Problem 20
Question
Explain how the graph of \(f\) can be obtained from the graph of \(y=\frac{1}{x}\) or \(y=\frac{1}{x^{2}}\) Draw a sketch of the graph of \(f\) by hand. Then generate an accurate depiction of the graph with a graphing calculator. Finally, give the domain and range. $$f(x)=\frac{1}{x-3}$$
Step-by-Step Solution
Verified Answer
The graph of \( f(x) = \frac{1}{x-3} \) is obtained by shifting \( y = \frac{1}{x} \) 3 units right, with domain \( x \neq 3 \) and range \( y \neq 0 \).
1Step 1: Identify the Base Graph
The given function is based on the form \( y = \frac{1}{x} \). The base graph for this function is the hyperbola represented by \( y = \frac{1}{x} \). This graph has vertical and horizontal asymptotes at \( x = 0 \) and \( y = 0 \) respectively.
2Step 2: Determine Transformations
The function \( f(x) = \frac{1}{x-3} \) can be rewritten as \( y = \frac{1}{(x-3)} \). This transformation involves a horizontal shift to the right by 3 units, as it modifies \( x \) to \( x-3 \), shifting the asymptotes to \( x=3 \) and \( y=0 \).
3Step 3: Sketch the Graph
To sketch the graph, start by drawing the horizontal asymptote at \( y = 0 \). Then, draw the vertical asymptote at \( x = 3 \). The hyperbolic graph will approach these asymptotes but never touch them. It will lie in the first and third quadrants due to the positive nature of \( y = \frac{1}{x} \).
4Step 4: Use a Graphing Calculator
Using a graphing calculator, input \( y = \frac{1}{x-3} \). This should show a graph with the same shape as the base graph, but shifted 3 units to the right. The graph will closely match your sketch, confirming the location of the asymptotes.
5Step 5: Determine the Domain and Range
For the function \( f(x) = \frac{1}{x-3} \), the domain excludes \( x = 3 \) where the function is undefined, so the domain is \( x \in (-\infty, 3) \cup (3, \infty) \). The range excludes \( y = 0 \) since the function has a horizontal asymptote at \( y = 0 \), so the range is \( y \in (-\infty, 0) \cup (0, \infty) \).
Key Concepts
AsymptotesDomain and RangeHyperbolic Functions
Asymptotes
Asymptotes are lines that a graph can get very close to but usually never touch. They help us understand the behavior of functions as they approach certain values. There are two main types of asymptotes relevant to the function \( f(x) = \frac{1}{x-3} \):
- Vertical Asymptotes: These occur where the function is undefined. For \( f(x) = \frac{1}{x-3} \), the function is undefined at \( x = 3 \) because dividing by zero is not possible. Thus, \( x = 3 \) is a vertical asymptote.
- Horizontal Asymptotes: These indicate the value that the function approaches as \( x \) goes to infinity or negative infinity. Here, the horizontal asymptote is \( y = 0 \). As \( x \) moves further away from 3, \( f(x) \) gets closer to 0 but never quite reaches it.
Domain and Range
The domain and range of a function tell us, respectively, which \( x \) values we can input and which \( y \) values we can get as output. For our function \( f(x) = \frac{1}{x-3} \):
- The domain includes all real numbers except where the function is undefined. Since the function is undefined at \( x = 3 \), the domain is \( x \in (-\infty, 3) \cup (3, \infty) \).
- The range includes all real \( y \) values except where the graph has a horizontal asymptote. Here, there is a horizontal asymptote at \( y = 0 \), so the range is \( y \in (-\infty, 0) \cup (0, \infty) \).
Hyperbolic Functions
Hyperbolic functions like \( y = \frac{1}{x} \) and its transformations have a distinct shape that resembles two branches approaching each other but never meeting. The function \( f(x) = \frac{1}{x-3} \) inherits this hyperbolic form but shifts horizontally.
- Basic Characteristics: Hyperbolic graphs often exist in two quadrants, either in the first and third or the second and fourth, depending on the transformation. For \( f(x) = \frac{1}{x-3} \), the branches are in the first and third quadrants, indicating that as \( x \) increases or decreases away from 3, \( f(x) \) approaches zero.
- Transformation: The transformation \( x \rightarrow x-3 \) shifts the entire graph to the right by 3 units, moving the vertical asymptote to \( x = 3 \).
Other exercises in this chapter
Problem 20
Find all complex solutions for each equation by hand. Do not use a calculator. $$4+\frac{7}{x}=-\frac{1}{x^{2}}$$
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Use positive rational exponents to rewrite each expression. Assume variables represent positive numbers. $$\sqrt[3]{2 x}$$
View solution Problem 21
Find all complex solutions for each equation by hand. Do not use a calculator. $$\frac{x}{2-x}+\frac{2}{x}-5=0$$
View solution