Problem 2
Question
Which of these ions is coloured as well as paramagnetic in nature? (a) \(\mathrm{Cu}^{2+}\) (b) \(\mathrm{Cu}^{+}\) (c) \(\mathrm{Nl}^{2+}\) (d) Both a and c
Step-by-Step Solution
Verified Answer
(d) Both a and c (7Cu^{2+} and 7Ni^{2+})
1Step 1: Understanding Paramagnetism
Paramagnetism occurs when an ion has unpaired electrons in its d-orbitals. These unpaired electrons have magnetic moments that add up to create a net magnetic moment, making the ion paramagnetic.
2Step 2: Understanding Ion Coloration
Ions absorb specific wavelengths of light due to electronic transitions between d-orbitals, which creates colors. The ions with partially filled d-orbitals can show colors due to these d-d transitions.
3Step 3: Analyzing 7Cu^{2+} Ion
The 7Cu^{2+} ion has the electron configuration [Ar]3d^9. With one unpaired electron in the d-orbital, it is paramagnetic and can show color because of d-d transitions.
4Step 4: Analyzing 7Cu^{+} Ion
The 7Cu^{+} ion has the electron configuration [Ar]3d^{10}. With a fully filled d-orbital, it is not paramagnetic and ordinarily appears colorless since d-d transitions are not possible.
5Step 5: Analyzing 7Ni^{2+} Ion
The 7Ni^{2+} ion has the electron configuration [Ar]3d^8. It has two unpaired electrons and is paramagnetic. It shows colors due to possible d-d transitions in its partially filled d-orbitals.
6Step 6: Conclusion
Both 7Cu^{2+} and 7Ni^{2+} are paramagnetic and colored. Therefore, both exhibit these properties.
Key Concepts
Ion Paramagnetismd-d TransitionsElectron Configuration
Ion Paramagnetism
Paramagnetism in ions is a fascinating concept in transition metal chemistry.
It arises when ions have unpaired electrons in their electronic orbitals, specifically in their d-orbitals for transition metals. These unpaired electrons act as tiny magnets themselves, creating a net magnetic moment for the ion.
In simple terms, the more unpaired electrons an ion has, the stronger its paramagnetic properties.
In the context of the exercise, ions such as
It arises when ions have unpaired electrons in their electronic orbitals, specifically in their d-orbitals for transition metals. These unpaired electrons act as tiny magnets themselves, creating a net magnetic moment for the ion.
In simple terms, the more unpaired electrons an ion has, the stronger its paramagnetic properties.
In the context of the exercise, ions such as
- **\( \mathrm{Cu}^{2+} \) with a configuration of [Ar]3d\(^9\)** has one unpaired electron,
- **\( \mathrm{Ni}^{2+} \) with [Ar]3d\(^8\)** has two unpaired electrons.
d-d Transitions
The term "d-d transitions" describes an electron's movement between d-orbitals of different energy levels.
This phenomenon occurs in transition metal compounds where d-orbitals split into different energy levels due to the presence of ligands. When an electron jumps from one d-orbital to another, it absorbs light energy.
The specific wavelength of this absorbed light is missing from the reflected light, and the color is perceived as the complementary color of the absorbed wavelength. This is why many transition metal ions appear colored.
For example, in the exercise,
This phenomenon occurs in transition metal compounds where d-orbitals split into different energy levels due to the presence of ligands. When an electron jumps from one d-orbital to another, it absorbs light energy.
The specific wavelength of this absorbed light is missing from the reflected light, and the color is perceived as the complementary color of the absorbed wavelength. This is why many transition metal ions appear colored.
For example, in the exercise,
- **\( \mathrm{Cu}^{2+} \)** ion's electron configuration [Ar]3d\(^9\) allows d-d transitions, imparting color.
- Similarly, **\( \mathrm{Ni}^{2+} \)** with its electron configuration [Ar]3d\(^8\) experiences d-d transitions, providing color.
Electron Configuration
Electron configuration is a crucial concept in understanding the behavior of ions.
It denotes the distribution of electrons into various orbitals around an atom's nucleus. For transition metals, focus is often on their d-orbitals, as the arrangement of electrons here influences an ion’s properties.
The arrangement of electrons in these orbitals determines paramagnetism, coloration, and other chemical behaviors.For transition metal ions, the electron configuration is derived by removing electrons first from the s-orbital and then the d-orbitals during ion formation.
It denotes the distribution of electrons into various orbitals around an atom's nucleus. For transition metals, focus is often on their d-orbitals, as the arrangement of electrons here influences an ion’s properties.
The arrangement of electrons in these orbitals determines paramagnetism, coloration, and other chemical behaviors.For transition metal ions, the electron configuration is derived by removing electrons first from the s-orbital and then the d-orbitals during ion formation.
- Understanding the electron configurations of ions like**\( \mathrm{Cu}^{2+} \) ([Ar]3d\(^9\))** and **\( \mathrm{Ni}^{2+} \) ([Ar]3d\(^8\))** helps identify their paramagnetic nature and color.
- In contrast, **\( \mathrm{Cu}^{+} \)** with configuration [Ar]3d\(^{10}\) is significant as it does not exhibit paramagnetism or typical coloration due to absence of unpaired electrons and d-d transitions.
Other exercises in this chapter
Problem 1
Among which of the following pairs of ions, the lower oxidation state in aqueous solution is more stable than the other? (a) \(\mathrm{Ti}^{+}, \mathrm{Ti}^{3+}
View solution Problem 3
The aqueous solution containing which one of the following ions will be colourless? (a) \(\mathrm{Sc}^{3+}\) (b) \(\mathrm{Fe}^{3+}\) (c) \(\mathrm{Fe}^{2+}\) (
View solution Problem 4
Which of the following is a highly corrosive salt? (a) \(\mathrm{FeCl}_{2}\) (b) \(\mathrm{HgCl}_{2}\) (c) \(\mathrm{PbCl}_{2}\) (d) \(\mathrm{Hg}_{2} \mathrm{C
View solution Problem 5
A complex compound of \(\mathrm{Co}^{3+}\) with molecular formula \(\mathrm{CoCl}_{\mathrm{x}} \cdot \mathrm{yNH}_{3}\) gives a total of 3 ions when dissolved i
View solution