Problem 2
Question
When we solve a quadratic equation, how many solutions should we always start out seeking? Explain why when solving a quadratic equation in the form \(a x^{2}+b x+c=0\) we may graph the equation \(y=a x^{2}+b x+c\) and have no zeroes ( \(x\) -intercepts).
Step-by-Step Solution
Verified Answer
A quadratic can have 0, 1, or 2 solutions. No x-intercepts occur if \(b^2 - 4ac < 0\).
1Step 1: Understanding the Problem
We are tasked with determining how many solutions a quadratic equation can have and explaining under what conditions it may have no real solutions. The problem specifically asks us to consider the quadratic equation in the form \( ax^2 + bx + c = 0 \) and relate it to its graph \( y = ax^2 + bx + c \).
2Step 2: Determine the Number of Solutions for Quadratics
A quadratic equation \( ax^2 + bx + c = 0 \) can have either two real solutions, one real solution, or no real solutions, this is determined by the discriminant \( b^2 - 4ac \). We start by seeking two solutions because the highest degree (2) indicates up to two solutions are possible. Solutions appear where the graph intersects the x-axis.
3Step 3: Explain Zero x-intercepts Possibility
If the discriminant \( b^2 - 4ac \) is negative, there are no real roots, meaning the graph \( y = ax^2 + bx + c \) does not intersect the x-axis. Therefore, there are no x-intercepts or zero points, and the quadratic equation has no real solutions. This scenario corresponds to the parabola being entirely above or below the x-axis depending on the leading coefficient \( a \).
Key Concepts
DiscriminantReal SolutionsX-Intercepts
Discriminant
The discriminant is a key concept when solving quadratic equations. It is represented by the expression \( b^2 - 4ac \). To understand its purpose, consider it as a tool that tells us about the nature of the solutions of the quadratic equation \( ax^2 + bx + c = 0 \).
Here's why the discriminant is so important:
Here's why the discriminant is so important:
- If the discriminant is positive (greater than zero), the quadratic equation has two distinct real solutions.
- If the discriminant equals zero, it means there is exactly one real solution, or more specifically, the two solutions are identical (also known as a "double root").
- If the discriminant is negative, the equation has no real solutions. This situation is explained further in terms of graph intersections later on.
Real Solutions
Real solutions to a quadratic equation are the points where the parabola intersects the x-axis. These are the solutions that we can see on a graph as the points where \( y \) (or the output of the equation) equals zero. Finding these solutions gives us the x-values (solutions) for which the equation \( ax^2 + bx + c = 0 \) holds true.
When we calculate the solutions:
When we calculate the solutions:
- We get **two real solutions** when the discriminant is positive, meaning the parabola crosses the x-axis at two different points.
- We have **one real solution** when the discriminant is zero, indicating the parabola touches the x-axis at just one point.
- We have **no real solutions** when the discriminant is negative, suggesting that the parabola does not touch or intersect the x-axis at all.
X-Intercepts
X-intercepts are where the function \( y = ax^2 + bx + c \) crosses the x-axis. This is essentially when the quadratic equation is "equal to zero."
Understanding x-intercepts is straightforward with these pointers:
Understanding x-intercepts is straightforward with these pointers:
- The x-intercepts correspond to the real solutions of the quadratic equation \( ax^2 + bx + c = 0 \).
- If the discriminant is positive, there will be two x-intercepts, since the parabola crosses the x-axis twice.
- If the discriminant is zero, there will be one x-intercept, indicating the vertex of the parabola touches the x-axis.
- With a negative discriminant, there are no x-intercepts, as the parabola remains entirely above or below the x-axis, depending on the leading coefficient \( a \).
Other exercises in this chapter
Problem 2
When solving an inequality, we arrive at: $$\begin{array}{c} x+2
View solution Problem 2
Explain why possible solutions must be checked in radical equations.
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What is the basic principle in multiplication of complex numbers?
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Use your own words to describe this equation where \(n\) is a number: \(5(n+3)=2 n\).
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