Problem 20
Question
Draw the graphs of \(f, g,\) and \(f+g\) on a common screen to illustrate graphical addition. $$ f(x)=\sqrt[4]{1-x}, g(x)=\sqrt{1-\frac{x^{2}}{9}} $$
Step-by-Step Solution
Verified Answer
Graph the functions \(f(x)\), \(g(x)\), and \(f(x)+g(x)\) over their valid domains, then observe the changes.
1Step 1: Understanding the Functions
We have two functions: \(f(x) = \sqrt[4]{1-x}\) and \(g(x) = \sqrt{1-\frac{x^2}{9}}\). The function \(f(x)\) is defined for \(1-x \geq 0\), which means the domain is \(x \leq 1\). The function \(g(x)\) describes the upper semicircle of the ellipse given by \(x^2/9 + y^2 = 1\), hence its domain is \(-3 \leq x \leq 3\).
2Step 2: Finding the Domain for Addition
The domain of \(f(x) + g(x)\) will be the intersection of the domains of \(f\) and \(g\), which is \(-3 \leq x \leq 1\).
3Step 3: Graphing the Function \(f(x)\)
Plot the graph of \(f(x) = \sqrt[4]{1-x}\) over the domain \(-3 \leq x \leq 1\). This graph will start from \(f(-3)\) which is imaginary and real values begin only \(x=1\) going downwards as \(x\) approaches \(-3\).
4Step 4: Graphing the Function \(g(x)\)
Plot the graph of \(g(x) = \sqrt{1-\frac{x^2}{9}}\). It will trace the upper half of an ellipse with a horizontal range from \(-3\) to \(3\).
5Step 5: Graphing \(f(x) + g(x)\)
Finally, plot the graph of \(f(x) + g(x)\) which adds the values from \(f(x)\) and \(g(x)\) across their common domain, \(-3 \leq x \leq 1\). For any \(x\), the value is \(\sqrt[4]{1-x} + \sqrt{1-\frac{x^2}{9}}\).
6Step 6: Analyzing the Graphs
Compare the individual graphs of \(f(x)\) and \(g(x)\) with their sum. Notice the shape changes indicating the effect of graphical addition.
Key Concepts
Domain of FunctionsPlotting GraphsIntersection of Domains
Domain of Functions
When we talk about the domain of a function, we mean the set of all possible input values (usually represented as "x") that the function can accept without causing any mathematical errors. The domain is very important because it helps us understand the limits within which the function behaves normally and can be graphed.
Let's examine two functions:
Let's examine two functions:
- The function \(f(x) = \sqrt[4]{1-x}\) has a domain defined by the condition that everything inside the root should be non-negative. So, \(1-x \geq 0\), leading to \(x \leq 1\). This means \(f(x)\) is only defined and will produce real numbers when \(x\) is less than or equal to 1.
- The function \(g(x) = \sqrt{1-\frac{x^2}{9}}\) represents the upper half of an ellipse. Its domain comes from ensuring the expression inside the square root remains non-negative, giving us \(x^2/9 \leq 1\), which simplifies to \(-3 \leq x \leq 3\).
Plotting Graphs
Graphing functions involves illustrating their behavior on a coordinate plane. It is a visual tool that helps comprehend mathematical relationships. Before starting, it's essential to understand the domain, as it shows us where the function is happy and healthy.
For example:
For example:
- The graph of \(f(x) = \sqrt[4]{1-x}\) will appear only on the left side of the coordinate plane up until \(x=1\). On plotting, you will notice the graph starts from 1 and declines as you move left, within the allowable domain. Imaginary numbers begin to affect if you move right of \(x=1\).
- The plot \(g(x) = \sqrt{1-\frac{x^2}{9}}\), on the other hand, draws out the top portion of an ellipse, existing between \(-3\) and \(3\). As you plot this, you'll see a smooth curve intercepting the x-axis at \(-3, 0\) and \(3, 0\).
Intersection of Domains
The intersection of domains occurs when we want to perform operations involving multiple functions, and it involves finding the "common ground" between them. This concept is important because it determines the new domain where combined functions like \(f(x) + g(x)\) behave well together.
For the functions \(f(x) = \sqrt[4]{1-x}\) and \(g(x) = \sqrt{1-\frac{x^2}{9}}\), their intersection means finding x-values where both functions are defined.
Given the domains:
For the functions \(f(x) = \sqrt[4]{1-x}\) and \(g(x) = \sqrt{1-\frac{x^2}{9}}\), their intersection means finding x-values where both functions are defined.
Given the domains:
- \(f(x)\) is valid where \(x \leq 1\)
- \(g(x)\) exists where \(-3 \leq x \leq 3\)
Other exercises in this chapter
Problem 19
Sketch the graph of the function by first making a table of values. \(f(x)=1+\sqrt{x}\)
View solution Problem 19
Evaluate the function at the indicated values. $$ \begin{array}{l}{f(x)=2 x+1} \\ {f(1), f(-2), f\left(\frac{1}{2}\right), f(a), f(-a), f(a+b)}\end{array} $$
View solution Problem 20
Determine whether the function is one-to-one. $$ f(x)=\frac{1}{x} $$
View solution Problem 20
A function is given. Determine the average rate of change of the function between the given values of the variable. $$ f(t)=\sqrt{t}, \quad t=a, t=a+h $$
View solution