Problem 20
Question
An astronaut's pack weighs 17.5 \(\mathrm{N}\) when she is on earth but only 3.24 \(\mathrm{N}\) when she is at the surface of an asteroid. (a) What is the acceleration due to gravity on this asteroid? (b) What is the mass of the pack on the asteroid?
Step-by-Step Solution
Verified Answer
(a) \( g = 1.815 \, \text{m/s}^2 \), (b) Mass = 1.7857 kg.
1Step 1: Understand the Problem
We are given the weight of an astronaut's pack on Earth and on the surface of an asteroid. We need to find the acceleration due to gravity on the asteroid and the mass of the pack on the asteroid.
2Step 2: Recall the Formula for Weight
Weight is the force of gravity acting on an object and is given by the formula: \( W = m \cdot g \), where \( W \) is weight, \( m \) is mass, and \( g \) is the acceleration due to gravity.
3Step 3: Calculate Mass of the Pack
Use the weight of the pack on Earth to find its mass. On Earth, \( g = 9.8 \, \text{m/s}^2 \), and the weight \( W = 17.5 \, \text{N} \). Therefore, \( m = \frac{W}{g} = \frac{17.5}{9.8} = 1.7857 \, \text{kg}\).
4Step 4: Calculate Gravitational Acceleration on the Asteroid
Using the mass from Step 3 and the weight on the asteroid (3.24 N), use the formula \( W = m \cdot g \), where \( m = 1.7857 \, \text{kg} \) to find \( g \). Therefore, \( g = \frac{W}{m} = \frac{3.24}{1.7857} = 1.815 \text{m/s}^2 \).
5Step 5: Confirm Mass Consistency
The mass of the pack remains the same regardless of location in the universe: \( 1.7857 \, \text{kg} \). This is a constant property of matter.
Key Concepts
Understanding Acceleration Due to GravityUnderstanding Mass DeterminationUsing the Weight Formula
Understanding Acceleration Due to Gravity
Acceleration due to gravity is essentially the rate at which an object accelerates when it's falling down due to the gravitational pull of a celestial body. This acceleration is different for every planet, moon, or asteroid based on their mass and size. On Earth, the acceleration due to gravity is approximately 9.8 m/s².
When you know the weight of an object and its mass, you can use the relation between weight and gravitational force to solve any such problem involving different celestial bodies.
- This value is calculated based on Earth's mass and radius.
- It represents how strong Earth's gravitational pull is.
When you know the weight of an object and its mass, you can use the relation between weight and gravitational force to solve any such problem involving different celestial bodies.
Understanding Mass Determination
Mass is a measure of how much matter is in an object. It remains the same regardless of where the object is located in the universe. Unlike weight, which can vary if you’re on Earth or an asteroid, mass is constant.
This step emphasizes the importance of distinguishing between mass and weight. While they are related, these properties are not the same. Knowing the mass allows us to find the gravitational acceleration on the asteroid by using the weight measured there.
- Mass is measured in kilograms (kg).
- It can be calculated if you know the weight and gravitational acceleration.
This step emphasizes the importance of distinguishing between mass and weight. While they are related, these properties are not the same. Knowing the mass allows us to find the gravitational acceleration on the asteroid by using the weight measured there.
Using the Weight Formula
Weight is defined as the force exerted on an object due to gravity. It is calculated using the weight formula: \[ W = m \cdot g \]Where:- \( W \) is the weight of the object,- \( m \) is its mass,- \( g \) is the acceleration due to gravity.
Using this formula, you can determine how much an object will weigh under different gravitational conditions. For example:
Using this formula, you can determine how much an object will weigh under different gravitational conditions. For example:
- On Earth, the astronaut's pack weighs 17.5 N.
- On the asteroid, it weighs only 3.24 N because the gravitational pull is weaker.
Other exercises in this chapter
Problem 17
Superman throws a \(2400-N\) boulder at an adversary. What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 12.0 \(\m
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World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15 \(\mathrm{m} / \mathrm{s}^{2
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Imagine that you are holding a book weighing 4 \(\mathrm{N}\) at rest on the palm of your hand. Complete the following sentences: (a) A downward force of magnit
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