Problem 20
Question
Find the derivatives of the functions in \(1-26\). $$ \frac{\sin x-\cos x}{\sin x+\cos x} $$
Step-by-Step Solution
Verified Answer
The derivative is \( \frac{2\sin(2x)}{(\sin x + \cos x)^2} \).
1Step 1: Identify the Function
The function given is \( f(x) = \frac{\sin x - \cos x}{\sin x + \cos x} \). Notice that this function is a quotient of two trigonometric expressions.
2Step 2: Recall Derivative of a Quotient Rule
To find the derivative of a quotient \( \frac{u}{v} \), use the formula: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \]. Here, \( u(x) = \sin x - \cos x \) and \( v(x) = \sin x + \cos x \).
3Step 3: Differentiate the Numerator
Differentiate \( u(x) = \sin x - \cos x \). The derivative is \( u'(x) = \cos x + \sin x \), because the derivative of \( \sin x \) is \( \cos x \) and the derivative of \( -\cos x \) is \( \sin x \).
4Step 4: Differentiate the Denominator
Differentiate \( v(x) = \sin x + \cos x \). The derivative is \( v'(x) = \cos x - \sin x \), because the derivative of \( \sin x \) is \( \cos x \) and the derivative of \( \cos x \) is \( -\sin x \).
5Step 5: Apply the Quotient Rule
Substitute \( u(x) \), \( v(x) \), \( u'(x) \), and \( v'(x) \) into the quotient rule formula: \[ f'(x) = \frac{(\cos x + \sin x)(\sin x + \cos x) - (\sin x - \cos x)(\cos x - \sin x)}{(\sin x + \cos x)^2} \].
6Step 6: Simplify the Expression
Compute the expression: First, expand each term in the numerator: \((\cos x + \sin x)(\sin x + \cos x) = \cos^2 x + \cos x \sin x + \sin x \cos x + \sin^2 x = 1 + 2\sin x \cos x = 1 + \sin(2x)\). Similarly, \((\sin x - \cos x)(\cos x - \sin x) = \sin^2 x - \sin x \cos x - \cos x \sin x + \cos^2 x = 1 - \sin(2x)\). Thus, the numerator becomes \(1 + \sin(2x) - (1 - \sin(2x)) = 2\sin(2x)\).
7Step 7: Final Expression
The derivative simplifies to \( f'(x) = \frac{2\sin(2x)}{(\sin x + \cos x)^2} \). This is the simplified expression for the derivative of the function.
Key Concepts
Quotient RuleTrigonometric FunctionsSimplification of Expressions
Quotient Rule
The quotient rule is a fundamental technique in calculus used to find the derivative of a division of two functions with respect to a variable. When you have a function that can be expressed as a quotient, as seen in the form \( f(x) = \frac{u(x)}{v(x)} \), where both \( u(x) \) and \( v(x) \) are differentiable, the derivative \( f'(x) \) can be computed using the quotient rule:
- Identify the numerator \( u(x) \) and the denominator \( v(x) \).
- Calculate the derivative of the numerator: \( u'(x) \).
- Calculate the derivative of the denominator: \( v'(x) \).
- Apply the quotient rule formula: \[ f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2} \].
Trigonometric Functions
Trigonometric functions like \( \sin x \) and \( \cos x \) are periodic functions fundamental in mathematics, especially in calculus. They model cycles, waves, and oscillations, which are prevalent in both pure and applied sciences.
- The basic trigonometric functions are \( \sin x \) and \( \cos x \).
- The derivatives of these functions are critical to remember:
- The derivative of \( \sin x \) is \( \cos x \).
- The derivative of \( \cos x \) is \(-\sin x \).
- These derivatives illustrate how rates of change for these functions relate directly to the other, showing their intrinsic link.
Simplification of Expressions
Simplifying expressions is a crucial step in finding derivatives and understanding calculus comprehensively. This process involves combining like terms, factoring, expanding, and reducing expressions to their simplest form to make them easier to interpret and solve.
- The aim is to identify terms that can be simplified or reduced.
- Look for opportunities to factor or combine terms, such as using angle sum identities in trigonometry.
- Always check for identity relationships or algebraic tricks like \( \sin(2x) = 2\sin x\cos x \).
Other exercises in this chapter
Problem 20
Find the limits if they exist. An \(\varepsilon-\delta\) test is not required. $$ \lim _{x \rightarrow 2} \frac{\sqrt{4-x}}{\sqrt{6+x}} $$
View solution Problem 20
At a point where \(d y / d x=0\), what is special about the graph of \(y(x)\) ? Test case: \(y=x^{2}\).
View solution Problem 20
Choose \(b, c, d\) so that the two parabolas \(y=x^{2}+b x+c\) and \(y=d x-x^{2}\) are tangent to each other at \(x=1, y=0\).
View solution Problem 20
Find the derivative of \(\sin (x+1)\) in two ways: (a) Expand to \(\sin x \cos 1+\cos x \sin 1\). Compute \(d y / d x\). (b) Divide \(\Delta y=\sin (x+1+\Delta
View solution