Problem 20
Question
Find \(c\) such that \(f^{\prime}(c)=0\) and determine whether \(f(x)\) has a local extremum at \(x=c .\) \(f(x)=(x-4)^{2}\)
Step-by-Step Solution
Verified Answer
The function has a local minimum at \( x = 4 \).
1Step 1: Find the Derivative
First, we need to find the derivative of the function \( f(x) = (x - 4)^2 \). Using the power rule, the derivative is: \( f'(x) = 2(x - 4) \).
2Step 2: Solve for Critical Points
To find the value of \( c \) where \( f'(c) = 0 \), set the derivative equal to zero and solve for \( x \): \[ 2(x - 4) = 0 \]. Dividing both sides by 2 gives \( x - 4 = 0 \). Adding 4 to both sides, we get \( x = 4 \). Thus, \( c = 4 \).
3Step 3: Determine if Local Extremum Exists
To determine if there is a local extremum at \( x = c \), we check the second derivative, \( f''(x) \). The second derivative of \( f(x) = (x - 4)^2 \) is \( f''(x) = 2 \), which is positive, indicating that \( f(x) \) is concave up at \( x = 4 \). This means \( f(x) \) has a local minimum at \( x = 4 \).
Key Concepts
Understanding DerivativesExploring Local ExtremaThe Power Rule in Calculus
Understanding Derivatives
Derivatives are a fundamental concept in calculus. They measure how a function changes as its input changes. Think of a derivative as the 'speed' at which a function's value changes. For example, the derivative of a position function with respect to time gives the velocity. In our exercise, we dealt with
- a specific quadratic function: \(f(x) = (x-4)^2\).
Exploring Local Extrema
A local extremum is a point on a function where it achieves a maximum or minimum value in a small interval around that point. It's important because these points often represent optimal values in real-world contexts, such as the highest profit or the least cost.
In mathematical terms, a function has a local minimum at a point \(x = c\) if \(f(c)\) is the lowest point in the neighborhood around \(c\). Conversely, it's a local maximum if \(f(c)\) is the highest. To determine if the point is a local extremum, we:
In mathematical terms, a function has a local minimum at a point \(x = c\) if \(f(c)\) is the lowest point in the neighborhood around \(c\). Conversely, it's a local maximum if \(f(c)\) is the highest. To determine if the point is a local extremum, we:
- First find where the derivative \(f'(x)\) equals zero, as this often indicates where extreme values might occur.
- Then check the concavity of the function by analyzing the second derivative. In our case, a positive second derivative (\(f''(x) = 2\)) signifies that the function is concave up, indicating a local minimum at that point.
The Power Rule in Calculus
The power rule is one of the simplest and most commonly used methods for finding derivatives. It states that if you have a function such as \(x^n\), the derivative is \(nx^{n-1}\). This rule helps simplify the process of differentiation, especially for polynomials.
In our example:
In our example:
- We started with \(f(x) = (x-4)^2\).
- Applying the power rule, we treated \((x-4)\) as a single term to easily find the derivative \(f'(x) = 2(x-4)\).
Other exercises in this chapter
Problem 20
Determine where each function is increasing, decreasing, concave up, and concave down. With the help of a graphing calculator, sketch the graph of each function
View solution Problem 20
In Problems 1-40, find the general antiderivative of the given function. $$ f(x)=e^{x / 2}+e^{-x / 2} $$
View solution Problem 20
A circular sector with radius \(r\) and angle \(\theta\) has area \(A .\) Find \(r\) and \(\theta\) so that the perimeter is smallest for a given area \(A .(\)
View solution Problem 21
Use l'Hospital's rule to find the limits. $$ \lim _{x \rightarrow \infty} \frac{(\ln x)^{2}}{x^{2}} $$
View solution