Problem 20
Question
For the following exercises, solve the inequality involving absolute value. Write your final answer in interval notation. $$ |-2 x+7| \leq 13 $$
Step-by-Step Solution
Verified Answer
\([-3, 10]\)
1Step 1: Understanding the Inequality
We start with the inequality \(|-2x+7| \leq 13\). An absolute value inequality \(|A| \leq B\) implies that \(-B \leq A \leq B\). In this case, \(A\) is \(-2x+7\) and \(B\) is 13.
2Step 2: Setup the Compound Inequality
Based on the previous step, rewrite the inequality without the absolute value as a compound inequality: \[-13 \leq -2x + 7 \leq 13\]
3Step 3: Solve the First Inequality
Start with the inequality \(-13 \leq -2x + 7\). Subtract 7 from both sides to isolate the term with \(x\): \[-13 - 7 \leq -2x\] \[-20 \leq -2x\] Now divide both sides by -2, remembering to reverse the inequality sign: \[x \leq 10\]
4Step 4: Solve the Second Inequality
Now solve \(-2x + 7 \leq 13\). Subtract 7 from both sides: \[-2x \leq 6\]Then, divide by -2 and reverse the inequality sign: \[x \geq -3\]
5Step 5: Combine the Solutions
We now combine the solutions from the two inequalities: \[-3 \leq x \leq 10\]This can be written in interval notation as \([-3, 10]\).
Key Concepts
Compound InequalityInterval NotationSolving Inequalities
Compound Inequality
A compound inequality is a statement that involves two inequalities combined by the word "and" or "or." In the case of absolute value inequalities, we often end up with a compound inequality. This happens because the absolute value of an expression is essentially the distance from zero, and it can be positive or negative.
For example, considering the inequality \(|-2x + 7| \leq 13\), we can split this into two parts:
Understanding how to break down and solve a compound inequality is key, as it provides us with a range where the solutions lie.
For example, considering the inequality \(|-2x + 7| \leq 13\), we can split this into two parts:
- The left part: \(-13 \leq -2x + 7\)
- The right part: \(-2x + 7 \leq 13\)
Understanding how to break down and solve a compound inequality is key, as it provides us with a range where the solutions lie.
Interval Notation
Interval notation is a mathematical method of writing down a set of numbers that includes all the values within a certain range. It includes two numbers, which are called endpoints, and defines when these endpoints are part of the solution.
There are two types of brackets used in interval notation:
This concise form makes it easy to grasp the range of possible values \(x\) can take.
There are two types of brackets used in interval notation:
- Square brackets [ ]: These indicate that the endpoint is included in the interval (inclusive).
- Parentheses ( ): These indicate that the endpoint is not included (exclusive).
This concise form makes it easy to grasp the range of possible values \(x\) can take.
Solving Inequalities
Solving inequalities involves finding all possible values of the variable that satisfy the inequality. With absolute value inequalities, the process consists of:
- Solving \(-2x + 7 \leq 13\) results in \(x \geq -3\).
Solving inequalities properly ensures that we account for all potential values that \(x\) can take within the given range defined by the original equation. Always remember to handle signs carefully, especially with absolute values, to avoid errors.
- Understanding and rewriting the inequality without absolute values as a compound inequality.
- Solving each part of the compound inequality separately.
- Reversing the inequality sign when multiplying or dividing by a negative number.
- Combining solutions to express a singular range of possible values.
- Solving \(-2x + 7 \leq 13\) results in \(x \geq -3\).
Solving inequalities properly ensures that we account for all potential values that \(x\) can take within the given range defined by the original equation. Always remember to handle signs carefully, especially with absolute values, to avoid errors.
Other exercises in this chapter
Problem 19
For each of the following exercises, find the distance between the two points. Simplify your answers, and write the exact answer in simplest radical form for ir
View solution Problem 19
Solve each rational equation for x. State all x-values that are excluded from the solution set. \(\frac{3 x}{x-1}+2=\frac{3}{x-1}\)
View solution Problem 20
For the following exercises, solve the radical equation. Be sure to check all solutions to eliminate extraneous solutions. $$ \sqrt{3 x-1}-2=0 $$
View solution Problem 20
Solve the inequality involving absolute value. Write your final answer in interval notation. $$ |-2 x+7| \leq 13 $$
View solution