Problem 20
Question
Find the points where the two curves meet. \(r=1+\cos \theta\) and \(r=1-\cos \theta\)
Step-by-Step Solution
Verified Answer
The curves meet at points \((1, \frac{\pi}{2})\) and \((1, \frac{3\pi}{2})\).
1Step 1: Understanding the Problem
We are given two polar coordinate equations: \(r=1+\cos \theta\) and \(r=1-\cos \theta\). Our task is to find the points where these two curves meet, i.e., where they have the same \(r\) value for the same \(\theta\) value.
2Step 2: Setting Equations Equal
To find the points of intersection, set the two equations equal to each other: \(1+\cos \theta = 1-\cos \theta\).
3Step 3: Solving for \(\cos \theta\)
Simplify the equation \(1+\cos \theta = 1-\cos \theta\) by subtracting 1 from both sides: \(\cos \theta = -\cos \theta\).
4Step 4: Isolating \(\cos \theta\)
Add \(\cos \theta\) to both sides to isolate \(\cos \theta\): \(2\cos \theta = 0\).
5Step 5: Finding Angle \(\theta\)
Divide both sides by 2 to solve for \(\cos \theta\): \(\cos \theta = 0\). Since \(\cos \theta = 0\), \(\theta\) can be \(\theta = \frac{\pi}{2}\) or \(\theta = \frac{3\pi}{2}\).
6Step 6: Calculating \(r\) for \(\theta = \frac{\pi}{2}\)
Substitute \(\theta = \frac{\pi}{2}\) into either original equation to find \(r\). Using \(r = 1 + \cos(\theta)\), we get \(r = 1 + \cos(\frac{\pi}{2}) = 1\).
7Step 7: Checking \(r\) for \(\theta = \frac{3\pi}{2}\)
Substitute \(\theta = \frac{3\pi}{2}\) into either original equation to find \(r\). Using \(r = 1 + \cos(\theta)\), we get \(r = 1 + \cos(\frac{3\pi}{2}) = 1\).
8Step 8: Conclusion
Both \(\theta = \frac{\pi}{2}\) and \(\theta = \frac{3\pi}{2}\) yield \(r = 1\). Therefore, the curves intersect at the points \((1, \frac{\pi}{2})\) and \((1, \frac{3\pi}{2})\).
Key Concepts
Polar CoordinatesTrigonometric EquationsProblem-Solving Steps
Polar Coordinates
Polar coordinates provide a powerful way to describe locations in the plane, especially for problems involving circles or angles. Unlike Cartesian coordinates which use \(x\) and \(y\), polar coordinates describe a point with a radius \(r\) and an angle \(\theta\).
- **Radius (r):** This is the distance from the origin to the point. It can be thought of as how far out you go from the center.
- **Angle (\theta):** This is the angle measured from the positive x-axis, usually moving counter-clockwise.
Trigonometric Equations
Solving trigonometric equations often involves manipulating expressions to isolate trigonometric functions such as \(\cos, \sin\), or \(\tan\). In this problem, we solve equations involving \(\cos \theta\). When we set \(r = 1 + \cos \theta\) equal to \(r = 1 - \cos \theta\), we derive \(\cos \theta = -\cos \theta\), a situation calling for clear problem solving.
- This equation simplifies to \(2\cos \theta = 0\) leading directly to \(\cos \theta = 0\).
- The solution for \(\theta\), where \(\cos \theta = 0\), occurs when \(\theta = \frac{\pi}{2}\) or \(\theta = \frac{3\pi}{2}\).
Problem-Solving Steps
Breaking down a mathematical problem into manageable steps is crucial for clarity. For the task of finding where two polar curves intersect, the approach involves equating and solving. Here’s how you can logically follow through:
- **Understand the problem:** Recognize the curves described by their polar equations. We are required to find common points \(\theta\) where both give the same \(r\).
- **Set and simplify equations:** Start by equating the given functions, leading you to solve for specific values of \(\theta\).
- **Solve trigonometric identities:** Solve \(\cos \theta = -\cos \theta\) by isolating terms and using known trigonometric angles.
- **Find corresponding radius values:** Input these angles back into one of the original equations to find \(r\).
Other exercises in this chapter
Problem 19
Find the points where the two curves meet. \(r^{2}=\sin 2 \theta\) and \(r^{2}=\cos 2 \theta\)
View solution Problem 20
Find all solutions of the form \(y=e^{t}\). $$ y^{\prime \prime \prime}+y=0 $$
View solution Problem 21
Find all solutions of the form \(y=e^{t}\). $$ y^{\prime \prime \prime}-y^{\prime}=0 $$
View solution Problem 21
Find the points where the two curves meet. \(r=2\) and \(r=4 \sin 2 \theta\)
View solution