Problem 20
Question
Find an equation of the line that satisfies the given conditions. Through \((-2,4) ;\) slope \(-1\)
Step-by-Step Solution
Verified Answer
The equation of the line is \(y = -x + 2\).
1Step 1: Understand the Problem
We need to find the equation of a line that passes through the point \((-2, 4)\) with a slope of \(-1\).
2Step 2: Use Point-Slope Form
The point-slope form of a linear equation is given by \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a point on the line. Here, \(m = -1\), \(x_1 = -2\), and \(y_1 = 4\).
3Step 3: Substitute Values
Substitute the values into the point-slope form: \(y - 4 = -1(x + 2)\).
4Step 4: Simplify the Equation
Distribute the slope on the right side and then simplify: \(y - 4 = -x - 2\).
5Step 5: Solve for y
Add 4 to both sides to solve for \(y\): \(y = -x + 2\). This is the equation of the line in slope-intercept form.
Key Concepts
Point-Slope Form of a Linear EquationSlope-Intercept Form and Its AdvantagesAlgebraic Manipulation to Transition Between Forms
Point-Slope Form of a Linear Equation
The point-slope form is a handy tool when you know one point on a line and the slope. This form is expressed as \( y - y_1 = m(x - x_1) \). Here, \( m \) represents the slope, while \( (x_1, y_1) \) is a point on the line. This format allows you to write an equation easily because you plug in values directly without rearranging terms.
In our example, the problem gives us a slope of -1 and a point (-2, 4). Plug these values into the point-slope formula, replacing \( m \) with -1, \( x_1 \) with -2, and \( y_1 \) with 4. This results in the equation:
In our example, the problem gives us a slope of -1 and a point (-2, 4). Plug these values into the point-slope formula, replacing \( m \) with -1, \( x_1 \) with -2, and \( y_1 \) with 4. This results in the equation:
- \( y - 4 = -1(x + 2) \)
Slope-Intercept Form and Its Advantages
The slope-intercept form, expressed as \( y = mx + b \), is a popular and versatile way of writing equations. Here, \( m \) is the slope of the line, and \( b \) is the y-intercept. This form is straightforward to interpret: it tells us the line's steepness and where it crosses the y-axis.
From our exercise, after simplifying the point-slope equation, we arrive at \( y = -x + 2 \). In this arrangement:
From our exercise, after simplifying the point-slope equation, we arrive at \( y = -x + 2 \). In this arrangement:
- The slope \( m \) is -1, indicating the line decreases as you move along the x-axis.
- The intercept \( b \) is 2, meaning the line crosses the y-axis at \( y = 2 \).
Algebraic Manipulation to Transition Between Forms
Algebraic manipulation involves changing the equation from one form to another using arithmetic operations. This skill is central in moving from the point-slope form to the slope-intercept form, often making the equation more understandable.
Starting with \( y - 4 = -1(x + 2) \), distribute the -1 to both terms inside the parenthesis:
Starting with \( y - 4 = -1(x + 2) \), distribute the -1 to both terms inside the parenthesis:
- \( y - 4 = -x - 2 \)
- \( y = -x + 2 \)
Other exercises in this chapter
Problem 19
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ 4 y=x^{2} $$
View solution Problem 19
Sketch the region given by the set. \(\\{(x, y)| | x | \leq 2 \text { and }|y| \leq 3\\}\)
View solution Problem 20
Express the statement as an equation. Use the given information to find the constant of proportionality. \(P\) is directly proportional to \(T .\) If \(T=300,\)
View solution Problem 20
\(11-22\) a Determine an appropriate viewing rectangle for the equation, and use it to draw the graph. $$ y=\frac{x}{x^{2}+25} $$
View solution