Problem 2
Question
Use a calculator to find each common logarithm. Express answers to four decimal places. $$ \log 2.05 $$
Step-by-Step Solution
Verified Answer
The common logarithm of 2.05 is 0.3118.
1Step 1: Understand the Common Logarithm
The common logarithm is the logarithm to base 10. When the exercise asks for \( \log 2.05 \), it is requesting the logarithm base 10 of 2.05.
2Step 2: Use Calculator to Compute the Logarithm
Enter 2.05 into your calculator and press the 'log' button to find \( \log 2.05 \). Most scientific calculators have a dedicated button for common logarithms.
3Step 3: Record the Answer
Ensure your calculator is set to display results to four decimal places. After computing, \( \log 2.05 \) returns approximately 0.3118.
Key Concepts
Logarithm Base 10Use of Calculator in MathDecimal Places in Calculations
Logarithm Base 10
The logarithm base 10, often referred to as a common logarithm, is a convenient way of expressing how many times 10 must be multiplied by itself to reach a specific number. In mathematics, this is written using the expression \( \log_{10}(x) \) or simply \( \log(x) \). For instance, if you encounter \( \log 2.05 \), it means you're determining the power to which 10 must be raised to result in 2.05.
Common logarithms are especially prevalent in science and engineering because they simplify complex multiplications into simple additions. If you're dealing with large numbers or tiny fractions, the common logarithm compresses this complexity, making it easier to manage.
To visualize: if \( \log 100 = 2 \), it means 10 multiplied by itself 2 times equals 100. Understanding this concept is essential for solving logarithmic exercises, such as the one asking you to evaluate \( \log 2.05 \).
Common logarithms are especially prevalent in science and engineering because they simplify complex multiplications into simple additions. If you're dealing with large numbers or tiny fractions, the common logarithm compresses this complexity, making it easier to manage.
To visualize: if \( \log 100 = 2 \), it means 10 multiplied by itself 2 times equals 100. Understanding this concept is essential for solving logarithmic exercises, such as the one asking you to evaluate \( \log 2.05 \).
Use of Calculator in Math
Calculators are invaluable tools in modern mathematics, especially when dealing with complex functions like logarithms. By using a scientific calculator, you can easily compute the logarithm base 10, such as \( \log 2.05 \).
Here's how you can efficiently use the calculator for finding common logarithms:
Here's how you can efficiently use the calculator for finding common logarithms:
- Ensure your calculator is in standard mode, ready for basic operations.
- Input the number for which you need the logarithm. For our exercise, this is 2.05.
- Locate the 'log' button. It's typically labeled clearly on the calculator.
- Press the 'log' button after entering the number.
Decimal Places in Calculations
Understanding how to round and display results accurately is crucial to math exercises like calculating logarithms. Decimal places refer to the number of digits shown after the decimal point in a number. In many exercises, you're asked to express the answer to a certain number of decimal places for precision.
In our logarithmic example, we're tasked to express \( \log 2.05 \) to four decimal places. This means rounding the result to the fourth digit after the decimal point. When rounding:
In our logarithmic example, we're tasked to express \( \log 2.05 \) to four decimal places. This means rounding the result to the fourth digit after the decimal point. When rounding:
- Identify the fourth decimal digit following the decimal point in your answer.
- Check the digit right after the fourth one: if it's 5 or greater, round up the fourth digit by one. Otherwise, keep it as is.
Other exercises in this chapter
Problem 1
Solve each of the equations. $$ 2^{x}=64 $$
View solution Problem 2
Solve each exponential equation and express approximate solutions to the nearest hundredth. $$ 2^{x}=21 $$
View solution Problem 2
Suppose it is estimated that the value of a car depreciates \(30 \%\) per year for the first 5 years. The equation \(A=P_{0}(0.7)^{t}\) yields the value \((A)\)
View solution Problem 2
Solve each of the equations. $$ 3^{x}=81 $$
View solution