Problem 20

Question

Find the indefinite integral and check your result by differentiation. $$ \int v^{-1 / 2} d v $$

Step-by-Step Solution

Verified
Answer
The indefinite integral of \(v^{-1/2}\) is \(2\sqrt{v} + C\).
1Step 1: Apply the Power Rule for Integration
When the power of the variable v is a real number, the power rule for integration can be applied. This integral should be computed as follows: \[\int v^{-1/2} dv = 2\sqrt{v} + C\] where C is the arbitrary constant of integration.
2Step 2: Differentiate the integral
To verify the computed integral, differentiate it which should result in the initial function. The derivative of \(2\sqrt{v}\) using the power rule for differentiation is \(v^{-1/2}\) . This checks out since it is the same as the integrand function.