Problem 2
Question
Show that if the particles of a solid are acted on by "body forces" which are distributed over the volume with intensities \(X, Y\), and \(Z\) per unit volume, then the requirement of \(\Sigma \mathbf{F}=0\) leads to $$ \begin{aligned} &\frac{\partial \sigma_{x}}{\partial x}+\frac{\partial \tau_{x y}}{\partial y}+\frac{\partial \tau_{z x}}{\partial z}+X=0 \\ &\frac{\partial \tau_{x y}}{\partial x}+\frac{\partial \sigma_{y}}{\partial y}+\frac{\partial \tau_{y z}}{\partial z}+Y=0 \\ &\frac{\partial \tau_{z x}}{\partial x}+\frac{\partial \tau_{y z}}{\partial y}+\frac{\partial \sigma_{z}}{\partial z}+Z=0 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The important principle to apply in this problem is the equilibrium of forces, which gives rise to three equations when examined in all three spatial directions - x, y, and z. The key steps involve understanding the components present, setting up and simplifying the equations for each direction - all of which comply with the equilibrium conditions and the principle of superposition.
1Step 1: Understand the Context and the unknowns
Start by understanding that the body forces are represented by \(X, Y\), and \(Z\). And \(\sigma_{x}\), \(\sigma_{y}\), \(\sigma_{z}\), \(\tau_{xy}\), \(\tau_{zx}\), and \(\tau_{yz}\) are stress components on the x, y, and z axes. The task is to show that the equilibrium of forces \(\Sigma \mathbf{F}=0\) leads to the given equations.
2Step 2: Obtain the force on the differential element in the x-direction
Obtain the forces in the x-direction considering the volume forces and the surface forces. The force on a surface is given by the stress on the surface multiplied by the surface area, and the direction is given by the normals of the stresses. Also, additional force contributions come from the product of the volume forces and the small volume of the differential element, \(\delta V\). Thus we can write the equilibrium of forces in the x-direction as: \(\frac{\partial \sigma_{x}}{\partial x} \delta V + \frac{\partial \tau_{x y}}{\partial y} \delta V + \frac{\partial \tau_{z x}}{\partial z} \delta V + X \, \delta V = 0\).
3Step 3: Simplify the Equation for the x-direction
Simplify the equation by dividing all terms by the differential volume, \(\delta V\), to get: \(\frac{\partial \sigma_{x}}{\partial x} + \frac{\partial \tau_{x y}}{\partial y} + \frac{\partial \tau_{z x}}{\partial z} + X = 0\). This is the first required equation.
4Step 4: Repeat the process for the y and z directions
Obtain the required equations for the y and z directions following the steps from 2 to 3. This should lead to: \(\frac{\partial \tau_{x y}}{\partial x}+\frac{\partial \sigma_{y}}{\partial y}+\frac{\partial \tau_{y z}}{\partial z}+Y=0\) for the y-direction and \(\frac{\partial \tau_{z x}}{\partial x}+\frac{\partial \tau_{y z}}{\partial y}+\frac{\partial \sigma_{z}}{\partial z}+Z=0\) for the z-direction.
Key Concepts
Body ForcesStress ComponentsDifferential ElementEquations of Equilibrium
Body Forces
Body forces are forces that act throughout the volume of a material, rather than just on its surface. Examples of body forces include gravitational forces, electromagnetic forces, and inertial forces resulting from acceleration. These forces are distributed over the volume of a solid and are represented by the intensity values, often denoted as \(X\), \(Y\), and \(Z\), corresponding to the x, y, and z directions respectively. These intensities indicate how much force is applied per unit volume in each direction. This concept is crucial when analyzing the equilibrium of forces acting on solid particles because body forces contribute to the total force impacting the volume. In the context of equilibrium of forces, body forces must be balanced by surface forces to ensure that the sum of all forces \(\Sigma \mathbf{F}=0\). This balancing results in the equations of equilibrium, which incorporate these body forces.
Stress Components
Stress components are the internal forces within a material that arise as a reaction to external loads. They vary with the position within the body and determine how the material deforms. In a three-dimensional state, stress at a point can be described using a stress tensor, with elements such as normal stresses and shear stresses.
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- \(\sigma_{x}\), \(\sigma_{y}\), and \(\sigma_{z}\) represent normal stresses in the x, y, and z directions. These are perpendicular to the face of the differential element.
- \(\tau_{xy}\), \(\tau_{zx}\), and \(\tau_{yz}\) are shear stresses, occurring parallel to the surface.
Differential Element
A differential element is an infinitesimally small portion of a material, used to analyze stress and strain distributions at a given point. In three-dimensional analysis, a differential element is typically a small cube where face areas and volume are considered infinitesimally small. This approach simplifies complex stress distributions by focusing on elemental interactions. Each face of the differential element can experience normal and shear stresses, and these contribute to the force balance in equilibrium equations.
The advantage of using a differential element lies in its ability to simplify the mathematical representation of stress and deformation in a solid. By considering such elements, we can formulate detailed equilibrium equations that accurately describe how forces are distributed and balanced throughout the entire material or structure. Analytical methods involving differential elements are powerful tools in continuum mechanics and are foundational in physical theory and engineering practices.
The advantage of using a differential element lies in its ability to simplify the mathematical representation of stress and deformation in a solid. By considering such elements, we can formulate detailed equilibrium equations that accurately describe how forces are distributed and balanced throughout the entire material or structure. Analytical methods involving differential elements are powerful tools in continuum mechanics and are foundational in physical theory and engineering practices.
Equations of Equilibrium
The equations of equilibrium are fundamental mathematical representations in mechanics that ensure the internal and external forces within a solid are balanced. These equations originate from Newton's First Law and are conditional on the requirement that the net force and moment acting on a body must be zero, indicating a state of rest or uniform motion.
For a differential element subjected to body forces \(X, Y, Z\) and stress components \(\sigma_{x}, \sigma_{y}, \sigma_{z}\), and \(\tau_{xy}, \tau_{zx}, \tau_{yz}\), the equilibrium is expressed as:
For a differential element subjected to body forces \(X, Y, Z\) and stress components \(\sigma_{x}, \sigma_{y}, \sigma_{z}\), and \(\tau_{xy}, \tau_{zx}, \tau_{yz}\), the equilibrium is expressed as:
- \(\frac{\partial \sigma_{x}}{\partial x} + \frac{\partial \tau_{xy}}{\partial y} + \frac{\partial \tau_{zx}}{\partial z} + X = 0\)
- \(\frac{\partial \tau_{xy}}{\partial x} + \frac{\partial \sigma_{y}}{\partial y} + \frac{\partial \tau_{yz}}{\partial z} + Y = 0\)
- \(\frac{\partial \tau_{zx}}{\partial x} + \frac{\partial \tau_{yz}}{\partial y} + \frac{\partial \sigma_{z}}{\partial z} + Z = 0\)
Other exercises in this chapter
Problem 3
Show that if a state of plane stress is to be described in terms of polar coordinates, the requirement that \(\Sigma F=0\) leads to the following two cquations:
View solution Problem 4
Show that if a general state of stress is to be described in cylindrical coordinates, the requirement that \(\Sigma \mathbf{F}=0\) leads to the following three
View solution Problem 7
Find the principal stresses and the oricntation of the principal axes of stress for the following cases of plane stress. $$ \begin{array}{llll} \text { (a) } \s
View solution