Problem 2
Question
Prove that if \(\alpha / 2 \pi\) is rational, then every point of \(\mathbb{T}\) is periodic for \(T_{\alpha}\), i.e., for each \(x \in \mathbb{T}\) there is an \(n>0\) such that \(T_{\alpha}^{n}(x)=x\)
Step-by-Step Solution
Verified Answer
If \(\alpha / 2 \pi\) is rational, every point \(x \in \mathbb{T}\) is periodic for \(T_\alpha\).
1Step 1: Define the transformation
The transformation \(T_{\alpha}\) on the circle \(\mathbb{T}\) is defined by \(T_{\alpha}(x) = x + \alpha \mod 1\). We apply this definition to each point \(x\) on the circle.
2Step 2: Express \(\alpha\) as a rational multiple of \(2\pi\)
Since \(\alpha / 2\pi\) is rational, we express it as \(\frac{m}{n}\) for some integers \(m\) and \(n\) with \(n > 0\). This implies \(\alpha = \frac{2\pi m}{n}\).
3Step 3: Calculate \(T_{\alpha}^{n}(x)\)
Apply the transformation \(n\) times: \(T_{\alpha}^{n}(x) = x + n\alpha \mod 1\). Substitute \(\alpha = \frac{2\pi m}{n}\) into this equation to get \(T_{\alpha}^{n}(x) = x + n\left(\frac{2\pi m}{n}\right) \mod 1 = x + 2\pi m \mod 1\).
4Step 4: Simplify the expression
Since adding \(2\pi m\) (for any integer \(m\)) is equivalent to making full revolutions around the circle, \(x + 2\pi m \equiv x \mod 1\). Therefore, \(T_{\alpha}^{n}(x) = x\), showing that after \(n\) applications of the transformation, the point returns to \(x\).
5Step 5: Conclusion
Since for each \(x \in \mathbb{T}\) such an \(n\) exists, every point of \(\mathbb{T}\) is periodic for \(T_{\alpha}\). This completes the proof that if \(\alpha / 2 \pi\) is rational, \(T_{\alpha}\) leaves all points \(x\) periodic.
Key Concepts
Periodic PointsRational NumbersCircle TransformationsModular Arithmetic
Periodic Points
Periodic points in circle transformations refer to the points that return to their initial position after a certain number of transformations. This concept is quite fascinating and plays a pivotal role in understanding how transformations can behave over a circular space like the unit circle \( \mathbb{T} \).
A point \( x \) on the circle \( \mathbb{T} \) is said to be periodic under a transformation \( T_{\alpha} \) if there exists some positive integer \( n \) such that \( T_{\alpha}^{n}(x) = x \).
A point \( x \) on the circle \( \mathbb{T} \) is said to be periodic under a transformation \( T_{\alpha} \) if there exists some positive integer \( n \) such that \( T_{\alpha}^{n}(x) = x \).
- This means after \( n \) transformations the point returns to its original position.
- In circular transformations like \( T_{\alpha} \), this concept helps illustrate the repetitive nature of angles and rotations on a circle.
Rational Numbers
Rational numbers are the numbers that can be expressed as a quotient or fraction \( \frac{m}{n} \), where both \( m \) and \( n \) are integers, and \( n \) is not zero. They form a crucial part of the transformation discussed in this exercise where the angle \( \alpha \) is related to \( 2\pi \) through a rational number.
The relationship \( \frac{\alpha}{2\pi} = \frac{m}{n} \) tells us that \( \alpha \) is some fraction of a full circle. Rational numbers bring about cyclical behavior in the context of this problem because:
The relationship \( \frac{\alpha}{2\pi} = \frac{m}{n} \) tells us that \( \alpha \) is some fraction of a full circle. Rational numbers bring about cyclical behavior in the context of this problem because:
- They enable the repetition of a particular transformation.
- They provide a predictable pattern due to their nature of expressing divisions or segments of a whole.
Circle Transformations
Circle transformations involve applying a function to points on a circle. For a point \( x \) on the unit circle \( \mathbb{T} \), the transformation \( T_{\alpha} \) is defined as \( T_{\alpha}(x) = x + \alpha \mod 1 \). This means that we take the point \( x \), add an angle \( \alpha \), and find the result within the range \([0, 1)\) by taking the modulo.
The aim of these transformations is to explore how points move around the circle and under which conditions they cycle back to the start:
The aim of these transformations is to explore how points move around the circle and under which conditions they cycle back to the start:
- The unit circle \( \mathbb{T} \) represents all real numbers from 0 to 1 in a loop.
- When \( \alpha / 2\pi \) is rational, the transformation results in every point being periodic.
Modular Arithmetic
Modular arithmetic is a system of arithmetic for integers, where numbers wrap around upon reaching a certain value—the modulus. It's a fascinating branch of number theory, often referred to as "clock arithmetic," and plays a crucial role in the exercise's solution.
When we apply transformations on a circle, like \( T_{\alpha} \) on \( \mathbb{T} \), modular arithmetic is used to ensure that the value remains within the circle's bounds.
When we apply transformations on a circle, like \( T_{\alpha} \) on \( \mathbb{T} \), modular arithmetic is used to ensure that the value remains within the circle's bounds.
- For example, the expression \( T_{\alpha}(x) = x + \alpha \mod 1 \) ensures that after adding \( \alpha \) we find the remainder when divided by 1, keeping the rotation within \([0, 1)\).
- This concept helps maintain periodicity and predictability, as points will eventually repeat their positions.
Other exercises in this chapter
Problem 1
Suppose \(\alpha / 2 \pi\) is irrational. Prove that every point of \(\mathbb{T}\) has a forward orbit for the transformation \(T_{\alpha}\) which is dense in \
View solution Problem 3
Prove that if \(m \in \mathbb{N}\) and \(m>1\), then the function \(M: \mathbb{T} \rightarrow\) \(\mathbb{T}\) given by \(M\left(e^{i x}\right)=e^{i m x}\) pres
View solution Problem 4
Define \(T:[0,1] \rightarrow[0,1]\) by $$ T(x)= \begin{cases}2 x, & \text { if } x \in\left[0, \frac{1}{2}\right] \\\ 2-2 x, & \text { if } x \in\left(\frac{1}{
View solution Problem 5
Suppose \(T:[0,1] \rightarrow[0,1]\) preserves Lebesgue measure. Prove that for almost all \(x \in[0,1]\) there is a sequence of positive integers \(\left\\{n_{
View solution