Problem 20
Question
For the following exercises, find the multiplicative inverse of each matrix, if it exists. $$ \left[\begin{array}{ccc} 1 & 0 & 6 \\ -2 & 1 & 7 \\ 3 & 0 & 2 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The matrix has an inverse: \( \begin{bmatrix} -\frac{1}{16} & \frac{14}{16} & \frac{1}{8} \\ -\frac{3}{16} & \frac{1}{4} & -\frac{3}{8} \\ \frac{3}{8} & -\frac{3}{4} & -\frac{1}{16} \end{bmatrix} \).
1Step 1: Check if the matrix is square
The given matrix is \(3 \times 3\), meaning it is a square matrix. Only square matrices can have inverses.
2Step 2: Calculate the determinant of the matrix
For the matrix \( A = \begin{bmatrix} 1 & 0 & 6 \ -2 & 1 & 7 \ 3 & 0 & 2 \end{bmatrix} \), the determinant \( \text{det}(A) \) is calculated as follows: \[ \text{det}(A) = 1(1 \cdot 2 - 7 \cdot 0) - 0(-2 \cdot 2 - 7 \cdot 3) + 6(-2 \cdot 0 - 1 \cdot 3) \] Simplify the expression:\[ \text{det}(A) = 1(2) + 0 + 6(-3) = 2 - 18 = -16 \]
3Step 3: Determine if the inverse exists
Since the determinant \( \text{det}(A) = -16 \) is non-zero, the matrix has an inverse. If the determinant were zero, the matrix would not have an inverse.
4Step 4: Calculate the adjoint matrix
The adjoint of a \(3 \times 3\) matrix \(A\) is the transpose of its cofactor matrix. Calculate each minor, find the cofactors, and then transpose to find the adjoint. The cofactor matrix is:\[\begin{bmatrix}1 & 3 & -6 \-14 & -4 & 12 \-2 & 6 & 1\end{bmatrix}\]Transpose the cofactor matrix to get the adjoint:\[\text{adj}(A) = \begin{bmatrix}1 & -14 & -2 \3 & -4 & 6 \-6 & 12 & 1\end{bmatrix}\]
5Step 5: Compute the inverse of the matrix
The inverse of matrix \( A \) is given by \( A^{-1} = \frac{1}{\text{det}(A)} \text{adj}(A) \). Since \( \text{det}(A) = -16 \), we have:\[ A^{-1} = \frac{1}{-16} \begin{bmatrix} 1 & -14 & -2 \ 3 & -4 & 6 \ -6 & 12 & 1 \end{bmatrix} = \begin{bmatrix} -\frac{1}{16} & \frac{14}{16} & \frac{1}{8} \ -\frac{3}{16} & \frac{1}{4} & -\frac{3}{8} \ \frac{3}{8} & -\frac{3}{4} & -\frac{1}{16} \end{bmatrix} \]
Key Concepts
Square MatrixDeterminant CalculationAdjoint of a MatrixMatrix Cofactors
Square Matrix
When dealing with matrix inversion, the concept of a square matrix is fundamental. A square matrix is simply a matrix that has the same number of rows and columns. This regularity is crucial because only square matrices can potentially have a multiplicative inverse.
- A matrix with dimensions such as 3x3, like the one given in the exercise, is a square matrix.
- Non-square matrices lack this uniformity, preventing any possibility of finding an inverse.
Determinant Calculation
The determinant is a unique number that can be calculated for square matrices. This number is vital for determining whether a matrix has an inverse. The determinant calculation for a 3x3 matrix may seem intricate, but breaking it down makes it feasible.
- For our example, the determinant is calculated using:\[ \text{det}(A) = 1(1 \cdot 2 - 7 \cdot 0) - 0(-2 \cdot 2 - 7 \cdot 3) + 6(-2 \cdot 0 - 1 \cdot 3) \]
- This simplifies to \[ \text{det}(A) = 2 - 18 = -16 \].
Adjoint of a Matrix
The adjoint of a matrix plays a crucial role in finding the inverse of a matrix. It is essentially the transpose of the cofactor matrix. This requires calculation in two steps: finding cofactors and transposing the matrix.
- First, calculate the cofactors for each element of the matrix.
- Next, take the transpose of the cofactor matrix to get the adjoint.
Matrix Cofactors
Understanding matrix cofactors is pivotal when finding the adjoint and subsequently the inverse of a matrix. Cofactors are specific minors of the matrix, essentially determinants of smaller square matrices derived from the larger matrix.
- To find a cofactor for an element, remove its row and column and compute the determinant of the resulting submatrix.
- The cofactor is then adjusted by a positive or negative sign based on its position.
Other exercises in this chapter
Problem 19
For the following exercises, solve each system by Gaussian elimination. $$ \begin{array}{c} 2 x+3 y-6 z=1 \\ -4 x-6 y+12 z=-2 \\ x+2 y+5 z=10 \end{array} $$
View solution Problem 20
For the following exercises, find the determinant. $$ \left|\begin{array}{rrr} 6 & -1 & 2 \\ -4 & -3 & 5 \\ 1 & 9 & -1 \end{array}\right| $$
View solution Problem 20
For the following exercises, solve the system by Gaussian elimination. $$ \left[\begin{array}{rr|r} -2 & 0 & 1 \\ 0 & 2 & -1 \end{array}\right] $$
View solution Problem 20
For the following exercises, use the matrices below to perform matrix multiplication. \(A=\left[\begin{array}{rr}-1 & 5 \\ 3 & 2\end{array}\right], B=\left[\beg
View solution