Problem 20
Question
Determine whether the ordered pair is a solution of the system of equations. See Example 1. $$ (2.1,-3.2) ;\left\\{\begin{array}{c} x+y=-1.1 \\ 2 x-3 y=13.8 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The ordered pair \((2.1, -3.2)\) is a solution to the system of equations.
1Step 1: Understand the Problem
We are given a system of two equations with two variables, \(x\) and \(y\). The ordered pair \((2.1, -3.2)\) needs to be checked for both equations to determine if it satisfies the system.
2Step 2: Substitute into First Equation
The first equation is \(x + y = -1.1\). Substitute \(x = 2.1\) and \(y = -3.2\) into this equation: \[ 2.1 + (-3.2) \stackrel{?}{=} -1.1 \] Calculate the left side: \[ 2.1 - 3.2 = -1.1 \] Both sides are equal, so the ordered pair satisfies the first equation.
3Step 3: Substitute into Second Equation
The second equation is \(2x - 3y = 13.8\). Again, substitute \(x = 2.1\) and \(y = -3.2\): \[ 2(2.1) - 3(-3.2) \stackrel{?}{=} 13.8 \] Calculate each term: \[ 4.2 + 9.6 = 13.8 \] Since both sides are equal, the ordered pair also satisfies the second equation.
4Step 4: Conclusion
Since the ordered pair \((2.1, -3.2)\) satisfies both equations in the system, it is a solution to the system of equations.
Key Concepts
Ordered Pairs: A Basic Building BlockSubstitution Method: Solving Systems Step-by-StepIdentifying Solutions to Equations
Ordered Pairs: A Basic Building Block
Ordered pairs are fundamental in understanding how to locate points on a plane and evaluate solutions in systems of equations. An ordered pair typically takes the form \((x, y)\) with the first number, \(x\), representing the horizontal position, and the second number, \(y\), representing the vertical position.
- In the context of a coordinate system, these numbers indicate a specific point on a graph.
- This concept is crucial for understanding solutions to equations since they can be visually represented as intersections of lines or curves on a graph.
- Each equation in a system introduces constraints that determine acceptable values for \(x\) and \(y\). Together, these constraints define the set of possible solutions.
Substitution Method: Solving Systems Step-by-Step
The substitution method is a popular algebraic technique used to find the solution to a system of equations. It involves replacing one variable with an equivalent expression obtained from another equation, essentially transforming a two-variable problem into a one-variable problem. This method simplifies the process of finding values for \(x\) and \(y\) that satisfy both equations.
- First, solve one of the equations for one variable. For instance, solve for \(y\) in terms of \(x\) using the first equation.
- Next, substitute this expression into the other equation. This step involves plugging the expression derived for \(y\) into the second equation.
- Solve the resulting single-variable equation. This will give a specific value for \(x\).
- Finally, substitute back to find the value of the other variable. Use the calculated \(x\) value to find \(y\).
Identifying Solutions to Equations
A solution to a system of equations is a specific set of values for variables that makes all equations in the system true simultaneously. In simple terms, it means finding where the graphs of these equations intersect if plotted.
- Once you have determined potential solutions using methods like substitution, verify by substituting these values back into each original equation.
- If both equations are satisfied, the ordered pair is indeed a solution to the system.
- Remember, a system can have one solution, no solution, or infinitely many solutions, depending on how equations relate to one another.
Other exercises in this chapter
Problem 20
Perform each of the following elementary row operations on the augumented matrix \(\left[\begin{array}{rrr}-3 & 1 & -6 \\ 1 & -4 & 4\end{array}\right].\) $$ 3 R
View solution Problem 20
Solve each system by substitution. See Examples 1 and 2 . $$ \left\\{\begin{array}{l} 0.9 p+0.2 q=1.2 \\ \frac{2}{3} p+\frac{1}{9} q=1 \end{array}\right. $$
View solution Problem 20
Solve each system. $$ \left\\{\begin{array}{l} 4 x-3 y+5 z=23 \\ 2 x-5 y-3 z=13 \\ -4 x-6 y+7 z=7 \end{array}\right. $$
View solution Problem 21
Evaluate each determinant. $$ \left|\begin{array}{cc} -6 & -2 \\ 15 & 4 \end{array}\right| $$
View solution