Problem 2
Question
Use the Second Fundamental Theorem of Calculus to evaluate each definite integral. $$ \int_{-1}^{2} x^{4} d x $$
Step-by-Step Solution
Verified Answer
The value of the definite integral is \( \frac{33}{5} \).
1Step 1: Identify the Antiderivative
According to the Second Fundamental Theorem of Calculus, to evaluate \( \int_{a}^{b} f(x) \, dx \), we first need to find an antiderivative \( F(x) \) of \( f(x) = x^4 \). The antiderivative of \( x^4 \) is \( F(x) = \frac{x^5}{5} \).
2Step 2: Apply the Antiderivative to the Limits
After finding the antiderivative, substitute the upper and lower limits into the antiderivative. Here, we calculate \( F(2) \) and \( F(-1) \):- \( F(2) = \frac{2^5}{5} = \frac{32}{5} \)- \( F(-1) = \frac{(-1)^5}{5} = -\frac{1}{5} \)
3Step 3: Compute the Definite Integral
Subtract \( F(-1) \) from \( F(2) \) to find the value of the definite integral:\[ \int_{-1}^{2} x^{4} \, dx = F(2) - F(-1) = \frac{32}{5} - \left(-\frac{1}{5}\right) \]Simplify this to get:\[ \frac{32}{5} + \frac{1}{5} = \frac{33}{5} \]
Key Concepts
Definite IntegralAntiderivativePower Rule
Definite Integral
A definite integral is a fundamental concept in calculus that represents the signed area under a curve defined by a function, over a specific interval from \( a \) to \( b \). This is different from an indefinite integral, which refers to the general antiderivative of a function without specific bounds.
When solving a definite integral like \( \int_{-1}^{2} x^{4} \, dx \), you're essentially finding the net area between the curve and the x-axis, from \( x = -1 \) to \( x = 2 \).
This calculation involves:
When solving a definite integral like \( \int_{-1}^{2} x^{4} \, dx \), you're essentially finding the net area between the curve and the x-axis, from \( x = -1 \) to \( x = 2 \).
This calculation involves:
- Finding the Antiderivative: Determine the antiderivative (or original function) of the integrand.
- Evaluating the Antiderivative: Substitute the upper and lower limits into this antiderivative.
- Subtracting Values: Subtract the value of the antiderivative at the lower limit from its value at the upper limit.
Antiderivative
The antiderivative, or primitive, of a function is a function whose derivative is the original function. To find an antiderivative, you're essentially reversing the process of differentiation.
In the exercise, to solve \( \int_{-1}^{2} x^{4} \), we look for a function \( F(x) \) such that \( F'(x) = x^4 \).
The antiderivative of \( x^4 \) turns out to be \( F(x) = \frac{x^5}{5} \).
In the exercise, to solve \( \int_{-1}^{2} x^{4} \), we look for a function \( F(x) \) such that \( F'(x) = x^4 \).
The antiderivative of \( x^4 \) turns out to be \( F(x) = \frac{x^5}{5} \).
- This antiderivative is found using integration rules that reverse the power rule of differentiation.
- It's crucial to ensure that the antiderivative is correctly derived, which can be confirmed by differentiating \( F(x) \) and checking it equals the original function \( x^4 \).
Power Rule
The power rule is a basic tool in calculus used for differentiation and integration. For integration, it helps find antiderivatives of power functions.
For any function \( x^n \), the power rule for integration is expressed as:
For any function \( x^n \), the power rule for integration is expressed as:
- \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \)
- Here, \( n \) is any real number except \( -1 \), and \( C \) is the constant of integration for indefinite integrals.
- Increases the exponent \( 4 \) by one to get \( 5 \).
- Divides by the new exponent, giving the antiderivative \( \frac{x^5}{5} \).
Other exercises in this chapter
Problem 2
Evaluate the indicated integrals. $$ \int_{1}^{2} \frac{2 x^{4}-3 x^{2}+1}{x^{2}} d x $$
View solution Problem 2
Find the value of the indicated sum. \(\sum_{i=1}^{6} i^{2}\)
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In Problems \(1-6,\) use the methods of (1) left Riemann sum, (2) right Riemann sum, (3) Trapezoidal Rule, (4) Parabolic Rule with \(n=8\) to approximate the de
View solution Problem 3
Evaluate the indicated integrals. $$ \int_{1}^{\pi} \frac{y^{3}-9 y \sin y+26 y^{-1}}{y} d y $$
View solution