Problem 2
Question
Suppose \(F\) is an antiderivative of \(f\) and \(A\) is an area function of \(f\) What is the relationship between \(F\) and \(A ?\)
Step-by-Step Solution
Verified Answer
Answer: The relationship between an antiderivative function, F, and an area function, A, of a given function f is that the antiderivative function F is equal to the derivative of the area function A with respect to x. Mathematically, this can be represented as:
$$F(x) = A'(x)$$
1Step 1: Define the Antiderivative Function (F)
An antiderivative function, F, is a function such that its derivative is equal to the original function f. Mathematically, this can be represented as:
$$F'(x) = f(x)$$
2Step 2: Define the Area Function (A)
An area function, A, is a function that represents the area under the curve of f from a fixed point a (lower bound) to a variable point x (upper bound) on the x-axis. Mathematically, it can be represented as an integral:
$$A(x) = \int_{a}^{x} f(t) dt$$
3Step 3: Use the Fundamental Theorem of Calculus to Connect F and A
The Fundamental Theorem of Calculus states that:
$$\frac{d}{dx}\left(\int_{a}^{x} f(t) dt\right) = f(x)$$
4Step 4: Derive the Relationship between F and A
Since \(\frac{d}{dx}(A(x)) = f(x)\), according to the Fundamental Theorem of Calculus, and \(F'(x) = f(x)\) by definition, we can then derive the relationship between F and A as follows:
$$\frac{d}{dx}(A(x)) = F'(x)$$
Thus, we can conclude that an antiderivative function F is equal to the derivative of the area function A with respect to x:
$$F(x) = A'(x)$$
Key Concepts
AntiderivativeArea FunctionIntegration
Antiderivative
An antiderivative is a function that reverses differentiation. If you have a function \( f(x) \), an antiderivative \( F(x) \) is one that, when differentiated, gives back \( f(x) \). This means that the derivative of \( F(x) \) is \( f(x) \), represented mathematically by:
- \( F'(x) = f(x) \)
Area Function
The area function, commonly denoted \( A(x) \), is pivotal in calculus as it helps quantify the area under a curve of a function \( f \) over a particular interval. This function is essentially a definite integral, starting from a fixed point \( a \) to a variable endpoint \( x \). It can be expressed as:
- \( A(x) = \int_{a}^{x} f(t) \, dt \)
Integration
Integration is a fundamental concept in calculus, referring to the process of finding an integral. It is often used to find the total accumulation of a quantity, such as area, volume, or other totals from rates of change. There are two main types of integration: definite and indefinite.
Indefinite Integration
This is the process of finding an antiderivative of a function, resulting in a family of functions that include a constant of integration \( C \). It is symbolized as:- \( \int f(x) \, dx = F(x) + C \)
Definite Integration
Used to compute the exact area under a curve between two limits. This involves the area function we spoke about earlier and looks like:- \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \)
Other exercises in this chapter
Problem 2
Why is the Substitution Rule referred to as a change of variables?
View solution Problem 2
If \(f\) is an even function, why is \(\int_{-a}^{a} f(x) d x=2 \int_{0}^{a} f(x) d x ?\)
View solution Problem 2
What is the geometric meaning of a definite integral if the integrand changes sign on the interval of integration?
View solution Problem 3
The composite function \(f(g(x))\) consists of an inner function \(g\) and an outer function \(f\). If an integrand includes \(f(g(x)),\) which function is ofte
View solution