Problem 2
Question
The complex numbers \(\sin x+i \cos 2 x\) and \(\cos x-\) \(i \sin 2 x\) are conjugate to each other, for (A) \(x=n \pi\) (B) \(x=0\) (C) \(x=\left(n+\frac{1}{2}\right) \pi\) (D) no value of \(x\)
Step-by-Step Solution
Verified Answer
Correct answer: (D) no value of \(x\).
1Step 1: Understand Conjugate Complex Numbers
For two complex numbers to be conjugates, the real part of one should equal the real part of the other, and the imaginary part should be the negative of the imaginary part of the other. Here, this means \[\sin x = \cos x \quad \text{and} \quad \cos 2x = -\sin 2x.\]
2Step 2: Analyze the Real Parts
From the equality \(\sin x = \cos x\), this holds when:\[\tan x = 1.\] That happens when \[x = \frac{\pi}{4} + n\pi,\ n \in \mathbb{Z}.\]
3Step 3: Analyze the Imaginary Parts
For \(-\cos 2x = \sin 2x\), we find:\[\tan(2x) = -1.\] This occurs when:\[2x = \frac{3\pi}{4} + m\pi \quad\Rightarrow\quad x = \frac{3\pi}{8} + \frac{m\pi}{2},\ m \in \mathbb{Z}.\]
4Step 4: Find Common Solutions
To find values of \(x\) that satisfy both conditions, equate:\[\frac{\pi}{4} + n\pi = \frac{3\pi}{8} + \frac{m\pi}{2}\]Solving the equation will determine if there is a solution that fits both equations.
5Step 5: Evaluate Possibilities
By solving the equation:\[2n\pi + \frac{1}{2} = m\pi + \frac{3}{8}\]No simplification resolves to natural numbers simultaneously, so there is no common solution under these transformations.
6Step 6: Conclusion
There is no single value for \(x\) that satisfies both conditions in natural arithmetic solutions, recognizing the relationship constraints without a simple overlap in values.
Key Concepts
Conjugate Complex NumbersTrigonometric EquationsImaginary and Real Parts Analysis
Conjugate Complex Numbers
In the world of complex numbers, conjugates are fascinating pairings. To understand conjugate complex numbers, imagine two numbers: if one is represented as \(a + bi\), its conjugate will be \(a - bi\). The rule for conjugates is straightforward: the real parts must be identical, while the imaginary parts are opposites. This pattern helps simplify many mathematical equations and operations.
Understanding these principles lays a foundation in complex numbers, making it easier to grasp more advanced concepts in mathematics.
- Real parts are equal.
- Imaginary parts are negatives of each other.
Understanding these principles lays a foundation in complex numbers, making it easier to grasp more advanced concepts in mathematics.
Trigonometric Equations
Trigonometric equations can seem intimidating at first, but they are just equations that include trigonometric functions like sine, cosine, and tangent. In our context, solving trigonometric equations involves determining conditions where two trigonometric expressions are equal or opposite.
These trigonometric equations are crucial for finding common solutions where both conditions are met.
- \(\sin x = \cos x\) highlights where the trigonometric identity \(\tan x = 1\) holds true.
- \(\cos 2x = -\sin 2x\) shows where \(\tan(2x) = -1\) is satisfied.
These trigonometric equations are crucial for finding common solutions where both conditions are met.
Imaginary and Real Parts Analysis
Analyzing imaginary and real parts separately is a valuable technique when dealing with complex equations. For a complex number, both components hold essential information.
Understanding this division proves useful not only in exercises involving trigonometric identities but also in broader applications such as signal processing and quantum mechanics.
- Real part analysis involves equating function outputs, like \(\sin x = \cos x\).
- Imaginary part analysis focuses on negating outputs, such as \(\cos 2x = -\sin 2x\).
Understanding this division proves useful not only in exercises involving trigonometric identities but also in broader applications such as signal processing and quantum mechanics.
Other exercises in this chapter
Problem 3
If \(z_{1}\) and \(z_{2}\) are two non-zero complex numbers such that \(\left|z_{1}+z_{2}\right|=\left|z_{1}\right|+\left|z_{2}\right|\), then \(\arg z_{1}-\arg
View solution Problem 4
The number of solutions of the equation \(z^{2}+|z|^{2}=0\), where \(z \in C\) is (A) one (B) two (C) three (D) infinitely many
View solution Problem 5
The number of solutions of the equation \(z^{2}+|z|^{2}=0\), where \(z \in C\) is (A) one (B) two (C) three (D) infinitely many
View solution