Problem 2
Question
The cross product of two vectors a and \(\mathbf{b}\) is ___________________ to \(\mathbf{a}\) and to \(\mathbf{b}\). Thus if both vectors a and b lie in a plane, the vector \(\mathbf{a} \times \mathbf{b}\) is _________________ to the plane.
Step-by-Step Solution
Verified Answer
perpendicular; perpendicular
1Step 1: Understanding the Cross Product
The cross product of two vectors, \( \mathbf{a} \times \mathbf{b} \), results in a vector that is perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \). This property can be leveraged to determine the orientation of the resultant vector compared to the original vectors.
2Step 2: Analyzing the Plane
When vectors \( \mathbf{a} \) and \( \mathbf{b} \) lie within the same plane, the plane itself is defined by all linear combinations of these two vectors. Hence, the cross product provides information about direction relative to this plane.
3Step 3: Identifying the Resultant Direction
Since the cross product \( \mathbf{a} \times \mathbf{b} \) is orthogonal to both \( \mathbf{a} \) and \( \mathbf{b} \), it is by definition also orthogonal to any plane formed by these vectors. Thus, the resultant vector \( \mathbf{a} \times \mathbf{b} \) is perpendicular to the plane that contains \( \mathbf{a} \) and \( \mathbf{b} \).
Key Concepts
Perpendicular VectorsPlane GeometryResultant Vector Direction
Perpendicular Vectors
When we talk about perpendicular vectors in the context of the vector cross product, we are referring to a special relationship between two vectors and their resultant vector. The cross product of two vectors \( \mathbf{a} \) and \( \mathbf{b} \), symbolized as \( \mathbf{a} \times \mathbf{b} \), leads to a third vector that has a unique property: it is perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \).
- The perpendicular nature means that the angle between the resultant vector and both initial vectors is 90 degrees, often described using the term 'orthogonal'.
- This orthogonal vector indicates the direction that is not aligned with either of the two vectors being multiplied, creating a useful tool for defining spatial relationships in three dimensions.
Plane Geometry
In plane geometry, vectors play a pivotal role in describing directions and boundaries within a plane. When two vectors, \( \mathbf{a} \) and \( \mathbf{b} \), lie within the same plane, they essentially define the plane's orientation and span.
- Any vector that resides in the same plane can be expressed as a linear combination of \( \mathbf{a} \) and \( \mathbf{b} \).
- This means that by adjusting the coefficients of \( \mathbf{a} \) and \( \mathbf{b} \), you can reach any point within that planar space.
- The defined plane serves to help visualize how these vectors interact and where the resulting vector from their cross product will sit relative to the original plane.
Resultant Vector Direction
The resultant vector direction is a defining characteristic of the vector cross product. When you perform a cross product on two vectors, such as \( \mathbf{a} \times \mathbf{b} \), the resulting vector does not lie in the same plane as \( \mathbf{a} \) and \( \mathbf{b} \). Here's how it works:
- The resultant vector is orthogonal to the plane established by \( \mathbf{a} \) and \( \mathbf{b} \), which means it points "out of the plane."
- To determine the direction of this vector, the right-hand rule is often used. To apply it, point your fingers in the direction of \( \mathbf{a} \) and curl them towards \( \mathbf{b} \); your thumb will then indicate the direction of \( \mathbf{a} \times \mathbf{b} \).
- This directional property is exceedingly practical in physics and engineering for indicating torque, rotational forces, or any vector quantities that require a distinct perpendicular orientation relative to a defined set of initial vectors.
Other exercises in this chapter
Problem 1
The cross product of the vectors \(\mathbf{a}=\left\langle a_{1}, a_{2}, a_{3}\right\rangle\) and \(\mathbf{b}=\left\langle b_{1}, b_{2}, b_{3}\right\rangle\) i
View solution Problem 2
The plane containing the point \(P\left(x_{0}, y_{0}, z_{0}\right)\) and having the normal vector \(\mathbf{n}=\langle a, b, c\rangle\) is described algebraical
View solution Problem 2
The angle \(\theta\) between the vectors \(\mathbf{u}\) and \(\mathbf{v}\) satisfies \(\cos \theta=\) So if \(\mathbf{u}\) and \(\mathbf{v}\) are perpendicular,
View solution Problem 2
Let \(a=\left\langle a_{1}, a_{2}\right\rangle\) and \(\mathbf{b}=\left\langle b_{1}, b_{2}\right\rangle\) be nonzero vectors in the plane, and let \(\theta\) b
View solution