Problem 20
Question
Find \(f^{\prime}(a),\) where \(a\) is in the domain of \(f .\) $$f(x)=-\frac{1}{x^{2}}$$
Step-by-Step Solution
Verified Answer
\(f'(a) = \frac{2}{a^3}\).
1Step 1: Identify and Understand the Derivative Formula
The derivative of a function \(f(x)\) with respect to \(x\) is found using the formula \(f^{\prime}(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}\). In this case, we need to find \(f^{\prime}(a)\), so we'll first find \(f^{\prime}(x)\).
2Step 2: Rewrite the Function
Given the function \(f(x) = -\frac{1}{x^2}\), it can be rewritten as \(f(x) = -x^{-2}\). This form will be helpful when applying the power rule for derivatives.
3Step 3: Apply the Power Rule
Use the power rule for differentiation, which states that \(\frac{d}{dx}[x^n] = nx^{n-1}\). Applying this to \(-x^{-2}\), we get: \[f'(x) = -(-2)x^{-2-1} = 2x^{-3}\].
4Step 4: Substitute \(a\) into the Derivative
We have found \(f'(x)\), now substitute \(a\) into this expression: \[f'(a) = 2a^{-3}\].
5Step 5: Write the Final Answer
Thus, the derivative of \(f(x) = -\frac{1}{x^2}\) with respect to \(x\), evaluated at \(a\) is: \[f^{\prime}(a) = \frac{2}{a^{3}}\].
Key Concepts
Power RuleFunction DifferentiationLimit Definition of Derivative
Power Rule
The power rule is one of the most fundamental tools in calculus, particularly when working with derivatives. It's a quick method to find the derivative of power functions. If you have a function of the form \( f(x) = x^n \), the derivative \( f'(x) \) is found by multiplying the exponent \( n \) by \( x \) to the power of \( n-1 \). This can be summarized as:
Consider the function in our exercise: \( f(x) = -\frac{1}{x^2} \). By rewriting it as \( f(x) = -x^{-2} \), we can easily apply the power rule. Multiply the exponent, \(-2\), by the starting function \(-x\), and reduce the exponent by one unit:
- \( \frac{d}{dx}[x^n] = nx^{n-1} \)
Consider the function in our exercise: \( f(x) = -\frac{1}{x^2} \). By rewriting it as \( f(x) = -x^{-2} \), we can easily apply the power rule. Multiply the exponent, \(-2\), by the starting function \(-x\), and reduce the exponent by one unit:
- \( f'(x) = -(-2)x^{-3} \)
Function Differentiation
Differentiation is the process of finding a function's derivative, which measures how the function's output changes as the input changes. In simple terms, it tells you how fast the function is changing at any given point.
When differentiating, especially complex expressions, it's helpful to break down the function into simpler parts. For example, write \( f(x) = -\frac{1}{x^2} \) as \( f(x) = -x^{-2} \). Such transformation allows for easier application of differentiation rules like the power rule.
This approach provides clarity and simplicity, enabling you to handle more challenging functions. Awareness of such techniques can greatly enhance your understanding and efficiency in calculus.
When differentiating, especially complex expressions, it's helpful to break down the function into simpler parts. For example, write \( f(x) = -\frac{1}{x^2} \) as \( f(x) = -x^{-2} \). Such transformation allows for easier application of differentiation rules like the power rule.
This approach provides clarity and simplicity, enabling you to handle more challenging functions. Awareness of such techniques can greatly enhance your understanding and efficiency in calculus.
Limit Definition of Derivative
The limit definition of a derivative provides the theoretical underpinning for differentiation. It is defined as:
In practice, while using the limit definition directly can be cumbersome, it ensures the precision and validity of derivative calculations.
In our exercise, identifying that we're essentially looking for an expression \( f^{\prime}(x) \) first, before substituting any value like \( a \), is crucial. It verifies our process, ensuring that the steps prior to applying rules like the power rule adhere to the foundational calculus concepts.
Thus, even though more straightforward methods like the power rule are typically used, the limit definition remains a cornerstone of understanding derivatives.
- \( f^{\prime}(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h} \)
In practice, while using the limit definition directly can be cumbersome, it ensures the precision and validity of derivative calculations.
In our exercise, identifying that we're essentially looking for an expression \( f^{\prime}(x) \) first, before substituting any value like \( a \), is crucial. It verifies our process, ensuring that the steps prior to applying rules like the power rule adhere to the foundational calculus concepts.
Thus, even though more straightforward methods like the power rule are typically used, the limit definition remains a cornerstone of understanding derivatives.
Other exercises in this chapter
Problem 20
If the sequence is convergent, find its limit. If it is divergent, explain why. $$a_{n}=\frac{5 n}{n+5}$$
View solution Problem 20
Evaluate the limit, if it exists. $$\lim _{t \rightarrow 0}\left(\frac{1}{t}-\frac{1}{t^{2}+t}\right)$$
View solution Problem 21
Use a graphing device to determine whether the limit exists. If the limit exists, estimate its value to two decimal places. $$\lim _{x \rightarrow 0} \cos \frac
View solution Problem 21
If the sequence is convergent, find its limit. If it is divergent, explain why. $$a_{n}=\frac{n^{2}}{n+1}$$
View solution