Problem 20
Question
Find the nth term of the arithmetic sequence \(\left\\{a_{n}\right\\}\) whose first term \(a_{1}\) and common difference d are given. What is the 51st term? $$ a_{1}=6 ; \quad d=-2 $$
Step-by-Step Solution
Verified Answer
The 51st term is -94.
1Step 1: Understand the arithmetic sequence formula
The formula to find the nth term of an arithmetic sequence is given by \[ a_n = a_1 + (n - 1)d \] where \( a_n \) is the nth term, \( a_1 \) is the first term, \( d \) is the common difference, and \( n \) is the term number.
2Step 2: Substitute known values
Substitute the given values into the arithmetic sequence formula. We know that \( a_1 = 6 \), \( d = -2 \), and we want to find the 51st term (\( n = 51 \)).Using the formula, we substitute the values: \[ a_{51} = 6 + (51 - 1)(-2) \]
3Step 3: Simplify the expression
First, simplify the term inside the parentheses: \[ a_{51} = 6 + (50)(-2) \].Next, calculate the product:\[ 50 \times -2 = -100 \].
4Step 4: Complete the calculation
Finally, add the results from the previous steps:\[ a_{51} = 6 + (-100) \].Simplify the expression to find the 51st term:\[ a_{51} = 6 - 100 = -94 \].
Key Concepts
nth term formulacommon differencesequence calculation
nth term formula
To find any term in an arithmetic sequence, we use a special formula. This formula helps us locate a specific term without listing all the terms. The formula is: \ \[ a_n = a_1 + (n - 1)d \] \ Here: \
- \( a_n \): the nth term we are looking for
- \( a_1 \): the first term of the sequence
- \( d \): the common difference between the terms
- \( n \): the term number we need
common difference
The common difference in an arithmetic sequence tells us how much each term increases or decreases from the previous one. It is represented by \( d \). \
- If \( d \) is positive, the sequence increases.
- If \( d \) is negative, the sequence decreases.
sequence calculation
Let’s use an example to understand how to calculate a specific term in an arithmetic sequence. We will find the 51st term for the sequence with the first term \( a_1 = 6 \) and the common difference \( d = -2 \). \
- Start with the nth term formula: \ \[ a_n = a_1 + (n - 1)d \]
- Substitute the given values: \ \[ a_{51} = 6 + (51 - 1)(-2) \]
- Simplify inside the parenthesis: \ \[ 51 - 1 = 50 \], so \ \[ a_{51} = 6 + 50(-2) \]
- Calculate the product: \ \[ 50 \times -2 = -100 \], so \ \[ a_{51} = 6 + (-100) \]
- Combine the terms: \ \[ 6 - 100 = -94 \]
Other exercises in this chapter
Problem 20
Find the fifth term and the nth term of the geometric sequence whose first term \(a_{1}\) and common ratio \(r\) are given. $$ a_{1}=-2 ; \quad r=4 $$
View solution Problem 20
List the first five terms of each sequence. \(\left\\{d_{n}\right\\}=\left\\{(-1)^{n-1}\left(\frac{n}{2 n-1}\right)\right\\}\)
View solution Problem 21
Use the Principle of Mathematical Induction to show that the given statement is true for all natural numbers \(n\). $$ n^{2}-n+2 \text { is divisible by } 2 $$
View solution Problem 21
Find the fifth term and the nth term of the geometric sequence whose first term \(a_{1}\) and common ratio \(r\) are given. $$ a_{1}=5 ; \quad r=-1 $$
View solution