Problem 2
Question
The graph of the equation \(x^{2}=4 p y\) is a parabola with focus \(F\) (____, ____) and directrix \(y=\) _____. So the graph of \(x^{2}=12 y\) is a parabola with focus \(F\) (_____, ____) and directrix y= ____.
Step-by-Step Solution
Verified Answer
Focus: (0, 3), Directrix: y = -3.
1Step 1: Identify the parabola properties
The general equation of a parabola that opens upwards is \(x^2 = 4py\), where \(p\) is the distance from the vertex to the focus and also from the vertex to the directrix. For this equation, the vertex is at the origin \((0,0)\).
2Step 2: Determine the given parameters
You are given \(x^2 = 12y\). In this case, compare it to the standard form \(x^2 = 4py\). Here, \(4p = 12\).
3Step 3: Solve for p
Solve \(4p = 12\) to find \(p\). Divide both sides of the equation by 4: \(p = \frac{12}{4} = 3\).
4Step 4: Locate the focus
The focus of the parabola \(x^2 = 4py\) is at \((0, p)\). Given that \(p = 3\), the focus of the parabola is at \((0, 3)\).
5Step 5: Identify the directrix
The directrix of the parabola \(x^2 = 4py\) is given by the equation \(y = -p\). With \(p = 3\), the directrix is \(y = -3\).
Key Concepts
Focus of a ParabolaDirectrix of a ParabolaProperties of Parabolas
Focus of a Parabola
In geometry, the focus of a parabola is a significant point that is directly related to how the parabola is shaped. For a parabola that opens upwards, like the one given by the equation \(x^2 = 4py\), the focus lies on the vertical axis (y-axis). The precise location of the focus is determined by the parameter \(p\), which represents the distance from the vertex to the focus.
- The general formula for the focus of a parabola opening upwards is \((0, p)\).
- The vertex of the parabola is at the origin \((0, 0)\).
- In the equation \(x^2 = 12y\), comparing it with the standard form \(x^2 = 4py\), \(p\) is determined to be 3.
- Thus, the focus of this parabola is at the point \((0, 3)\).
Directrix of a Parabola
The directrix is another fundamental element of a parabola. It acts as a reference line that helps define the width and orientation of the parabola. While the focus is within the curve, the directrix is outside the curve, opposite the focus. For the equation \(x^2 = 4py\), this line is horizontal.
- The directrix acts as the spread constraint for the parabola.
- The mathematical formula for the directrix of a parabola that opens upwards is \(y = -p\).
- Given \(p = 3\), as calculated from the equation \(x^2 = 12y\), this directrix becomes \(y = -3\).
- The presence of both focus and directrix allows us to define the parabolic curve completely.
Properties of Parabolas
Parabolas have many fascinating properties that make them a widely studied topic in Geometry and Algebra. Not only are they present in mathematical problems, but their applications extend to real-life scenarios, such as satellite dishes and headlights. Understanding the basic properties allows for better comprehension of these applications.
- A parabola is a symmetric curve, and its symmetry axis is the vertical line passing through the vertex.
- The equation of a standard parabola that opens upwards is \(x^2 = 4py\).
- Its geometric structure means that any point on the parabola is the same distance from the focus and the directrix.
- As the value of \(p\) increases, the parabola becomes wider; conversely, a smaller \(p\) results in a more "narrow" shape.
Other exercises in this chapter
Problem 2
The graph of the equation \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) with \(a>0, b>0\) is a hyperbola with _______________ (horizontal/vertical) transverse a
View solution Problem 2
The graphs of \(x^{2}=12 y\) and \((x-3)^{2}=12(y-1)\) are given. Label the focus, directrix, and vertex on each parabola. (Graph cannot copy)
View solution Problem 3
Determine the XY-coordinates of the given point if the coordinate axes are rotated through the indicated angle. $$(1,1), \quad \phi=45^{\circ}$$
View solution Problem 3
The graph of the equation \(\frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1\) with \(a>b>0\) is an ellipse with vertices (________ , _______) and (_______ , _______)
View solution