Problem 20
Question
Complete the following tables. $$\begin{array}{|c|c|c|} \hline\begin{array}{c}\text { First } \\\\\text { Number } \\\a\end{array} & \begin{array}{c}\text { Second } \\\\\text { Number } \\\b\end{array} & \begin{array}{c}\text { The Quotient } \\ \text { of } a \text { and } b\\\ \frac{a}{b} \end{array} \\ \hline -24 & -2 \\\\\hline -24 & -4 \\\\\hline -24 & -6 \\ \hline -24 & -8 \\\\\hline\end{array}$$
Step-by-Step Solution
Verified Answer
1st: 12, 2nd: 6, 3rd: 4, 4th: 3.
1Step 1: Understand the Task
We are given a table with two columns titled 'First Number' and 'Second Number', and we need to fill in the third column, 'The Quotient of a and b', which represents the division result of the 'First Number' by the 'Second Number'.
2Step 2: Analyze the Table
Identify the given values in the table. The 'First Number' is consistently \(-24\) for each row, while the 'Second Number' varies (\(-2\), \(-4\), \(-6\), and \(-8\)). We will calculate \(\frac{a}{b}\) for each row.
3Step 3: Calculate the Quotients
Determine the quotient for each row:- For the first row, \(-24\) divided by \(-2\) is \(\frac{-24}{-2} = 12\).- For the second row, \(-24\) divided by \(-4\) is \(\frac{-24}{-4} = 6\).- For the third row, \(-24\) divided by \(-6\) is \(\frac{-24}{-6} = 4\).- For the fourth row, \(-24\) divided by \(-8\) is \(\frac{-24}{-8} = 3\).
4Step 4: Fill in the Table
Insert the calculated results into the quotient section of each row:1. First row: \(12\)2. Second row: \(6\)3. Third row: \(4\)4. Fourth row: \(3\)
Key Concepts
Table CompletionInteger DivisionQuotients Calculation
Table Completion
When dealing with table completion in math, we are often asked to fill in missing values based on the information given in other parts of the table.
In our exercise, you're given a table with three key components:
To do this, identify the values, substitute them into your equation, and compute to find a solution. This requires your understanding of integer division and the relationship between the divisors and the dividend.
In our exercise, you're given a table with three key components:
- First Number (constant at -24)
- Second Number (varies across rows)
- The Quotient of the division of these two numbers
To do this, identify the values, substitute them into your equation, and compute to find a solution. This requires your understanding of integer division and the relationship between the divisors and the dividend.
Integer Division
Integer division is a crucial concept in prealgebra, especially when dealing with whole numbers that might be negative.
Here, integer indicates that you are dividing whole numbers, which can either be positive or negative, as in our example. When dividing integers like \(-24\) by any of the second numbers (-2, -4, -6, -8), you should remember:
Here, integer indicates that you are dividing whole numbers, which can either be positive or negative, as in our example. When dividing integers like \(-24\) by any of the second numbers (-2, -4, -6, -8), you should remember:
- Division of two negative integers results in a positive quotient.
- Always handle the negative signs before performing the arithmetic division of absolute values.
Quotients Calculation
The calculation of quotients is where you find the result of dividing one number by another.
This involves applying the process of division and involves understanding how the quotient relates to division, which is particularly vital in filling out tables or when checking table calculations. Here is how it works:
This involves applying the process of division and involves understanding how the quotient relates to division, which is particularly vital in filling out tables or when checking table calculations. Here is how it works:
- To find your quotient, identify your 'First Number' (dividend) and 'Second Number' (divisor).
- Apply the formula \(\frac{a}{b}\) where \(a\) is the dividend and \(b\) is the divisor.
- Solve for the quotient, ensuring correct arithmetic operation, especially with attention to signs.
Other exercises in this chapter
Problem 19
Combine the following by using the rule for addition of positive and negative numbers. $$-6+(-5)$$
View solution Problem 20
Subtract. $$121-21$$
View solution Problem 20
Apply the associative property to expression, and then simplify the result. \(4+(1+y)\)
View solution Problem 20
Find each of the following products. (Multiply.) $$-2(-3)(-4)$$
View solution