Problem 2
Question
Use log \(_{3} 2 \approx 0.6309\) and \(\log _{3} 7 \approx 1.7712\) to approximate the value of each expression. \(\log _{3} 14\)
Step-by-Step Solution
Verified Answer
The approximate value of \( \log_{3} 14 \) is 2.4021.
1Step 1: Express the Logarithm in Terms of Known Logs
Given the expression \( \log_{3} 14 \), we recognize that 14 can be written as the product of 2 and 7. Therefore, we can use the logarithmic property \( \log_{b}(xy) = \log_{b}(x) + \log_{b}(y) \). Thus, \( \log_{3} 14 = \log_{3}(2 \times 7) = \log_{3} 2 + \log_{3} 7 \).
2Step 2: Substitute Known Values
We substitute the given approximate values into the expression: \( \log_{3} 2 + \log_{3} 7 = 0.6309 + 1.7712 \).
3Step 3: Perform the Addition
Add the two approximate values together. \( 0.6309 + 1.7712 = 2.4021 \). This is the approximate value of \( \log_{3} 14 \).
Key Concepts
Properties of LogarithmsApproximating Logarithmic ValuesLogarithmic Calculations
Properties of Logarithms
Understanding the properties of logarithms is essential for simplifying and solving various mathematical problems. One of the fundamental properties is the product rule for logarithms, which states that the logarithm of a product is the sum of the logarithms of the factors. Mathematically, this is expressed as:
Besides the product rule, there are other important properties of logarithms:
- \( \log_{b}(xy) = \log_{b}(x) + \log_{b}(y) \)
Besides the product rule, there are other important properties of logarithms:
- Quotient Rule: \( \log_{b}(x/y) = \log_{b}(x) - \log_{b}(y) \)
- Power Rule: \( \log_{b}(x^{n}) = n \cdot \log_{b}(x) \)
- Change of Base: \( \log_{a}(x) = \frac{\log_{b}(x)}{\log_{b}(a)} \)
Approximating Logarithmic Values
There are instances where exact logarithmic values are difficult to compute, especially without a calculator. In such cases, approximating logarithmic values using known values and properties becomes helpful. For example, if we know \( \log_{3} 2 \approx 0.6309 \) and \( \log_{3} 7 \approx 1.7712 \), we can use these values to find the approximate logarithm of numbers that can be expressed in terms of 2 and 7.
Using the product property, \( \log_{3} 14 = \log_{3} (2 \times 7) \), we substitute the approximate values into the expression:
Using the product property, \( \log_{3} 14 = \log_{3} (2 \times 7) \), we substitute the approximate values into the expression:
- Calculate \( \log_{3} 2 + \log_{3} 7 = 0.6309 + 1.7712 \)
Logarithmic Calculations
Logarithmic calculations involve manipulating expressions using logarithm properties to achieve a simplified form or find an unknown value. Often, these calculations are facilitated by approximate values when precise values aren’t known or practical to compute. Let's consider the example of calculating \( \log_{3} 14 \):
In the solution, we utilized the known approximate logarithmic values of 2 and 7. By applying the product property, the calculation of \( \log_{3} (2 \times 7) \) transformed into a simple addition problem of two approximations:
In the solution, we utilized the known approximate logarithmic values of 2 and 7. By applying the product property, the calculation of \( \log_{3} (2 \times 7) \) transformed into a simple addition problem of two approximations:
- Calculation: \( 0.6309 + 1.7712 = 2.4021 \)
Other exercises in this chapter
Problem 2
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Use a calculator to evaluate each expression to four decimal places. \(e^{-3.4}\)
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Write each equation in logarithmic form. \(7^{-2}=\frac{1}{49}\)
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For Exercises \(2-4,\) use the following information. A radioisotope is used as a power source for a satellite. The power output \(P\) (in watts) is given by \(
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