Problem 20
Question
Graph \(y=f(x)\) by hand by first plotting points to determine the shape of the graph. $$ f(x)=x^{2}+1 $$
Step-by-Step Solution
Verified Answer
The graph of \(f(x) = x^2 + 1\) is a parabola opening upwards with a vertex at (0, 1).
1Step 1: Choose Values of x
Select a range of x-values to use for plotting the graph. A good range for quadratic functions often spans from -3 to 3 to capture the critical points, turning points, and symmetry characteristic. Let's choose x-values: -3, -2, -1, 0, 1, 2, 3.
2Step 2: Calculate Corresponding y-Values
For each chosen x-value, substitute it into the function to find the corresponding y-value.- For \(x = -3\), \(f(-3) = (-3)^2 + 1 = 9 + 1 = 10\).- For \(x = -2\), \(f(-2) = (-2)^2 + 1 = 4 + 1 = 5\).- For \(x = -1\), \(f(-1) = (-1)^2 + 1 = 1 + 1 = 2\).- For \(x = 0\), \(f(0) = 0^2 + 1 = 0 + 1 = 1\).- For \(x = 1\), \(f(1) = 1^2 + 1 = 1 + 1 = 2\).- For \(x = 2\), \(f(2) = 2^2 + 1 = 4 + 1 = 5\).- For \(x = 3\), \(f(3) = 3^2 + 1 = 9 + 1 = 10\).
3Step 3: Plot the Points
Now plot the calculated points (x, y) on a coordinate plane:
- (-3, 10)
- (-2, 5)
- (-1, 2)
- (0, 1)
- (1, 2)
- (2, 5)
- (3, 10)
Make sure the points are accurately placed on the graph based on their coordinates.
4Step 4: Draw the Curve
Connect the plotted points smoothly to form a curve. Since \(y = x^2 + 1\) is a quadratic function, the graph will be a parabola opening upwards. Ensure the curve passes through each plotted point and maintains symmetry about the y-axis.
5Step 5: Verify the Graph's Symmetry and Shape
Check that the graph has the expected shape of a parabola opening upwards with a vertex at the point (0, 1). Verify that the graph is symmetric around the y-axis and that points mirror each other across the axis.
Key Concepts
Plotting PointsSymmetry in FunctionsParabolas
Plotting Points
One fundamental step in graphing quadratic functions is plotting points. This involves selecting specific x-values and determining their corresponding y-values based on the given function.
Doing this helps us shape the graph accurately. Typically, choosing a symmetric range around zero, like from -3 to 3, can be very effective. This ensures we can see any turning points or critical features of the quadratic function.
The function given, \(f(x) = x^2 + 1\), can be evaluated by substituting the x-values to find the y-values. For instance, substituting
Doing this helps us shape the graph accurately. Typically, choosing a symmetric range around zero, like from -3 to 3, can be very effective. This ensures we can see any turning points or critical features of the quadratic function.
The function given, \(f(x) = x^2 + 1\), can be evaluated by substituting the x-values to find the y-values. For instance, substituting
- \(x = -3\) gives \(f(-3) = 10\).
- For \( x = -2\), \(f(-2) = 5\).
- Similarly, for \(x = 0\), \(f(0) = 1\), which is a critical point as it's the vertex of the parabola.
Symmetry in Functions
Symmetry plays a crucial role in understanding the behavior of quadratic functions. Quadratics inherently exhibit symmetry, particularly around their vertex. In the function \(f(x) = x^2 + 1\), symmetry is apparent due to the constant term and the parabolic nature.
A parabola's symmetry means if you were to fold the graph along a vertical line—a vertical line through the vertex (y-axis for this function) would mean the left side mirrors the right side. This is why when plotting points, the y-values will repeat in a mirrored fashion:
A parabola's symmetry means if you were to fold the graph along a vertical line—a vertical line through the vertex (y-axis for this function) would mean the left side mirrors the right side. This is why when plotting points, the y-values will repeat in a mirrored fashion:
- Points like (-2, 5) and (2, 5) reflect over the y-axis.
- The graph passes through (0, 1), indicating its vertex and axis of symmetry at \(x=0\).
Parabolas
A parabolic graph is the visual representation of a quadratic function, with a unique "U" shape, either opening upwards or downwards depending on the sign of the quadratic term. In the equation given, \(y = x^2 + 1\), the positive coefficient of \(x^2\) indicates the parabola opens upwards.
Key characteristics of parabolas include:
Drawing a smooth curve through these points while respecting their symmetry ensures you accurately capture the essence of the parabola's shape.
Key characteristics of parabolas include:
- The **vertex**, which is the highest or lowest point, serving as the turning point of the function.
- The **axis of symmetry**, a vertical line passing through the vertex, dividing the parabola perfectly in half.
- **Openness**, determined by the sign of the \(x^2\) term; positive coefficient means open upwards.
Drawing a smooth curve through these points while respecting their symmetry ensures you accurately capture the essence of the parabola's shape.
Other exercises in this chapter
Problem 20
If possible, find the slope of the line passing through each pair of points. $$ (17,7),(19,7) $$
View solution Problem 20
Evaluate by hand. $$ (4-5)^{2}-3^{2}-3 \sqrt{9} $$
View solution Problem 21
Find the exact distance between the two points. Where appropriate, also give approximate results to the nearest hundredth. $$ \left(\frac{1}{2},-\frac{1}{2}\rig
View solution Problem 21
If possible, find the slope of the line passing through each pair of points. $$ \left(\frac{1}{3},-\frac{3}{5}\right),\left(-\frac{5}{6}, \frac{7}{10}\right) $$
View solution