Problem 20
Question
A 1.20 \(\mathrm{kg}\) piece of cheese is placed on a vertical spring of negligible mass and force constant \(k=1800 \mathrm{N} / \mathrm{m}\) that is compressed 15.0 \(\mathrm{cm}\) . When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.)
Step-by-Step Solution
Verified Answer
The cheese rises approximately 1.72 meters from the initial position.
1Step 1: Understand the problem
We need to find how high the cheese rises after being released from a compressed spring. The cheese gains potential energy when the spring releases and converts it into kinetic energy and eventually gravitational potential energy. The energy conservation principle will guide the solution.
2Step 2: Write the energy conservation equation
Initially, the spring has potential energy stored due to its compression, given by the formula: \[ PE_{ ext{spring}} = \frac{1}{2} k x^2 \]where \(k = 1800 \, \text{N/m}\) is the spring constant and \(x = 0.15 \, \text{m}\) is the compression distance (remember to convert cm to m). This energy converts fully to gravitational potential energy \( PE_g \) when the cheese reaches the highest point. The equation representing this energy transformation is:\[ \frac{1}{2} k x^2 = mgh \]where \(m = 1.20 \, \text{kg}\) is the mass of the cheese, \(g = 9.81 \, \text{m/s}^2\) is the acceleration due to gravity, and \(h\) is the height we need to find.
3Step 3: Solve for height \(h\)
Rearrange the equation from Step 2 to solve for \(h\):\[ h = \frac{\frac{1}{2} k x^2}{mg} \]Substitute the known values into the equation:\[ h = \frac{\frac{1}{2} \times 1800 \, \text{N/m} \times (0.15 \, \text{m})^2}{1.20 \, \text{kg} \times 9.81 \, \text{m/s}^2} \]Calculate \(h\): \[ h = \frac{\frac{1}{2} \times 1800 \times 0.0225}{1.20 \times 9.81} = \frac{20.25}{11.772} \approx 1.72 \, \text{m} \]So, the cheese rises approximately 1.72 meters from the initial compressed position.
Key Concepts
Spring Potential EnergyGravitational Potential EnergyKinetic Energy Transformation
Spring Potential Energy
Spring Potential Energy is the energy stored in a spring when it is compressed or stretched. This energy is calculated using the formula \[ PE_{\text{spring}} = \frac{1}{2} k x^2 \]where:
kis the spring constant, which tells us how stiff the spring is. A larger value ofkmeans the spring is stiffer.xis the distance the spring is compressed or stretched from its usual length.
Gravitational Potential Energy
Gravitational Potential Energy (GPE) is the energy an object possesses because of its position in a gravitational field. It's expressed by the formula:\[ PE_g = mgh \]Here:
mstands for the mass of the object.gis the acceleration due to gravity, about9.81 m/s^2on Earth.his the height above the reference point, such as the ground.
Kinetic Energy Transformation
Kinetic Energy is the energy of motion. When an object is moving, it has kinetic energy, calculated by the formula:\[ KE = \frac{1}{2} mv^2 \]where:
mindicates the mass of the object.vis the velocity of the object.
Other exercises in this chapter
Problem 18
A slingshot will shoot a \(10-8\) pebble 220 \(\mathrm{m}\) straight up. (a) How much potential energy is stored in the slingshot's rubber band? (b) With the sa
View solution Problem 19
A spring of negligible mass has force constant \(k=\) 1600 \(\mathrm{N} / \mathrm{m}\) . (a) How far must the spring be compressed for 3.20 \(\mathrm{J}\) of po
View solution Problem 23
A 2.50 -kg mass is pushed against a horizontal spring of force constant 25.0 \(\mathrm{N} / \mathrm{cm}\) on a frictionless air table. The spring is attached to
View solution Problem 25
You are asked to design a spring that will give a \(1160-\mathrm{kg}\) satellite a speed of 2.50 \(\mathrm{m} / \mathrm{s}\) relative to an orbiting space shutt
View solution