Problem 20
Question
Determine whether the given message is a code word in the Hamming \((7,4)\) code. If it is, decode it. If it is not, correct the single error and decode the corrected message. $$ \left.\begin{array}{llllllll} (1 & 1 & 0 & 0 & 0 & 0 & 0 \end{array}\right) $$
Step-by-Step Solution
Verified Answer
The message has a single error; the corrected code word decodes to (1, 1, 0, 0).
1Step 1: Define Hamming (7,4) Code
The Hamming \((7, 4)\) code is a specific linear error-correcting code used to encode 4 bits of data into 7 bits by adding 3 parity bits. The standard way to write a Hamming code uses the matrix form for encoding and decoding.
2Step 2: Construct Parity Check Matrix
For the Hamming \((7, 4)\) code, the parity check matrix \(H\) is given by:\[H = \begin{bmatrix}1 & 0 & 0 & 0 & 1 & 1 & 1 \0 & 1 & 0 & 0 & 1 & 1 & 0 \0 & 0 & 1 & 0 & 1 & 0 & 1 \0 & 0 & 0 & 1 & 0 & 1 & 1 \end{bmatrix}\]
3Step 3: Calculate Syndrome
To find if a single error is present, we calculate the syndrome \(S\) by multiplying the received message by the parity check matrix:\[S = \begin{bmatrix} 1 & 1 & 0 & 0 & 0 & 0 & 0 \end{bmatrix} \cdot H^T \]\[S = \begin{bmatrix} 1 \cdot 1 + 1 \cdot 0 + 0 \cdot 0 + 0 \cdot 0 + 0 \cdot 1 + 0 \cdot 1 + 0 \cdot 1, \ 1 \cdot 1 + 1 \cdot 0 + 0 \cdot 1 + 0 \cdot 0 + 0 \cdot 1 + 0 \cdot 1 + 0 \cdot 0, \ 1 \cdot 1 + 1 \cdot 1 + 0 \cdot 0 + 0 \cdot 1 + 0 \cdot 1 + 0 \cdot 0 + 0 \cdot 1 \end{bmatrix}\]\[S = \begin{bmatrix} 1, 1, 1 \end{bmatrix}\]Thus, the syndrome is \([1, 1, 1]\).
4Step 4: Locate and Correct the Error
The syndrome \([1, 1, 1]\) corresponds to the error being in the 7th bit of the message, as it identifies the binary representation of the position of the bit with the error. Hence, flipping the 7th bit in the received message rotates it to \((1, 1, 0, 0, 0, 0, 1)\).
5Step 5: Decode the Corrected Code Word
In the Hamming \((7, 4)\) code, the first four bits are the data bits. Therefore, for the corrected code word \((1, 1, 0, 0, 0, 0, 1)\), the data bits are \((1, 1, 0, 0)\).
Key Concepts
Error CorrectionParity Check MatrixSyndrome DecodingLinear Codes
Error Correction
Error correction is a cornerstone of communication systems. It ensures that even when errors occur during data transmission, the correct original message can be retrieved. In the context of Hamming codes, error correction involves identifying and correcting a single bit error.
These codes are specifically designed to detect and correct errors without needing to resend data. This is crucial in environments where resending data is either not feasible or costly, such as in satellite communications. Using Hamming \(7,4\) code, a 4-bit message can be encoded into a 7-bit codeword to allow error correction. When a message is received, any errors can be swiftly identified and corrected by using specialized techniques, like calculating the syndrome.
Error correction is not exclusive to Hamming codes but is a fundamental feature of many linear codes, providing robust, error-free communication.
These codes are specifically designed to detect and correct errors without needing to resend data. This is crucial in environments where resending data is either not feasible or costly, such as in satellite communications. Using Hamming \(7,4\) code, a 4-bit message can be encoded into a 7-bit codeword to allow error correction. When a message is received, any errors can be swiftly identified and corrected by using specialized techniques, like calculating the syndrome.
Error correction is not exclusive to Hamming codes but is a fundamental feature of many linear codes, providing robust, error-free communication.
