Problem 20
Question
If \(\$ 1\) is invested over a 10-year period, then the balance \(A\), where \(t\) represents the time in years, is given by \(A=1+0.06[t]\) or \(A=[1+(0.055 / 365)]^{[365 r]}\) depending on whether the interest is simple interest at \(6 \%\) or compound interest at \(5 \frac{1}{2} \%\) compounded daily. Use a graphing utility to graph each function in the same viewing window. Which grows at a greater rate?
Step-by-Step Solution
Verified Answer
The graph which ends higher at the end of the 10 year period represents the model that grows at a greater rate. The graph of these functions will definitively answer whether the simple or compound interest represent the higher growth over 10 years.
1Step 1: Setting up the simple interest function
The function to represent the simple interest over time (in years) is \(A=1+0.06t\).
2Step 2: Setting up the compound interest function
The function to represent the compound interest over time (in years) is \(A=[1+(0.055 / 365)]^{[365 t]}\). This function takes into account that the interest is calculated daily.
3Step 3: Graphing the functions
To visualize these functions, use a graphing tool. Simply enter the functions as they are derived and plot them over a 10 year period. In most graphing utilities, this can be done by typing in the function and setting the x-axis (which represents time in this case) to range from 0 to 10.
4Step 4: Analyzing the graphs
Once the functions have been graphed, observe which line is higher at the end of the 10 year period (at \(t=10\)). The line that ends higher indicates the model which results in more growth over the 10 year period.
Key Concepts
Simple Interest FormulaCompound Interest FormulaGraphing Financial FunctionsAnalyzing Interest Rates
Simple Interest Formula
Simple interest is a financial concept where the interest charge is calculated only on the principal amount, or the initial sum of money. The formula used for calculating simple interest is given by:
\( I = P \times r \times t \),
where \( I \) represents the interest earned, \( P \) is the principal amount (the initial sum of money), \( r \) is the annual interest rate in decimal, and \( t \) is the time in years. For instance, if you invest \( 1 \) dollar at a simple interest rate of 6%, the function that represents your balance over time would be \( A=1+0.06t \). Here, each year, the interest is calculated as 6% of the initial \( 1 \) dollar.
\( I = P \times r \times t \),
where \( I \) represents the interest earned, \( P \) is the principal amount (the initial sum of money), \( r \) is the annual interest rate in decimal, and \( t \) is the time in years. For instance, if you invest \( 1 \) dollar at a simple interest rate of 6%, the function that represents your balance over time would be \( A=1+0.06t \). Here, each year, the interest is calculated as 6% of the initial \( 1 \) dollar.
Compound Interest Formula
Unlike simple interest that is only calculated on the principal, compound interest is calculated on the principal amount and the accumulated interest of prior periods. The compound interest formula can look daunting at first, but it simply reflects the process of interest accumulating over time. It is given by:
\( A = P(1 + \frac{r}{n})^{nt} \),
where \( A \) is the amount of money obtained after \( t \) years including interest, \( P \) is the principal amount, \( r \) is the annual interest rate (in decimal form), \( n \) is the number of times that interest is compounded per year, and \( t \) is the time the money is invested or borrowed for, in years. In the given problem, the annual rate is 5.5% or 0.055, and since the interest is compounded daily, \( n = 365 \). Therefore, the function for compound interest becomes \( A=[1+(0.055 / 365)]^{[365t]} \).
\( A = P(1 + \frac{r}{n})^{nt} \),
where \( A \) is the amount of money obtained after \( t \) years including interest, \( P \) is the principal amount, \( r \) is the annual interest rate (in decimal form), \( n \) is the number of times that interest is compounded per year, and \( t \) is the time the money is invested or borrowed for, in years. In the given problem, the annual rate is 5.5% or 0.055, and since the interest is compounded daily, \( n = 365 \). Therefore, the function for compound interest becomes \( A=[1+(0.055 / 365)]^{[365t]} \).
Graphing Financial Functions
Graphing financial functions like those representing simple and compound interest is an effective way to visualize the growth of investments over time. To do this, you can enter the simple and compound interest functions into a graphing calculator or software, setting the horizontal axis to represent time (in years) and the vertical axis to represent the balance.
For our simple interest function \( A=1+0.06t \), we'll see a straight line that steadily slopes upwards. On the other hand, the compound interest graph \( A=[1+(0.055 / 365)]^{[365t]} \) will curve upwards, increasing faster as time goes on. This is because the interest is being calculated on a growing balance due to compounding. It's important to have both functions in the same viewing window to properly compare their growth over the same period.
For our simple interest function \( A=1+0.06t \), we'll see a straight line that steadily slopes upwards. On the other hand, the compound interest graph \( A=[1+(0.055 / 365)]^{[365t]} \) will curve upwards, increasing faster as time goes on. This is because the interest is being calculated on a growing balance due to compounding. It's important to have both functions in the same viewing window to properly compare their growth over the same period.
Analyzing Interest Rates
Analyzing interest rates is crucial in understanding how fast your money can grow through different investment options. A higher interest rate does not automatically mean greater returns, especially when comparing simple and compound interests.
Simple interest tends to result in slower growth since it's always calculated on the initial principal. Compound interest, especially when compounded frequently (like daily), can lead to exponential growth. By graphing and comparing, you can analyze which investment grows at a greater rate. Normally, compound interest will outpace simple interest over time, as the effect of compounding becomes increasingly significant. In the exercise, by observing which line (simple or compound interest) is higher at the end of 10 years, you conclude which investment would yield more. This analytical skill can be beneficial for making informed financial decisions in the real world.
Simple interest tends to result in slower growth since it's always calculated on the initial principal. Compound interest, especially when compounded frequently (like daily), can lead to exponential growth. By graphing and comparing, you can analyze which investment grows at a greater rate. Normally, compound interest will outpace simple interest over time, as the effect of compounding becomes increasingly significant. In the exercise, by observing which line (simple or compound interest) is higher at the end of 10 years, you conclude which investment would yield more. This analytical skill can be beneficial for making informed financial decisions in the real world.
Other exercises in this chapter
Problem 20
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