Problem 20
Question
Graph each inequality. $$y \leq x^{2}-4$$
Step-by-Step Solution
Verified Answer
Shade below \( y = x^2 - 4 \) and include the parabola.
1Step 1: Understand the Inequality
The inequality given is \( y \leq x^2 - 4 \). This signifies all the points \((x, y)\) that are below or on the parabola \( y = x^2 - 4 \). The parabola is a basic quadratic equation, with vertex at (0, -4) and opens upwards.
2Step 2: Sketch the Parabola
First, we graph the equation \( y = x^2 - 4 \). This is the boundary of the inequality. Since the inequality symbol is \( \leq \), the parabola itself is part of the solution set. Plot points to draw a smooth curve: (0, -4) is the vertex; plot points like (-2, 0), (2, 0), (-1, -3), and (1, -3) to help with sketching the curve.
3Step 3: Determine Shading for Inequality
Since we have \( y \leq x^2 - 4 \), shade the area below the parabola. This includes the space beneath the curve and the curve itself because of the \( \leq \) sign, indicating that points on the parabola satisfy the inequality.
4Step 4: Draw the Final Graph
On your graph, draw the parabola as a solid line to indicate that points on the line are included in the solution. Then shade the entire region below this parabola. Check sample points like (0, 0) to confirm they satisfy the inequality since 0 is less than -4.
Key Concepts
Quadratic EquationsParabolasInequality Solutions
Quadratic Equations
A quadratic equation is an equation of the form \(y = ax^2 + bx + c\). In our exercise, the equation given is \(y = x^2 - 4\), which is a simple form where \(a = 1\), \(b = 0\), and \(c = -4\). This means our equation is a basic parabolic form without any linear or constant term affecting the slope or position along the y-axis.
Key characteristics of quadratic equations:
Key characteristics of quadratic equations:
- **Parabola Shape:** The graph is a U-shaped curve called a parabola.
- **Vertex:** The point where the curve changes direction, here it's (0, -4).
- **Symmetry:** It is symmetric about the vertical line passing through the vertex.
Parabolas
Parabolas are special curves that can appear in the graphs of quadratic equations. For \(y = x^2 - 4\), the shape of the equation is a parabola. Here's what you need to know:
- **Standard Form:** A standard parabola looks like \(y = ax^2\). Ours deviates by having a vertical shift down by 4.
- **Direction:** The direction in which a parabola opens is controlled by the coefficient of \(x^2\). A positive coefficient, like 1 in \(x^2\), makes it open upwards.
- **Vertex:** The vertex in this case is at the lowest point (0, -4), meaning it sets the minimum y-value.
- **Axis of Symmetry:** This parabola is symmetric about the y-axis because \(b = 0\) in \(ax^2 + bx + c\).
Inequality Solutions
Inequality solutions in graphs tell us where one set of coordinates lies in relation to another. In this exercise, the inequality \(y \leq x^2 - 4\) indicates solution coordinates found on or beneath the parabola. Here's how to tackle such inequalities:
- **Boundary Curve:** First, identify the curve that forms the boundary, which is \(y = x^2 - 4\).
- **Inclusion of the Curve:** The \(\leq\) sign shows that this boundary is included. Thus, the graph of the parabola is drawn as a solid line.
- **Shaded Region:** Since the inequality states \(y \leq x^2 - 4\), the shaded region will be under the parabola. All points in this region satisfy the inequality.
- **Verification:** Test points, like (0,0), to ascertain they fit the inequality. For this one, \(0 \leq (0)^2 - 4\) confirms the shading direction.
Other exercises in this chapter
Problem 19
Solve each system by substitution. $$\begin{array}{c}2 x-7 y=8 \\\\-3 x+\frac{21}{2} y=5\end{array}$$
View solution Problem 20
Find each determinant. $$\operatorname{det}\left[\begin{array}{rrr}2 & 3 & 0 \\\1 & 9 & 0 \\\\-1 & -2 & 0\end{array}\right]$$
View solution Problem 20
Find the partial fraction decomposition for each rational expression. $$\frac{3}{x^{2}+4 x+3}$$
View solution Problem 20
For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{rrr} -2 & 1 & 0 \\ 1 & 0 & 1 \\ -1 & 1 & 0 \end{array}\right]$$
View solution