Parity Check Matrix
The parity check matrix is a mathematical tool used to check the correctness of data received. It is a fundamental aspect of many linear codes, including the Hamming \(7,4\) code.
This matrix is crucial for encoding and decoding processes. In simple terms, it aids in verifying whether a received codeword is correct or if it has errors. For instance, the parity check matrix for Hamming \(7,4\) code is structured to evaluate all 7 bits of a codeword to determine correctness.
Given a codeword, multiplying it by the transpose of the parity check matrix yields the syndrome, which is a vector that signifies whether and where an error exists. Using this matrix makes the error detection and correction process efficient and reliable.
This matrix is crucial for encoding and decoding processes. In simple terms, it aids in verifying whether a received codeword is correct or if it has errors. For instance, the parity check matrix for Hamming \(7,4\) code is structured to evaluate all 7 bits of a codeword to determine correctness.
Given a codeword, multiplying it by the transpose of the parity check matrix yields the syndrome, which is a vector that signifies whether and where an error exists. Using this matrix makes the error detection and correction process efficient and reliable.
Syndrome Decoding
Syndrome decoding is a process used in identifying errors within a codeword. It leverages the parity check matrix to accomplish this task.
When a codeword is received, multiplying it by the transpose of the parity check matrix produces a result known as the syndrome. For Hamming codes, if the syndrome is \( [0, 0, 0] \), the codeword is error-free. However, if not all zeros, like \( [1, 1, 1] \), then an error has occurred.
The non-zero syndrome directly corresponds to the position of the erroneous bit, allowing the error to be corrected efficiently by flipping the bit located. This technique significantly reduces the chances of miscommunication and ensures data integrity.
When a codeword is received, multiplying it by the transpose of the parity check matrix produces a result known as the syndrome. For Hamming codes, if the syndrome is \( [0, 0, 0] \), the codeword is error-free. However, if not all zeros, like \( [1, 1, 1] \), then an error has occurred.
The non-zero syndrome directly corresponds to the position of the erroneous bit, allowing the error to be corrected efficiently by flipping the bit located. This technique significantly reduces the chances of miscommunication and ensures data integrity.
Linear Codes
Linear codes form a big family of error-correcting codes, including Hamming codes. These codes are based on linear algebra principles, which make them especially efficient for error detection and correction.
One of the key characteristics of linear codes is their ability to be represented using matrices, such as the parity check matrix. This matrix helps perform complex operations in a straightforward manner.
Linear codes have a structured way to manage error correction. Each linear code has specific properties, like minimum distance, that determines its capability to correct errors. In the case of Hamming \(7,4\) code, it’s designed to correct single bit errors, ensuring data accuracy is maintained during transmission.
One of the key characteristics of linear codes is their ability to be represented using matrices, such as the parity check matrix. This matrix helps perform complex operations in a straightforward manner.
Linear codes have a structured way to manage error correction. Each linear code has specific properties, like minimum distance, that determines its capability to correct errors. In the case of Hamming \(7,4\) code, it’s designed to correct single bit errors, ensuring data accuracy is maintained during transmission.
Other exercises in this chapter
Problem 19
In Problems 1-20, use either Gaussian elimination or Gauss-Jordan elimination to solve the given system or show that no solution exists. $$ \begin{aligned} x_{2
View solution Problem 19
If \(\mathbf{A}=\left(\begin{array}{rr}1 & -2 \\ -2 & 4\end{array}\right), \mathbf{B}=\left(\begin{array}{ll}6 & 3 \\ 2 & 1\end{array}\right)\), and \(\mathbf{C
View solution Problem 20
In Problems, determine whether the given matrix \(\mathbf{A}\) is diagonalizable. If so, find the matrix \(\mathbf{P}\) that diagonalizes \(\mathbf{A}\) and the
View solution Problem 20
Find the inverse of the given matrix or show that no inverse exists. $$ \left(\begin{array}{rrr} 1 & 0 & -1 \\ 0 & -2 & 1 \\ 2 & -1 & 3 \end{array}\right) $$
View solution