Problem 2
Question
Name the conic (horizontal ellipse, vertical hyperbola, and so on) corresponding to the given equation. $$ \frac{x^{2}}{9}-\frac{y^{2}}{4}=1 $$
Step-by-Step Solution
Verified Answer
The conic is a horizontal hyperbola.
1Step 1: Identify the Standard Form
The given equation is \( \frac{x^{2}}{9} - \frac{y^{2}}{4} = 1 \). This is in the standard form \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \), which represents a hyperbola.
2Step 2: Determine the Orientation
In the standard form of a hyperbola \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \), if the \( x^{2} \) term is positive and \( y^{2} \) term is negative, it indicates a horizontal hyperbola.
Key Concepts
HyperbolasStandard Form of ConicsEquation of a Hyperbola
Hyperbolas
A hyperbola is a fascinating type of conic section formed by the intersection of a plane with a double-napped cone. Unlike other conics, such as ellipses and parabolas, hyperbolas consist of two separate curves known as branches. These branches mirror each other and extend infinitely in opposite directions.
Hyperbolas have distinctive properties:
Hyperbolas have distinctive properties:
- Two foci (plural of focus) and two directrices.
- Two asymptotes that intersect at a point known as the center of the hyperbola. These asymptotes act as guidelines for the branches, becoming closer to them as the branches extend.
- The line segment passing through the foci is called the transverse axis, which is an essential feature. It's the axis where the branches open.
- Additionally, there's a conjugate axis that is perpendicular to the transverse axis.
Standard Form of Conics
The standard form of a conic is an equation used to express different types of conic sections, such as circles, ellipses, parabolas, and hyperbolas in a simplified manner. When dealing with conics, recognizing their standard forms is crucial for understanding and analyzing them.
For hyperbolas, the standard form is \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] or\[ \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \]The positive term's variable indicates the axis along which the hyperbola is oriented.
For hyperbolas, the standard form is \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] or\[ \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \]The positive term's variable indicates the axis along which the hyperbola is oriented.
- If the term \( \frac{x^2}{a^2} \) is positive, it's a horizontal hyperbola.
- If the term \( \frac{y^2}{b^2} \) is positive, it's a vertical hyperbola.
Equation of a Hyperbola
The equation of a hyperbola is essential for its identification and analysis. As part of the family of conic sections, hyperbolas have distinct forms.
The standard equation: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]is used to represent a hyperbola centered at the origin with the transverse axis along the x-axis.
In this equation, \(a\) and \(b\) denote lengths associated with the hyperbola:
The standard equation: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]is used to represent a hyperbola centered at the origin with the transverse axis along the x-axis.
In this equation, \(a\) and \(b\) denote lengths associated with the hyperbola:
- \(a\) is the distance from the center to each vertex on the transverse axis.
- \(b\) is related to the distance from the center to points on the conjugate axis.
- For a hyperbola centered at the origin, its foci are at points \((\pm c, 0)\) or \((0, \pm c)\), where \(c = \sqrt{a^2 + b^2}\).
- Vertices occur at \((\pm a, 0)\) or \((0, \pm a)\), confirming the direction in which the hyperbola opens.
Other exercises in this chapter
Problem 2
Plot the points whose polar coordinates are \((3,2 \pi)\), \(\left(2, \frac{1}{2} \pi\right),\left(4,-\frac{1}{3} \pi\right),(0,0),(1,54 \pi),\left(3,-\frac{1}{
View solution Problem 2
a parametric representation of a curve is given. $$ x=2 t, y=3 t ;-\infty
View solution Problem 2
Find the coordinates of the focus and the equation of the directrix for each parabola. Make a sketch showing the parabola, its focus, and its directrix. $$ y^{2
View solution Problem 3
Sketch the graph of the given equation and find the area of the region bounded by it. $$ r=2+\cos \theta $$
View solution