin(0) = 0, y = 0 \).- For \( t = \frac{\pi}{2}, x = \sin(\frac{\pi}{2}) = 1, y = \frac{\pi}{2} \).Plot these points on the coordinate plane.
4Step 4: Determine Curve's Shape and Orientation
The curve is a sine curve that extends vertically, shown by varying \( y = t \) while \( x = \sin(t) \). The points provided and continuity of sine give the orientation from bottom to top (as \( t \) increases from \(-\frac{\pi}{2} \) to \( \frac{\pi}{2} \)).
5Step 5: Sketch the Curve
Draw a smooth curve passing through the plotted points. The curve starts from \((-1, -\frac{\pi}{2})\) and ends at \((1, \frac{\pi}{2})\). Arrowheads on the curve should indicate the increasing direction of \(t\), which is upwards.
Key Concepts
Sine FunctionCoordinate PlanePlotting PointsGraph Orientation
Sine Function
The sine function is one of the fundamental functions in trigonometry. It relates the angle in a right triangle to the ratio of the length of the opposite side over the hypotenuse. In the context of parametric equations, we use sine to represent oscillations and periodic behavior.
When you input a variable, such as an angle or a parameter like \( t \), into the sine function, you get a value between
These values, when paired with corresponding \( y = t \) outputs, provide specific points we can plot on a coordinate plane. Remember that the essence of the sine function is its periodic nature and predictable pattern, which makes it a favorite for generating waves and cycles in mathematics and physics.
When you input a variable, such as an angle or a parameter like \( t \), into the sine function, you get a value between
- -1
- and 1.
These values, when paired with corresponding \( y = t \) outputs, provide specific points we can plot on a coordinate plane. Remember that the essence of the sine function is its periodic nature and predictable pattern, which makes it a favorite for generating waves and cycles in mathematics and physics.
Coordinate Plane
The coordinate plane is a two-dimensional surface where we can plot points and graph equations. It consists of two perpendicular axes:
In parametric equations like the one in our exercise, the coordinate plane allows us to visualize relations between \( x \) and \( y \). By assigning values to a parameter \( t \), we place corresponding points onto this plane. It’s the tool that transforms our abstract equations into visual representations.
To effectively use the coordinate plane, make sure you understand the scales and increments on your axes. Being able to visualize where your curve should lie based on calculated points is essential for accurate plotting.
- The horizontal axis, usually called the \( x \)-axis.
- The vertical axis, known as the \( y \)-axis.
In parametric equations like the one in our exercise, the coordinate plane allows us to visualize relations between \( x \) and \( y \). By assigning values to a parameter \( t \), we place corresponding points onto this plane. It’s the tool that transforms our abstract equations into visual representations.
To effectively use the coordinate plane, make sure you understand the scales and increments on your axes. Being able to visualize where your curve should lie based on calculated points is essential for accurate plotting.
Plotting Points
Plotting points is the process of placing them onto the coordinate plane based on their \( (x, y) \) values. When dealing with parametric equations, this means selecting specific values of the parameter \( t \) to find corresponding \( x \) and \( y \) values.
Start with a range of values that makes sense for your problem, here from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). Calculate the \( x \) and \( y \) for each chosen \( t \), then mark these points on the coordinate plane.
Once you've plotted enough points, connect them with a smooth curve to represent the overall shape. The precision of your curve depends on how many points you use. More points often mean a more accurate depiction of the function you are graphing.
Start with a range of values that makes sense for your problem, here from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). Calculate the \( x \) and \( y \) for each chosen \( t \), then mark these points on the coordinate plane.
- For example, at \( t = 0 \), \( x = \sin(0) = 0 \) and \( y = 0 \).
- These values translate directly to the point (0, 0).
Once you've plotted enough points, connect them with a smooth curve to represent the overall shape. The precision of your curve depends on how many points you use. More points often mean a more accurate depiction of the function you are graphing.
Graph Orientation
Graph orientation refers to the direction and order in which points are plotted along the curve. With parametric equations, this is determined by how \( t \) progresses over its interval.
In our exercise, as \( t \) moves from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\), we notice the curve moves from bottom to top. This is showcased by the increasing values of \( y \) corresponding to \( t \) while \( x \) oscillates within its range.
It’s important to show orientation on your graph. As you connect plotted points, you should add arrowheads indicating this direction of movement. This makes understanding easier, showing how the curve flows naturally as \( t \) increases.
In our exercise, as \( t \) moves from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\), we notice the curve moves from bottom to top. This is showcased by the increasing values of \( y \) corresponding to \( t \) while \( x \) oscillates within its range.
It’s important to show orientation on your graph. As you connect plotted points, you should add arrowheads indicating this direction of movement. This makes understanding easier, showing how the curve flows naturally as \( t \) increases.
- For example, you might see the arrows moving upwards along the curve from the point \((-1, -\frac{\pi}{2})\) to \((1, \frac{\pi}{2})\).
Other exercises in this chapter
Problem 19
Convert the point from polar coordinates into rectangular coordinates. $$ \left(11,-\frac{7 \pi}{6}\right) $$
View solution Problem 19
Solve for the remaining side(s) and angle(s) if possible. As in the text, \((\alpha, a)\), \((\beta, b)\) and \((\gamma, c)\) are angle-side opposite pairs. $$
View solution Problem 20
In Exercises \(1-20\), use the pair of vectors \(\vec{v}\) and \(\vec{w}\) to find the following quantities. $$ \vec{v}=\left\langle\frac{1}{2},-\frac{\sqrt{3}}
View solution Problem 20
Find the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Give exact values. \(\|\vec{v}\|=4 \sqrt{3} ;\)
View solution