Problem 20
Question
For Exercises 20 and \(21,\) use the following information. Carlos is walking on a moving walkway. His speed is given by the function \(C(x)=3 x^{2}+3 x-4,\) and the speed of the walkway is \(W(x)=x^{2}-4 x+7\) What is his total speed as he walks along the moving walkway?
Step-by-Step Solution
Verified Answer
The total speed function is \( T(x) = 4x^2 - x + 3 \).
1Step 1: Identify Functions
Carlos's speed is represented by the function \( C(x) = 3x^2 + 3x - 4 \). The speed of the walkway is given by \( W(x) = x^2 - 4x + 7 \). We need to determine the total speed as Carlos walks on the moving walkway.
2Step 2: Add the Speeds
To find the total speed, we add the two functions together: \[ C(x) + W(x) = (3x^2 + 3x - 4) + (x^2 - 4x + 7) \]
3Step 3: Combine Like Terms
Combine the like terms in the expression: - Combine the \( x^2 \) terms: \( 3x^2 + x^2 = 4x^2 \).- Combine the \( x \) terms: \( 3x - 4x = -x \).- Combine the constant terms: \( -4 + 7 = 3 \).
4Step 4: Write the Total Speed Function
The total speed as Carlos walks on the moving walkway is given by the function: \[ T(x) = 4x^2 - x + 3 \]
Key Concepts
Function AdditionPolynomial FunctionsSpeed Calculation
Function Addition
When dealing with algebraic functions, one powerful operation you can perform is **function addition**. This means you're literally adding two functions together to create a new one. In the exercise, Carlos's walking speed and the moving walkway's speed each have their own separate functions. But when you want to find out his overall speed on the walkway, you need to add these functions together.
The functions in this case are:
The functions in this case are:
- Carlos's speed: \( C(x) = 3x^2 + 3x - 4 \)
- Walkway's speed: \( W(x) = x^2 - 4x + 7 \)
- Combine these functions: \( T(x) = C(x) + W(x) \)
- This becomes \( T(x) = (3x^2 + 3x - 4) + (x^2 - 4x + 7) \)
Polynomial Functions
**Polynomial Functions** are mathematical expressions that have variables raised to different powers, and they can include different terms like constants, variables, and coefficients. They are both versatile and common in algebra.
The functions given in the problem are examples of polynomials. Carlos's speed function is a quadratic polynomial:
The functions given in the problem are examples of polynomials. Carlos's speed function is a quadratic polynomial:
- \( C(x) = 3x^2 + 3x - 4 \)
- \( W(x) = x^2 - 4x + 7 \)
Speed Calculation
Calculating speed when dealing with different contributions, such as a person's speed and another moving object's speed, is important and practical. In this exercise, you calculate the total speed by combining the individual speeds.
When Carlos is on the moving walkway, his effective speed is the sum of his speed \( C(x) \) and the walkway's speed \( W(x) \). Calculating it involves:
When Carlos is on the moving walkway, his effective speed is the sum of his speed \( C(x) \) and the walkway's speed \( W(x) \). Calculating it involves:
- Adding the function expressions: \( T(x) = C(x) + W(x) \)
- For example: In \( (3x^2 + 3x - 4) + (x^2 - 4x + 7) \), you combine to get \( 4x^2 - x + 3 \)
Other exercises in this chapter
Problem 20
Graph each function. State the domain and range of each function. \(y=2 \sqrt{3-4 x}+3\)
View solution Problem 20
Find the inverse of each function. Then graph the function and its inverse. $$ f(x)=3 x+3 $$
View solution Problem 21
Solve each equation. $$ \sqrt{b+1}=\sqrt{b+6}-1 $$
View solution Problem 21
Write each radical using rational exponents. $$ \sqrt{23} $$
View solution