Problem 20
Question
Find an equation of the tangent plane to the graph of the given equation at the indicated point. $$ x z=6 ;(2,0,3) $$
Step-by-Step Solution
Verified Answer
The equation of the tangent plane is \( 3x + 2z = 12 \).
1Step 1: Understand the Problem
We need to find the equation of the tangent plane to the surface given by the equation \( xz = 6 \) at the point \((2, 0, 3)\). The equation of a tangent plane to a surface \( F(x, y, z) = 0 \) at a point \((x_0, y_0, z_0)\) is given by \( F_x(x_0, y_0, z_0) (x - x_0) + F_y(x_0, y_0, z_0) (y - y_0) + F_z(x_0, y_0, z_0) (z - z_0) = 0 \).
2Step 2: Identify the Function and Point
The surface can be written as \( F(x, y, z) = xz - 6 = 0 \). We are looking for the tangent plane at the specific point \((x_0, y_0, z_0) = (2, 0, 3)\).
3Step 3: Calculate Partial Derivatives
First, calculate the partial derivatives of \( F(x, y, z) = xz - 6 \) with respect to \( x \), \( y \), and \( z \). Thus, we have:- \( F_x = z \)- \( F_y = 0 \)- \( F_z = x \)
4Step 4: Evaluate Partial Derivatives at the Given Point
Substitute the point \((2, 0, 3)\) into the partial derivatives:- \( F_x(2, 0, 3) = 3 \)- \( F_y(2, 0, 3) = 0 \)- \( F_z(2, 0, 3) = 2 \)
5Step 5: Formulate the Tangent Plane Equation
Substitute the evaluated partial derivatives and the point \((x_0, y_0, z_0)\) into the equation of the tangent plane:\[ 3(x - 2) + 0(y - 0) + 2(z - 3) = 0 \]Simplifying this, we get:\[ 3x + 2z = 12 \]
6Step 6: Simplify the Equation
Rearrange the equation to its simplest form:\[ 3x + 2z = 12 \]This is the equation of the tangent plane.
Key Concepts
Partial DerivativesMultivariable CalculusSurface Equation
Partial Derivatives
Partial derivatives are a fundamental concept in multivariable calculus. They help us understand how a function changes as we tweak one variable while keeping the others constant. This is similar to taking the derivative in single-variable calculus but in the context of functions with several variables. So, imagine a mountain range.
- The partial derivative in the x-direction tells us how steep the incline is when moving directly horizontally across the range.
- The partial derivative in the y-direction would tell the story of the steepness when you are moving forward or backward through the range.
- \( F_x \) tells us how the surface changes as \( x \) changes, which is simply \( z \).
- \( F_y \) shows no change here with respect to \( y \), resulting in zero: \( F_y = 0 \).
- \( F_z \) indicates the change due to \( z \), which is \( x \).
Multivariable Calculus
Multivariable calculus extends traditional calculus to functions of two, three, or even more variables. It's a powerful tool in fields like physics, engineering, statistics, and economics, where simple single-variable calculus isn't sufficient. In multivariable calculus, we are interested in quantities such as:
- Partial derivatives: Derivatives with respect to each individual variable, showing how a function changes.
- Gradient: A vector composed of all the partial derivatives, indicating the direction of the steepest ascent of a function.
- Tangent planes: Planes that just touch the surface of a graph at a point, not cutting through it.
Surface Equation
In this context, a surface equation like \( xz = 6 \) describes a relationship between variables \( x, y, \) and \( z \) that form a surface in a 3D space. Such equations are pivotal in understanding how different variables interact to form complex shapes. When dealing with a surface, we often want to find characteristics like slopes, tangents, and changes in altitude.To gain insights into these surfaces:
- A surface equation represents a condition that the points \( (x, y, z) \) must satisfy to lie on the surface.
- Tangent planes are flat surfaces that lightly touch the curved surface at a point, providing a linear approximation at that location.
Other exercises in this chapter
Problem 20
Show that the given integral is independent of the path. Evaluate. $$ \int_{(0,0,0)}^{(1,1,1)} 2 x d x+3 y^{2} d y+4 z^{3} d z $$
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Find \(\mathbf{r}^{\prime}(t)\) and \(\mathbf{r}^{\prime \prime}(t)\) for the given vector function. $$ \mathbf{r}(t)=t^{2} \mathbf{i}+t^{3} \mathbf{j}+\tan ^{-
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In Problems \(21-24\), find the volume of the solid bounded by the graphs of the given equations. \(x=y^{2}, 4-x=y^{2}, z=0, z=3\)
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