Problem 2
Question
The center of a group \(G\) is the normal subgroup \(C\) of \(G\) consisting of all those elements of \(G\) which commute with every element of \(G\). Suppose the quotient group \(G / C\) is a cyclic group; say it is generated by the element \(C a\) of \(G / C\). Prove each of the following: For every \(x \in G\), there is some integer \(m\) such that \(x=c a^{m}\), where \(c \in C\).
Step-by-Step Solution
Verified Answer
For any \( x \in G \), \( x = c a^m \) for some integer \( m \) and \( c \in C \), as \( G/C \) is cyclic.
1Step 1: Understanding the Structure of the Quotient
We are given that the quotient group \( G / C \) is cyclic and generated by the element \( Ca \). This means every element in \( G/C \) can be expressed as \( (Ca)^n \) for some integer \( n \). Thus, for any \( x \in G \), its corresponding element in \( G/C \) is \( Cx = (Ca)^m \) for some integer \( m \).
2Step 2: Expressing \( x \) in Terms of \( a \) and an Element of \( C \)
Given \( Cx = (Ca)^m \), which we know is \( Ca^m \), by definition of the quotient group, this means that \( x \) and \( a^m \) must differ by some element of \( C \). We can express \( x = c a^m \) where \( c \) is in \( C \), because \( Cx = Ca^m \) implies \( x = c a^m \) for some \( c \in C \).
3Step 3: Conclusion of the Problem
For every element \( x \in G \), there exists an integer \( m \) such that \( x = c a^{m} \), where \( c \) is an element of \( C \), the center of \( G \). This holds because of our ability to express each element of the quotient group \( G/C \) in terms of a generator raised to an integer power, translated back to \( G \) with an element from the center.
Key Concepts
Center of a GroupCyclic GroupNormal SubgroupGroup Theory
Center of a Group
The center of a group, often denoted as \( Z(G) \) or simply \( C \), is a fundamental concept in group theory. To understand it, let's consider any group \( G \). The center of this group is defined as the set of all elements in \( G \) that commute with every other element in \( G \).
This means for any element \( g \) in \( G \), if \( z \) is in the center, then \( zg = gz \).
This means for any element \( g \) in \( G \), if \( z \) is in the center, then \( zg = gz \).
- The center is a subset of the group.
- It's a normal subgroup, which means it's invariant under conjugation by any element of \( G \).
- The center captures the idea of elements having a "neutral" position in the group.
Cyclic Group
A cyclic group is a type of group that can be generated by a single element, which means that every element in the group can be expressed as a power of this generator. Cyclic groups are very important in group theory because they represent the simplest non-trivial groups.
Imagine you have a group \( G \), and an element \( g \) in \( G \) such that every element of \( G \) can be expressed as \( g^n \) for some integer \( n \). In this case, \( G \) is cyclic and \( g \) is the generator.
Imagine you have a group \( G \), and an element \( g \) in \( G \) such that every element of \( G \) can be expressed as \( g^n \) for some integer \( n \). In this case, \( G \) is cyclic and \( g \) is the generator.
- A cyclic group can be finite or infinite.
- If the group is finite, the generator's powers cycle back to the identity element after it reaches the group order.
- Cyclic groups are always abelian, meaning the order of multiplication does not matter.
Normal Subgroup
In group theory, a normal subgroup is a subgroup that is invariant under conjugation by any element of the group. This means if you take an element \( g \) from the parent group \( G \) and a normal subgroup \( N \), then the element formed by conjugating \( n \) as \( gng^{-1} \) will still lie within \( N \).
Normal subgroups are pivotal because they allow the concept of quotient groups.
Normal subgroups are pivotal because they allow the concept of quotient groups.
- They offer a way to "divide" groups and analyze their structure through simpler components.
- Any subgroup that's center to the group is always normal because its elements commute with all others.
- They are used to derive other groups and analyze the structure of symmetry and transformations.
Group Theory
Group theory is a branch of mathematics that studies the algebraic structures known as groups. It's an essential area of abstract algebra and is applied in various fields such as physics, chemistry, and computer science.
A group is essentially a set equipped with a single operation that satisfies four fundamental properties: closure, associativity, identity, and inversibility.
A group is essentially a set equipped with a single operation that satisfies four fundamental properties: closure, associativity, identity, and inversibility.
- Closure: Combining two elements from the group results in another element from the group.
- Associativity: The order of applying the operation does not affect the result, i.e., \((a \cdot b) \cdot c = a \cdot (b \cdot c) \).
- Identity: There's an element in the group which, when combined with any element of the group, leaves it unchanged.
- Inversibility: For every element in the group, an inverse exists such that when they are combined, the identity element is the result.
Other exercises in this chapter
Problem 1
In each of the following, \(H\) is a subset of \(\mathbb{R} \times \mathbb{R}\) (a) Prove that \(H\) is a normal subgroup of \(\mathbb{R} \times \mathbb{R}\). (
View solution Problem 1
In each of the following, \(G\) is a group and \(H\) is a normal subgroup of \(G\). List the elements of \(G / H\) and then write the table of \(G / H\). Exampl
View solution Problem 2
Let \(G\) be a group, and \(H\) a normal subgroup of \(G\). Prove the following: If \((G: H)=m\), the order of every element of \(G / H\) is a divisor of \(m\).
View solution Problem 2
There are some group properties which, if they are true in \(G / H\) and in \(H\), must be true in \(G .\) Here is a sampling. Let \(G\) be a group, and \(H\) a
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