Problem 20
Question
Find the quotient in each case by replacing the divisor by its reciprocal and multiplying. $$\frac{28}{125} \div \frac{5}{2}$$
Step-by-Step Solution
Verified Answer
The quotient is \( \frac{56}{625} \).
1Step 1: Identify the Problem
We have the expression \( \frac{28}{125} \div \frac{5}{2} \). To solve this division problem using multiplication, we need to replace the divisor by its reciprocal and then multiply.
2Step 2: Find the Reciprocal of the Divisor
The divisor in this expression is \( \frac{5}{2} \). The reciprocal of \( \frac{5}{2} \) is \( \frac{2}{5} \). The reciprocal is found by swapping the numerator and the denominator.
3Step 3: Replace Division with Multiplication
Rewrite the original problem by replacing the division with multiplication by the reciprocal of the divisor:\[\frac{28}{125} \div \frac{5}{2} = \frac{28}{125} \times \frac{2}{5}.\]
4Step 4: Multiply the Fractions
To multiply two fractions, multiply the numerators together and the denominators together:\[\frac{28 \times 2}{125 \times 5} = \frac{56}{625}.\]
5Step 5: Simplify the Result (If Necessary)
In this case, \( \frac{56}{625} \) is already in its simplest form because 56 and 625 have no common factors other than 1. Thus, the answer remains \( \frac{56}{625} \).
Key Concepts
Reciprocal of a FractionSimplifying FractionsMultiplication of Fractions
Reciprocal of a Fraction
To grasp the concept of dividing fractions, understanding the 'reciprocal' is crucial. A reciprocal is what you get when you swap the numerator and the denominator of a fraction.
For example, if you have the fraction \( \frac{5}{2} \), its reciprocal is \( \frac{2}{5} \). Notice how we just flipped the positions of the two numbers. This switch is fundamental when dealing with division of fractions, as it turns the division problem into a multiplication one.
For example, if you have the fraction \( \frac{5}{2} \), its reciprocal is \( \frac{2}{5} \). Notice how we just flipped the positions of the two numbers. This switch is fundamental when dealing with division of fractions, as it turns the division problem into a multiplication one.
- Find the reciprocal of \( \frac{a}{b} \) by swapping it to \( \frac{b}{a} \).
- This allows you to replace division with multiplication.
Simplifying Fractions
Simplifying fractions means reducing them to their simplest form. This involves changing a fraction like \( \frac{28}{56} \) into a fraction like \( \frac{1}{2} \). The process involves finding the greatest common divisor (GCD) and dividing both the numerator and the denominator by this number.
When you simplify, the fraction remains equal in value even though the numbers in it change. Simplified fractions are easier to understand and often needed for final answers in math problems.
When you simplify, the fraction remains equal in value even though the numbers in it change. Simplified fractions are easier to understand and often needed for final answers in math problems.
- Identify the GCD of the numerator and the denominator.
- Divide both by the GCD to get the simplest form.
Multiplication of Fractions
Multiplying fractions is one of the simplest operations involving fractions, as it only requires multiplying across the numerators and denominators. Given two fractions, \( \frac{a}{b} \) and \( \frac{c}{d} \), multiplying them involves the following steps:
First, multiply the numerators together to get a new numerator: \( a \times c \).
First, multiply the numerators together to get a new numerator: \( a \times c \).
- For \( \frac{28}{125} \times \frac{2}{5} \), calculate \( 28 \times 2 = 56 \).
- Again, for our example, \( 125 \times 5 = 625 \).
Other exercises in this chapter
Problem 20
Add and subtract the following mixed numbers as indicated. \(8 \frac{5}{6}+9 \frac{5}{6}\)
View solution Problem 20
Find the following quotients. $$8 \frac{2}{3} \div 4 \frac{1}{3}$$
View solution Problem 20
Reduce each fraction to lowest terms. $$\frac{4}{10}$$
View solution Problem 20
Indicate whether each of the following is True or False. Some improper fractions are also proper fractions.
View solution