Problem 2
Question
Translate the following into algebraic equations. When 12 is subtracted from twice some number the result is \(6 .\)
Step-by-Step Solution
Verified Answer
The equation is \( 2x - 12 = 6 \).
1Step 1: Determine the Variable
Let's represent the unknown number with a variable. We will choose \( x \) to be this variable.
2Step 2: Translate 'Twice Some Number'
The phrase 'twice some number' suggests doubling the unknown number. In algebraic terms, this can be represented as \( 2x \).
3Step 3: Translate '12 is Subtracted from'
The phrase 'when 12 is subtracted from' means we subtract 12 from a previous expression. So, from \( 2x \), we subtract 12, which gives us the expression \( 2x - 12 \).
4Step 4: Express the Result
The result of subtracting 12 from twice the number is given as 6. Therefore, we equate the expression to 6: \( 2x - 12 = 6 \).
5Step 5: Verification
Check that each part of the sentence is correctly translated into the expression. Twice the number is \( 2x \), subtracting 12 gives \( 2x - 12 \), and the result is indeed 6, leading to the equation \( 2x - 12 = 6 \).
Key Concepts
Algebraic EquationsVariable RepresentationSolving EquationsAlgebraic Translation Steps
Algebraic Equations
Algebraic equations form the backbone of algebra, providing a way to express relationships and solve problems involving unknown values. They consist of two expressions set equal to each other, often depicted using variables to represent unknown quantities. In the given exercise, the algebraic equation represents the problem as it states that when 12 is subtracted from twice a number, the result equals 6. This relationship is expressed by the equation :
- \( 2x - 12 = 6 \)
Variable Representation
Variable representation is a fundamental aspect of algebra, allowing us to use symbols to represent unknown values. Variables, typically denoted by letters like \( x \), \( y \), or \( z \), stand in for numbers that we aim to find. In our exercise, the variable \( x \) is used to represent 'some number' which is unknown.
Choosing a variable is a simple but crucial first step. It serves as a placeholder that we manipulate to find solutions to equations. This abstraction is what makes algebra powerful; it lets us perform complex calculations on an unknown quantity and solve for it systematically. Through variable representation, we convert word problems into mathematical language which can then be solved using algebraic techniques.
Choosing a variable is a simple but crucial first step. It serves as a placeholder that we manipulate to find solutions to equations. This abstraction is what makes algebra powerful; it lets us perform complex calculations on an unknown quantity and solve for it systematically. Through variable representation, we convert word problems into mathematical language which can then be solved using algebraic techniques.
Solving Equations
Solving equations involves finding the value of the variable that makes the equation true. Once we have an equation, the next step is to solve it. This often involves performing operations that simplify the equation until the variable is isolated.
- Consider our example equation: \( 2x - 12 = 6 \).
- Add 12 to both sides to get \( 2x = 18 \).
- Then divide each side by 2, resulting in \( x = 9 \).
Algebraic Translation Steps
Algebraic translation is the process of converting language-based descriptions into algebraic expressions and equations. It often begins with identifying key phrases and understanding their mathematical equivalents. In translating the exercise to an equation:
This systematic approach allows students to convert word problems to equations effectively. It's a crucial skill for tackling more complex algebraic challenges, enhancing both understanding and analytical abilities.
- 'Twice some number' becomes \( 2x \) by multiplying the variable by 2.
- '12 is subtracted from' is translated by subtracting 12 from \( 2x \).
- 'The result is 6' signifies equating the expression to 6, giving us \( 2x - 12 = 6 \).
This systematic approach allows students to convert word problems to equations effectively. It's a crucial skill for tackling more complex algebraic challenges, enhancing both understanding and analytical abilities.
Other exercises in this chapter
Problem 2
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Multiply. $$ 12(-5 y+1) $$
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