Problem 20
Question
\(g(\theta)=|\sin \theta|, 0<\theta<2 \pi\)
Step-by-Step Solution
Verified Answer
\(g(\theta)\) is the absolute value of \(\sin\theta\), remaining non-negative and oscillates between 0 and 1.
1Step 1: Understand the Function
The function given is \(g(\theta) = |\sin \theta|\). This is the absolute value of the sine function, meaning it will always produce non-negative outcomes.
2Step 2: Determine the Non-negative Output
For any angle \(\theta\), \(\sin \theta\) ranges from -1 to 1. The absolute value \(|\sin \theta|\) will thus have the same magnitude as \(\sin \theta\), but it will always be positive or zero. For example, when \(\sin \theta = -0.5\), \(| \sin \theta | = 0.5\).
3Step 3: Identify Key Points Within the Interval
Given that the interval is \(0 < \theta < 2\pi\), find key points where \(\sin\theta = 0\), \(\sin\theta = 1\), and \(\sin\theta = -1\):- For \(\sin\theta = 0\): \(\theta = 0, \pi, 2\pi\), but exclude 0 and 2\pi as they are not within the interval.- For \(\sin\theta = 1\): \(\theta = \frac{\pi}{2}\).- For \(\sin\theta = -1\): \(\theta = \frac{3\pi}{2}\).
4Step 4: Analyze Behavior in Each Interval Segment
Since \(g(\theta) = |\sin \theta|\), we observe the behavior in each segment:- From \(0\) to \(\frac{\pi}{2}\), \(\sin \theta\) is positive and equals \(|\sin \theta|\).- From \(\frac{\pi}{2}\) to \(\pi\), \(\sin \theta\) is still positive.- From \(\pi\) to \(\frac{3\pi}{2}\), \(\sin \theta\) is negative but becomes positive when taking the absolute value.- From \(\frac{3\pi}{2}\) to \(2\pi\), \(\sin \theta\) is negative, and \(|\sin \theta|\) makes it positive as well.
5Step 5: Sketch the Graph for Better Understanding
Sketching the graph can show that within the interval from \(0\) to \(2\pi\), the \(|\sin\theta|\) resembles the typical sine wave but reflected above the x-axis. The graph consists of arcs that peak at \(1\) and touch the x-axis at \(\theta = \pi\).
6Step 6: Finalize the Behavior Description
The absolute value function \(g(\theta) = |\sin \theta|\) oscillates between \(0\) and \(1\) within the interval \(0 < \theta < 2\pi\). The function reaches \(1\) at \(\theta = \frac{\pi}{2}\) and \(\theta = \frac{3\pi}{2}\), and crosses the x-axis at \(\theta = \pi\).
Key Concepts
absolute valuesine functioninterval analysis
absolute value
The concept of absolute value is quite straightforward yet impactful, especially when applied to functions like the sine function. In mathematics, the absolute value of a number refers to its distance from zero on the number line, regardless of its direction. It is represented using vertical bars \( |x| \). Hence, for any real number or expression \(x\), \( |x| \) is always non-negative.
- If \(x\) is positive or zero, then \( |x| = x\).
- If \(x\) is negative, \( |x| = -x\), which converts \(x\) to a positive value.
sine function
The sine function is one of the fundamental trigonometric functions, primarily used to relate the angle of a right-angled triangle to the ratios of its sides. In a circle described in radians, it helps define the vertical position of a point on the circumference. The sine of an angle \(\theta\), written as \(\sin \theta\), results in values between \(-1\) and \(1\).
- For angles where \(\theta\) is \(0\) or integral multiples of \(\pi\), \(\sin \theta\) equals \(0\).
- When \(\theta\) is \(\frac{\pi}{2}\), \(\sin \theta\) achieves a maximum value of \(1\), representing the peak of its wave.
- Conversely, \(\sin\theta\) reaches a minimum value of \(-1\) at \(\theta = \frac{3\pi}{2}\).
interval analysis
Interval analysis is an essential tool in understanding the behavior and characteristics of functions over specific ranges. In this exercise, we focus on the interval \(0 < \theta < 2\pi\) for the function \(g(\theta) = |\sin \theta|\). By analyzing how \(\theta\) behaves within this range, we can better understand the patterns in the function's output.
- Within \(0 < \theta < \frac{\pi}{2}\), \(\sin \theta\) steadily increases to its maximum of \(1\).
- From \(\frac{\pi}{2}\) to \(\pi\), it then decreases back to \(0\).
- In the interval \(\pi\) to \(\frac{3\pi}{2}\), \(\sin \theta\) becomes negative, but \(|\sin \theta|\) flips this negativity positive.
- Finally, as \(\theta\) progresses from \(\frac{3\pi}{2}\) to \(2\pi\), \(\sin \theta\) returns to zero.
Other exercises in this chapter
Problem 19
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