Problem 20
Question
For \(|x| \leq 0.1,\) graph the error $$E_{0}=\cos x-P_{0}(x)=\cos x-1$$ Explain the shape of the graph, using the Taylor expansion of \(\cos x .\) Find a bound for \(\left|E_{0}\right|\) for \(|x| \leq 0.1\).
Step-by-Step Solution
Verified Answer
The maximum error \(|E_0|\) is approximately 0.005 for \(|x| \leq 0.1\).
1Step 1: Understanding the Function and Polynomial
The function is given as \( \cos x \) and the polynomial \( P_0(x) \) based on the Taylor expansion of \( \cos x \) at \( x = 0 \). The polynomial \( P_0(x) = 1 \) is the first-term of the Taylor series.
2Step 2: Writing the Error Function
The error function is \( E_0 = \cos x - P_0(x) = \cos x - 1 \). We need to analyze this function within the interval \( |x| \leq 0.1 \).
3Step 3: Calculate the Taylor Expansion of \( \cos x \)
The Taylor series of \( \cos x \) around \( x = 0 \) is \( \cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24} - \cdots \). This expansion helps in understanding the behavior of \( E_0 \).
4Step 4: Determine the Error Using the Taylor Series
By substituting \( x = 0 \), which gives \( E_0 = \cos(0) - 1 = 0 \). As \( x \) increases within the interval, \( E_0 = \cos x - 1 \) can be approximated as \( -\frac{x^2}{2} \) since higher-order terms have lesser influence near zero.
5Step 5: Graphing the Error Function
The graph of \( E_0 = \cos x - 1 \) will be a downward-opening parabola within the interval because \( \cos x \) is approximated by a parabola near zero, and it's negative because \( \cos x < 1 \).
6Step 6: Determining the Bound of the Error
For \( |x| \leq 0.1 \), the error can be approximated as \( E_0 \approx -\frac{x^2}{2} \). The maximum value \( E_0 \) can achieve is at \( x = \pm 0.1 \), therefore, \( |E_0| \leq \frac{(0.1)^2}{2} = 0.005 \).
Key Concepts
Error FunctionCosine FunctionPolynomial Approximation
Error Function
In the realm of mathematics, an error function is pivotal when evaluating the difference between a true function and its approximation. In our exercise, the error function is denoted as \( E_0 = \cos x - 1 \). This calculation specifically examines how well the simplest Taylor polynomial approximates the cosine function. The simplest polynomial in this scenario is a constant value of 1, which directly comes from the Taylor expansion of \( \cos x \) at \( x = 0 \).Understanding the error function involves mapping its value across an interval. Here, we are considering \( |x| \leq 0.1 \). Due to the approximation \( \cos x \approx 1 - \frac{x^2}{2} \), the error function simplifies to \( E_0 \approx -\frac{x^2}{2} \). This tells us that near zero, the approximation error forms a downward-opening parabola. The error function indicates the deviation of \( \cos x \) from its polynomial approximation, thus providing insight into accuracy.
Cosine Function
The cosine function, \( \cos x \), is one of the fundamental trigonometric functions. It is periodic with a period of \( 2\pi \) and is essential in various fields including geometry, physics, and engineering. In our context, we focus on its approximation near \( x = 0 \) using a Taylor series expansion.For small values of \( x \), the Taylor series expansion of the cosine function is very useful. It is given by:\[ \cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24} - \cdots \]This expansion shows that the cosine function is symmetric and can be approximated to a polynomial for small intervals around zero. This makes the cosine function an excellent candidate for simplification in calculations by providing a polynomial approximation, especially useful where high precision is not mandatory, or computational efficiency is more critical.The first term, \(1\), is why for very small \( x \), \( \cos x \) is close to 1. The accuracy of the approximation increases as more terms are included, but just the first term gives a quick and reasonably accurate estimation in a small vicinity around zero.
Polynomial Approximation
Polynomial approximation is a method in mathematics that aims to approximate complex functions using polynomials. This is incredibly advantageous because polynomials are simpler to evaluate, analyze, and differentiate. In our situation with \( \cos x \), the polynomial approximation begins with its Taylor series expansion where higher-order terms diminish as \( x \to 0 \).Key benefits of polynomial approximation include:
- Simplicity: Polynomials are made of basic operations: addition, subtraction, and multiplication.
- Computational Efficiency: Easier to compute compared to more complex functions.
- Analytical Convenience: Differentiating or integrating polynomials is straightforward.
Other exercises in this chapter
Problem 19
expand the quantity about 0 in terms of the variable given. Give four nonzero terms. $$\frac{a}{\sqrt{a^{2}+x^{2}}} \text { in terms of } \frac{x}{a}, \text { w
View solution Problem 19
Find the second-degree Taylor polynomial for \(f(x)=\) \(4 x^{2}-7 x+2\) about \(x=0 .\) What do you notice?
View solution Problem 20
Find the third-degree Taylor polynomial for \(f(x)=\) $$x^{3}+7 x^{2}-5 x+1\( about \)x=0 .$$ What do you notice?
View solution Problem 20
using known Taylor series, find the first four nonzero terms of the Taylor series about 0 for the function. $$\sqrt{(1+t)} \sin t$$
View solution