Problem 2
Question
The graph of each equation is a parabola. Determine whether the parabola opens upward, downward, to the left, or to the right. Do not graph. $$y=-x^{2}+16$$
Step-by-Step Solution
Verified Answer
The parabola opens downward.
1Step 1: Identify the standard form of the parabola equation
The given equation is \( y = -x^2 + 16 \). This is the standard form of a parabola equation with respect to the variable \( y \), which is typically written as \( y = ax^2 + bx + c \). In this form, \( a = -1 \), \( b = 0 \), and \( c = 16 \).
2Step 2: Determine the direction of opening based on coefficient 'a'
The sign of the coefficient \( a \) in the equation \( y = ax^2 + bx + c \) determines the direction the parabola opens. If \( a > 0 \), the parabola opens upward. If \( a < 0 \), the parabola opens downward. Here, \( a = -1 \), which is less than zero.
3Step 3: Conclude the direction of the parabola's opening
Since \( a = -1 \) is negative, the parabola described by the equation \( y = -x^2 + 16 \) opens downward.
Key Concepts
Standard FormDirection of OpeningCoefficient Analysis
Standard Form
When working with parabolas, the standard form of their equation is crucial. This standard form usually follows the equation \( y = ax^2 + bx + c \), where:
Although different formulations exist, such as the vertex form \( y = a(x-h)^2 + k \), starting with the standard form gives a solid grounding in the basic properties of the parabola.
- \( a \), \( b \), and \( c \) are coefficients.
- \( y \) is typically dependent on the variable \( x \).
Although different formulations exist, such as the vertex form \( y = a(x-h)^2 + k \), starting with the standard form gives a solid grounding in the basic properties of the parabola.
Direction of Opening
Understanding the direction in which a parabola opens is fundamental to learning about its graphical representation. This direction is primarily dictated by the coefficient \( a \) in the equation's standard form. Here's what you should remember:
- If \( a > 0 \), the parabola opens upwards. Think of it as a smile.
- If \( a < 0 \), the parabola opens downwards. It's this scenario that resembles a frown.
Coefficient Analysis
The analysis of coefficients in the standard form of a parabola lets us uncover essential features of the graph. Let's break down these roles:
- Coefficient \( a \): Determines the direction of the parabola's opening and affects its width. A larger absolute value of \( a \) means a steeper graph, whereas a smaller absolute value indicates a broader parabola.
- Coefficient \( b \): Affects the symmetry and position of the parabola along the x-axis. While it is zero in our example, a nonzero \( b \) means the parabola doesn't necessarily peak or dip directly at the y-axis.
- Coefficient \( c \): Represents the y-intercept, the point where the graph crosses the y-axis. In \( y = -x^2 + 16 \), the parabola crosses the y-axis at \( y = 16 \).
Other exercises in this chapter
Problem 2
Solve each nonlinear system of equations for real solutions. $$ \left\\{\begin{aligned} x^{2}+y^{2} &=25 \\ 3 x+4 y &=0 \end{aligned}\right. $$
View solution Problem 2
Graph each inequality. See Examples 1 and \(2 .\) $$ y
View solution Problem 2
Identify the graph of each equation as an ellipse or a hyperbola. Do not graph. \(\frac{x^{2}}{16}-\frac{y^{2}}{4}=1\)
View solution Problem 3
Solve each nonlinear system of equations for real solutions. $$ \left\\{\begin{aligned} x^{2}+4 y^{2} &=10 \\ y &=x \end{aligned}\right. $$
View solution