Problem 20
Question
Four identical charges \((+2.0 \mu C\) each \()\) are brought from infinity and fixed to a straight line. The charges are located \(0.40 \mathrm{~m}\) apart. Determine the electric potential energy of this group.
Step-by-Step Solution
Verified Answer
389.57 J
1Step 1: Understand the Configuration
There are four identical charges, each with a charge of +2.0 μC, placed at equal distances of 0.40 meters along a straight line. We need to calculate the total electric potential energy of this system of charges.
2Step 2: Formula for Electric Potential Energy between Two Charges
The electric potential energy between two charges \( q_1 \) and \( q_2 \), separated by a distance \( r \), is given by the formula: \[ U = \frac{k \cdot q_1 \cdot q_2}{r} \]where \( k \) is Coulomb's constant, \( k = 8.99 \times 10^9 \text{ N m}^2/\text{C}^2 \).
3Step 3: Calculate Potential Energy for Each Pair
Since potential energy is additive, calculate the potential energy for each unique pair of charges:1. Charges 1 & 2, 1 & 3, 1 & 4, 2 & 3, 2 & 4, and 3 & 4.2. Distances are: 0.40 m (1 & 2), 0.80 m (1 & 3), 1.20 m (1 & 4), 0.40 m (2 & 3), 0.80 m (2 & 4), and 0.40 m (3 & 4).Calculate each separately:- For Charges 1 & 2 or 2 & 3 or 3 & 4 (distance = 0.40 m), \[ U = \frac{(8.99 \times 10^9) \cdot (2.0 \times 10^{-6}) \cdot (2.0 \times 10^{-6})}{0.40} \]- For Charges 1 & 3 or 2 & 4 (distance = 0.80 m),\[ U = \frac{(8.99 \times 10^9) \cdot (2.0 \times 10^{-6}) \cdot (2.0 \times 10^{-6})}{0.80} \]- For Charges 1 & 4 (distance = 1.20 m),\[ U = \frac{(8.99 \times 10^9) \cdot (2.0 \times 10^{-6}) \cdot (2.0 \times 10^{-6})}{1.20} \]
4Step 4: Calculate Individual Potential Energies
Calculate each potential energy using the distances:- For distance 0.40 m, potential energy for each pair is:\[ U = \frac{(8.99 \times 10^9) \cdot 4.0 \times 10^{-12}}{0.40} = 89.9 \text{ J} \]- For distance 0.80 m, potential energy is:\[ U = \frac{(8.99 \times 10^9) \cdot 4.0 \times 10^{-12}}{0.80} = 44.95 \text{ J} \]- For distance 1.20 m, potential energy is:\[ U = \frac{(8.99 \times 10^9) \cdot 4.0 \times 10^{-12}}{1.20} = 29.97 \text{ J} \]
5Step 5: Sum All Potential Energies
Add the potential energies of all unique pairs:\[ U_{total} = 3(89.9) + 2(44.95) + 29.97 = 269.7 + 89.9 + 29.97 = 389.57 \text{ J} \]
6Step 6: Conclusion: Electric Potential Energy Total
The total electric potential energy of the group of charges is 389.57 J.
Key Concepts
Coulomb's LawElectric ChargesSuperposition Principle
Coulomb's Law
Coulomb's Law is a fundamental principle used to understand electric forces between charges. It states that the electric force \( F \) between two point charges \( q_1 \) and \( q_2 \) is directly proportional to the product of their charges and inversely proportional to the square of the distance \( r \) that separates them. The equation for the electric force can be expressed as follows:\[ F = \frac{k \cdot q_1 \cdot q_2}{r^2} \]Here, \( k \) represents Coulomb's constant, with a value of approximately \( 8.99 \times 10^9 \) N m²/C².
- It helps to predict how strongly two charges will interact.
- It is essential for calculating electric potential energy, which is the energy due to the position of charges in an electric field.
Electric Charges
Electric charges are the building blocks of electricity. There are two types of charges: positive and negative. Like charges repel each other, while opposite charges attract. This basic property explains behaviors and phenomena related to electricity and electrostatics.
- Positive charge: Found in protons.
- Negative charge: Found in electrons.
- Neutral atoms have equal amounts of positive and negative charges.
Superposition Principle
In electrostatics, the superposition principle allows us to calculate the total electric potential energy or electric field generated by multiple charges. According to this principle, the net effect (force, field, or potential energy) at a point in space due to multiple charges is the algebraic sum of the effects produced by each individual charge.
- Simplifies calculations with multiple charges.
- Aids in determining the total force or potential energy in a system of charges.
Other exercises in this chapter
Problem 19
A charge of \(-3.00 \mu \mathrm{C}\) is fixed in place. From a horizontal distance of \(0.0450 \mathrm{~m}, \mathrm{a}\) particle of mass \(7.20 \times 10^{-3}
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Four identical charges \((+2.0 \mu \mathrm{C}\) each \()\) are brought from infinity and fixed to a straight line. The charges are located \(0.40 \mathrm{~m}\)
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