Problem 20
Question
\(15-20\) : Use properties of real numbers to write the expression without parentheses. $$ (3 a)(b+c-2 d) $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(3ab + 3ac - 6ad\).
1Step 1: Expand the Expression
Apply the distributive property, which states that \((x)(y+z) = (x)(y) + (x)(z)\), to remove the parentheses. Distribute \(3a\) to each term inside the parentheses: \((3a)(b) + (3a)(c) - (3a)(2d)\).
2Step 2: Simplify the Terms
Multiply the terms. So, we multiply each term by \(3a\):\(3ab + 3ac - 6ad\).
3Step 3: Final Simplified Expression
Thus, the expression without parentheses becomes \(3ab + 3ac - 6ad\).
Key Concepts
Distributive PropertyAlgebraic ExpressionsExpression Simplification
Distributive Property
The distributive property is a fundamental principle in algebra that helps in simplifying expressions with parentheses. It states that when you multiply a number by a sum or a difference, you can distribute the multiplication across each term inside the parentheses. In mathematical terms, it can be expressed as
For example, if you have an expression like \((3a)(b+c-2d)\), according to the distributive property, you will first multiply \(3a\) with \(b\), then \(3a\) with \(c\), and finally \(3a\) with \(-2d\). This results in the expression \(3ab + 3ac - 6ad\).
Understanding this property is crucial because it allows you to simplify expressions into more manageable terms without parentheses.
- \((x)(y + z) = (x)(y) + (x)(z)\).
For example, if you have an expression like \((3a)(b+c-2d)\), according to the distributive property, you will first multiply \(3a\) with \(b\), then \(3a\) with \(c\), and finally \(3a\) with \(-2d\). This results in the expression \(3ab + 3ac - 6ad\).
Understanding this property is crucial because it allows you to simplify expressions into more manageable terms without parentheses.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and mathematical operations. They are used to represent values and relationships in a concise way. For example:
When working with algebraic expressions, it is important to follow the order of operations for accurate solution. In expressions involving parentheses, the operations inside the parentheses are performed first, unless dictated otherwise by the problem.
- Numbers: 5, -2, 3/4
- Variables: \(x\), \(y\), \(z\)
- Operations: addition (+), subtraction (−), multiplication (×), division (÷)
When working with algebraic expressions, it is important to follow the order of operations for accurate solution. In expressions involving parentheses, the operations inside the parentheses are performed first, unless dictated otherwise by the problem.
Expression Simplification
Expression simplification involves reducing an algebraic expression into its most basic, easily understandable form. This often includes distributing, combining like terms, and rewriting expressions to eliminate any unnecessary complexity.
For our exercise \((3a)(b+c-2d)\), simplification involves applying the distributive property: first, we distribute \(3a\) across the terms in the parentheses, resulting in \((3a)(b) + (3a)(c) - (3a)(2d)\), which translates to \(3ab + 3ac - 6ad\).
The goal of simplifying an expression is to present it in a way that's easier to work with or understand, without changing the expression's value. Simplification can make complex algebraic expressions more manageable and is essential for solving problems effectively.
For our exercise \((3a)(b+c-2d)\), simplification involves applying the distributive property: first, we distribute \(3a\) across the terms in the parentheses, resulting in \((3a)(b) + (3a)(c) - (3a)(2d)\), which translates to \(3ab + 3ac - 6ad\).
The goal of simplifying an expression is to present it in a way that's easier to work with or understand, without changing the expression's value. Simplification can make complex algebraic expressions more manageable and is essential for solving problems effectively.
Other exercises in this chapter
Problem 20
Evaluate the expression using \(x=3, y=4,\) and \(z=-1\). \(\sqrt[4]{x^{3}+14 y+2 z}\)
View solution Problem 20
Write an algebraic formula for the given quantity.. The distance \(d\) in miles that a car travels in \(t\) hours at a speed of \(r\) miles per hour
View solution Problem 21
Evaluate each expression. $$ 2^{-2}+2^{-3} $$
View solution Problem 21
\(21-34\) . Perform the multiplication or division and simplify. $$ \frac{4 x}{x^{2}-4} \cdot \frac{x+2}{16 x} $$
View solution