Problem 2
Question
Which fields are conservative, and which are not? \(\mathbf{F}=(y \sin z) \mathbf{i}+(x \sin z) \mathbf{j}+(x y \cos z) \mathbf{k}\)
Step-by-Step Solution
Verified Answer
The field is conservative as its curl is zero.
1Step 1: Understand the Concept
A vector field is conservative if there exists a scalar potential function, \(\), such that \(abla = extbf{F}\). This means the curl of a conservative vector field is zero. We will verify if the field \(\mathbf{F} = (y \sin z) \mathbf{i} + (x \sin z) \mathbf{j} + (xy \cos z) \mathbf{k}\) is conservative by calculating its curl.
2Step 2: Write the Formula for the Curl
The formula for the curl of a vector field \(\mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k}\) is given by \(abla \times \mathbf{F} = \left(\frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}\right) \mathbf{i} + \left(\frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}\right) \mathbf{j} + \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) \mathbf{k}\).
3Step 3: Calculate Partial Derivatives
For \(\mathbf{F} = (y \sin z) \mathbf{i} + (x \sin z) \mathbf{j} + (xy \cos z) \mathbf{k}\):- \(\frac{\partial R}{\partial y} = \frac{\partial}{\partial y}(xy \cos z) = x \cos z\)- \(\frac{\partial Q}{\partial z} = \frac{\partial}{\partial z}(x \sin z) = x \cos z\)- \(\frac{\partial P}{\partial z} = \frac{\partial}{\partial z}(y \sin z) = y \cos z\)- \(\frac{\partial R}{\partial x} = \frac{\partial}{\partial x}(xy \cos z) = y \cos z\)- \(\frac{\partial Q}{\partial x} = \frac{\partial}{\partial x}(x \sin z) = \sin z\)- \(\frac{\partial P}{\partial y} = \frac{\partial}{\partial y}(y \sin z) = \sin z\)
4Step 4: Compute the Curl
Now plug in the partial derivatives into the curl formula:\(abla \times \mathbf{F} = \left(x \cos z - x \cos z\right) \mathbf{i} + \left(y \cos z - y \cos z\right) \mathbf{j} + \left(\sin z - \sin z\right) \mathbf{k}\)This simplifies to \(abla \times \mathbf{F} = 0 \mathbf{i} + 0 \mathbf{j} + 0 \mathbf{k}\).
Key Concepts
Curl of a Vector FieldScalar Potential FunctionPartial Derivatives
Curl of a Vector Field
The curl of a vector field is a concept that helps us determine whether a vector field is conservative. If you imagine a vector field having arrows, representing directions and magnitudes, the curl describes the tendency of these arrows to rotate around a point. It's like observing a whirlpool and measuring how the water spins.
To calculate the curl of a vector field \(\mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k}\), use the formula for curl given by:
To calculate the curl of a vector field \(\mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k}\), use the formula for curl given by:
- \(abla \times \mathbf{F} = \left(\frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}\right) \mathbf{i}\)
- \( + \left(\frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}\right) \mathbf{j} + \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) \mathbf{k} \)
Scalar Potential Function
When dealing with conservative vector fields, one of the key concepts is the scalar potential function, often called simply the potential function. This function is like a hidden layer underlying the vector field. It represents a kind of 'gravity' or 'energy' landscape from which the vector field derives direction and magnitude.
If you can find a scalar potential function \(\phi\) such that its gradient equals the vector field \(\mathbf{F} \), then \(\mathbf{F}\) is conservative. Mathematically, this is described by:
If you can find a scalar potential function \(\phi\) such that its gradient equals the vector field \(\mathbf{F} \), then \(\mathbf{F}\) is conservative. Mathematically, this is described by:
- \(abla \phi = \mathbf{F}\)
Partial Derivatives
Partial derivatives play a crucial role in not only understanding vector fields but in many areas of calculus and physics. They measure how a function changes as only one of the input variables is modified, keeping the others constant. Think of partial derivatives as looking at the slope, or the rate of change, of a function along one axis at a time.
For a vector field \(\mathbf{F}\), when computing the curl or checking for a scalar potential function, we often need to calculate several partial derivatives. For example, in the vector field \(\mathbf{F} = (y \sin z) \mathbf{i} + (x \sin z) \mathbf{j} + (xy \cos z) \mathbf{k}\), we calculate partial derivatives like \(\frac{\partial R}{\partial y}\) or \(\frac{\partial Q}{\partial x}\). Each of these derivatives helps us understand a specific detail about how the vector field behaves along a particular direction or dimension.
For a vector field \(\mathbf{F}\), when computing the curl or checking for a scalar potential function, we often need to calculate several partial derivatives. For example, in the vector field \(\mathbf{F} = (y \sin z) \mathbf{i} + (x \sin z) \mathbf{j} + (xy \cos z) \mathbf{k}\), we calculate partial derivatives like \(\frac{\partial R}{\partial y}\) or \(\frac{\partial Q}{\partial x}\). Each of these derivatives helps us understand a specific detail about how the vector field behaves along a particular direction or dimension.
- It's important to be careful with signs and terms since they affect the overall computation of curl.
- Partial derivatives are central in the formulas that determine if a vector field is conservative.
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