Problem 2
Question
Rita said that when \(a, b,\) and \(c\) are real numbers, the roots of \(a x^{2}+b x+c=0\) are real numbers only when \(b^{2} \geq 4 a c .\) Do you agree with Rita? Explain why or why not.
Step-by-Step Solution
Verified Answer
Yes, Rita is correct; real roots occur when \(b^2 \geq 4ac\).
1Step 1: Understanding the Discriminant
The roots of a quadratic equation of the form \(a x^2 + bx + c = 0\) are determined using the discriminant formula, \(D = b^2 - 4ac\). This discriminant tells us the nature of the roots.
2Step 2: Condition for Real Roots
For the roots of the quadratic equation to be real, the discriminant \(D\) must be greater than or equal to zero. That is, \(b^2 - 4ac \geq 0\). This ensures that the square root of the discriminant is a real number, allowing us to find two real roots using the quadratic formula.
3Step 3: Interpreting Rita's Statement
Rita stated that the roots are real when \(b^2 \geq 4ac\). This condition is exactly what we found necessary for the discriminant to be non-negative, ensuring the roots are real. Thus, Rita's statement is correct.
Key Concepts
DiscriminantReal RootsQuadratic Formula
Discriminant
The discriminant is a special value found in quadratic equations that helps determine the nature of the roots of the equation. For a quadratic equation in the form of \(ax^2 + bx + c = 0\), the discriminant \(D\) is calculated using the formula \(D = b^2 - 4ac\).
The discriminant provides important information:
The discriminant provides important information:
- If \(D > 0\), the equation has two distinct real roots.
- If \(D = 0\), the equation has exactly one real root, also known as a repeated or double root.
- If \(D < 0\), the equation does not have real roots; instead, the roots are complex or imaginary.
Real Roots
Real roots in a quadratic equation occur when the solutions to the equation can be plotted on the real number line and are not imaginary. The discriminant determines if and how many real roots an equation will have. For the quadratic equation \(ax^2 + bx + c = 0\), real roots are possible when the discriminant \(D = b^2 - 4ac\) is equal to or greater than zero.
- When \(D > 0\): The quadratic equation will cut the x-axis at two distinct points, meaning two separate real roots exist.- When \(D = 0\): The x-axis is touched at a single point indicating a repeated real root, which is also the vertex of the parabola represented by the equation.
Real roots are important as they represent practical solutions in real-world problems where imaginary numbers are not applicable.
- When \(D > 0\): The quadratic equation will cut the x-axis at two distinct points, meaning two separate real roots exist.- When \(D = 0\): The x-axis is touched at a single point indicating a repeated real root, which is also the vertex of the parabola represented by the equation.
Real roots are important as they represent practical solutions in real-world problems where imaginary numbers are not applicable.
Quadratic Formula
The quadratic formula is a powerful tool used to find the roots of a quadratic equation. For an equation \(ax^2 + bx + c = 0\), the roots are given by the formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula incorporates the discriminant \(b^2 - 4ac\), giving insight into both the nature and the value of the roots based on whether the discriminant is positive, zero, or negative.
When applying the quadratic formula:
When applying the quadratic formula:
- If \(D > 0\), the square root in the formula evaluates to a real number, allowing for the determination of two distinct real roots.
- If \(D = 0\), the expression simplifies to give one real root.
- If \(D < 0\), the square root yields an imaginary number, leading to complex roots.
Other exercises in this chapter
Problem 2
Joshua said that the product of a complex number and its conjugate is always a real number. Do you agree with Joshua? Explain why or why not.
View solution Problem 2
Ethan said that the square of any pure imaginary number is a negative real number. Do you agree with Ethan? Justify your answer.
View solution Problem 2
Phillip said that the equation \(0=x^{2}-6 x+1\) can be solved by adding 8 to both sides of the equation. Do you agree with Phillip? Explain why or why not.
View solution Problem 3
In \(3-14,\) use the quadratic formula to find the imaginary roots of each equation. $$ x^{2}-4 x+8=0 $$
View solution