Problem 20
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(t+8)(t-8)$$
Step-by-Step Solution
Verified Answer
The product is \(t^2 - 64\).
1Step 1: Identify the Problem Type
The exercise requires finding the product \((t+8)(t-8)\). Notice that this is a difference of squares pattern, \((a+b)(a-b) = a^2 - b^2\). In our case, substitute \(t\) for \(a\) and \(8\) for \(b\).
2Step 2: Apply the Difference of Squares Formula
Using the difference of squares pattern, the expression \((t+8)(t-8)\) is equivalent to \(t^2 - 8^2\). This simplifies the multiplication process by applying this well-known pattern.
3Step 3: Compute the Squares
Now, compute the squares of the individual terms: \(t^2\) remains \(t^2\), and \(8^2\) is \(64\).
4Step 4: Write the Final Expression
Replace the squares with their computed values in the expression \(t^2 - 8^2\) to obtain \(t^2 - 64\). This is the simplified product of the original binomials.
Key Concepts
Multiplying BinomialsAlgebraic ExpressionsSpecial Products
Multiplying Binomials
When faced with the task of multiplying binomials, one effective strategy is to use special patterns that allow for quick and efficient computation. In the given exercise, you encounter the binomials \((t+8)\) and \((t-8)\). The goal is to calculate their product. By recognizing that this expression fits the difference of squares pattern, you can apply a useful formula instead of expanding and combining terms the conventional way.
- Difference of squares formula: \((a+b)(a-b) = a^2 - b^2\)
Algebraic Expressions
Algebraic expressions, such as \((t+8)(t-8)\), consist of variables, numbers, and arithmetic operations. They sometimes require simplification to reveal their essence. To address them effectively, understanding operations like addition, subtraction, multiplication, and division is vital.
- Variables represent unknown quantities (e.g., \(t\)).
- Arithmetic operations manipulate these variables and constants within expressions.
Special Products
Special products refer to algebraic products that result from multiplying certain binomials in a way that reflects specific recognizable patterns. In our case, \((t+8)(t-8)\) exemplifies a special product known as a difference of squares.
- The formula for difference of squares: \(a^2 - b^2\).
- This formula can be quickly applied to simplify products without direct term-by-term multiplication.
Other exercises in this chapter
Problem 20
Use the difference-of-squares pattern to factor each of the following. $$(x-1)^{2}-(x-8)^{2}$$
View solution Problem 20
Factor each of the composite numbers into the product of prime numbers. For example, \(30=2 \cdot 3 \cdot 5 .\) $$91$$
View solution Problem 20
Find each product. $$\left(\frac{3}{4} x^{4} y^{5}\right)\left(-x^{2} y\right)$$
View solution Problem 20
Add the given polynomials. \(-x^{2}-x-4,2 x^{2}-7 x+9\), and \(-3 x^{2}+6 x-10\)
View solution