Problem 20
Question
Explain the outcome of the following reactions by a mechanism showing how the product could be formed. a. 2,6-Di- \((t\)-butyl)phenoxide reacts with \(o\)-nitroaryl halides in \(\mathrm{NaOH} / \mathrm{DMSO}\) at \(80^{\circ} \mathrm{C}\) to give 2,6 -di- \((t\)-butyl)-4-(2-nitrophenyl)phenol in \(60-90 \%\) yield. Under similar conditions, 1,4-dinitrobenzene gives 2,6-di- \((t\)-butyl)-4(4-nitrophenyl)phenol. b. 2 -(3-Chlorophenyl)-4,4-dimethyloxazoline reacts with alkyllithium reagents to give 2-(2-alkylphenyl)-4,4-dimethyloxazolines. c. Nitrobenzene reacts with cyanomethyl phenyl sulfide in \(\mathrm{NaOH} / \mathrm{DMSO}\) to give a mixture of 2- and 4-nitrophenylacetonitrile. d. The following transformation occurs: e. Reaction of benzene with 3,3,3-trifluoropropene in the presence of \(\mathrm{BF}_{3}\) gives 3,3,3-trifluoropropylbenzene. f. 3-Chloronitrobenzene reacts with 4-amino-1,2,4-triazole in \(\mathrm{K}^{+} .{ }^{-} \mathrm{O}-t-\mathrm{Bu} /\) DMSO to give 2-chloro-4-nitroaniline. g. Good yields of tetralone can be obtained from 4-phenylbutanoic acid or the corresponding acyl chloride in the presence of the strongly acidic resin Nafion-H. With 3-phenylpropanonic acid, only the acyl chloride gives a cyclization product.
Step-by-Step Solution
VerifiedKey Concepts
Nucleophilic Aromatic Substitution
This process typically involves the initial attack by the nucleophile on the carbon atom bearing the leaving group, often a halide. The bond between the carbon and the halide is then broken, leading to the departure of the halide ion. The result is a new carbon-nucleophile bond, replacing the one with the leaving group.
- The nucleophile must be strong enough; a powerful ion like the phenoxide is ideal.
- The reaction is significantly affected by the nature of substituents present on the aromatic ring.
- Nitro groups or other electron-withdrawing groups enhance the electrophilicity of the carbon center.
Phenoxide Ion Deprotonation
- In this scenario, phenol acts as an acid, donating a proton.
- The phenoxide ion formed is more stable than the starting phenol in basic conditions.
- It plays a crucial role in subsequent nucleophilic substitutions.
Because of its reactivity, the phenoxide ion is ideally suited to participate in further chemical transformations, making it invaluable in synthetic chemistry.
Electrophilic Centers
- Electron-withdrawing groups pull electron density away from the carbon, enhancing its electrophilicity.
- The stronger the electron-withdrawing ability, the more reactive the electrophilic center.
- These centers play a pivotal role in determining the mechanism and rate of reactions.
The interplay of nucleophilic and electrophilic centers drives many synthetic transformations, allowing chemists to manipulate and design complex organic molecules.
Rearrangement Mechanisms
Rearrangements often follow the formation of unstable intermediates that facilitate a shift of groups within the molecule. These shifts can be driven by electronic factors, such as the distribution of electron density or the stabilization conferred by electron-withdrawing groups.
- Rearrangements can lead to unexpected products, differing from simple substitution.
- They often proceed through a sequence of bond-breaking and bond-forming steps.
- The outcome is highly dependent on the stability of the intermediates formed.
Understanding these mechanisms is essential in predicting the course and outcome of intricate synthetic pathways, offering vital insights into the adaptability and resilience of chemical structures.