Problem 20
Question
15–26 Use an appropriate half-angle formula to find the exact value of the expression. $$\cos 112.5^{\circ}$$
Step-by-Step Solution
Verified Answer
\( \cos 112.5^{\circ} = -\frac{\sqrt{2 - \sqrt{2}}}{2} \).
1Step 1: Identify Half-Angle Formula for Cosine
The half-angle formula for cosine is \( \cos\left(\frac{x}{2}\right) = \pm \sqrt{\frac{1 + \cos x}{2}} \). We will use this formula to find \( \cos 112.5^{\circ} \).
2Step 2: Find Double Angle
Since \( 112.5^{\circ} \) is half of \( 225^{\circ} \), set \( x = 225^{\circ} \). This choice lets us use the half-angle formula with \( x \).
3Step 3: Calculate \( \cos 225^{\circ} \)
The cosine of \( 225^{\circ} \) can be calculated as it is in the third quadrant where both sine and cosine are negative. Therefore, \( \cos 225^{\circ} = -\frac{\sqrt{2}}{2} \).
4Step 4: Plug into Half-Angle Formula
Substitute \( \cos 225^{\circ} = -\frac{\sqrt{2}}{2} \) into the half-angle formula: \( \cos 112.5^{\circ} = \pm \sqrt{\frac{1 + (-\frac{\sqrt{2}}{2})}{2}} \).
5Step 5: Simplify the Expression
Simplify the expression: \( \cos 112.5^{\circ} = \pm \sqrt{\frac{2}{2} - \frac{\sqrt{2}}{2}}{2} = \frac{2 - \sqrt{2}}{4} \), giving \( \cos 112.5^{\circ} = \pm \sqrt{\frac{2 - \sqrt{2}}{4}} \).
6Step 6: Determine the Correct Sign
Since \( 112.5^{\circ} \) is in the second quadrant where cosine is negative, \( \cos 112.5^{\circ} = -\sqrt{\frac{2 - \sqrt{2}}{4}} \).
7Step 7: Complete the Simplification
Simplifying further, \( \cos 112.5^{\circ} = -\frac{\sqrt{2 - \sqrt{2}}}{2} \).
Key Concepts
Cosine FunctionTrigonometric IdentitiesExact Trigonometric Values
Cosine Function
The cosine function is one of the fundamental functions in trigonometry, used to describe the relationship between the angles and sides of a right triangle. It is especially helpful when working with circular motion and oscillations. The cosine of an angle in a right triangle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse. This means that for any angle \( \theta \), \( \cos \theta = \frac{\text{adjacent side}}{\text{hypotenuse}} \).
Cosine function values vary from -1 to 1, depending on the angle. Additionally, the cosine function is periodic with a period of \(360^{\circ}\) or \(2\pi\) radians. This periodic nature makes it valuable in modeling situations that repeat at regular intervals.
A unique feature of the cosine function is its symmetry. It is an even function, meaning \( \cos(\theta) = \cos(-\theta) \). This characteristic helps in simplifying calculations in trigonometry.
Cosine function values vary from -1 to 1, depending on the angle. Additionally, the cosine function is periodic with a period of \(360^{\circ}\) or \(2\pi\) radians. This periodic nature makes it valuable in modeling situations that repeat at regular intervals.
A unique feature of the cosine function is its symmetry. It is an even function, meaning \( \cos(\theta) = \cos(-\theta) \). This characteristic helps in simplifying calculations in trigonometry.
Trigonometric Identities
Trigonometric identities are equations that relate the trigonometric functions to one another. They are useful tools for simplifying expressions and solving trigonometric equations.
Some of the most common trigonometric identities include:
Some of the most common trigonometric identities include:
- Pythagorean Identity: \( \sin^2\theta + \cos^2\theta = 1 \)
- Reciprocal Identities: \( \sin \theta = \frac{1}{\csc \theta} \), \( \cos \theta = \frac{1}{\sec \theta} \), \( \tan \theta = \frac{1}{\cot \theta} \)
- Sum and Difference Formulas:
\( \cos(a \pm b) = \cos a \cos b \mp \sin a \sin b \)\ - Double Angle and Half Angle: \( \cos\left(\frac{x}{2}\right) = \pm \sqrt{\frac{1 + \cos x}{2}} \)
Exact Trigonometric Values
Finding exact trigonometric values refers to the process of determining precise values, rather than approximations, for trigonometric functions at specific angles. These angles are usually multiples of \(30^{\circ}\), \(45^{\circ}\), or \(60^{\circ}\), for which values are typically memorized or derived quickly.
In our exercise, we calculated \( \cos 112.5^{\circ} \) using exact trigonometric steps:
In our exercise, we calculated \( \cos 112.5^{\circ} \) using exact trigonometric steps:
- Recognized \( 112.5^{\circ} = \frac{225^{\circ}}{2} \)
- Calculated \( \cos 225^{\circ} = -\frac{\sqrt{2}}{2} \)
- Applied the half-angle formula \( \cos\left(\frac{225^{\circ}}{2}\right) \)
- Simplified to find \( \cos 112.5^{\circ} = -\frac{\sqrt{2 - \sqrt{2}}}{2} \)
Other exercises in this chapter
Problem 20
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Simplify the trigonometric expression. $$ \frac{2+\tan ^{2} x}{\sec ^{2} x}-1 $$
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Find the exact value of the expression, if it is defined. \(\tan ^{-1}\left(\tan \frac{2 \pi}{3}\right)\)
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